location

You can determine if any providers are available with LocationManager, but can it be done with the google play services location api? When nothing is enabled, in fact "access to my location" is off, all the API calls (connect(), requestLocationUpdates()) succeed, but you never get an onLocationChanged(). Seems silly to have to use both LocationManager and the LocationClient. I guess what I need is some way to know that onLocationChanged(0 will never get called. I've combed the docs and also haven't found any way to use LocationClient to detect if location services are enabled. onConnected,

I need to implement location-based service. I don't need fine location, so no GPS is needed. Easiest would be to start listening for locations updates at app start, and leave it ON: mLocationMgr.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 10000, 100, mPendingIntent); Since I don't need much accuracy, I set max frequency of updates, to 10s, and 100m instead of default 0, 0. When we think location, we think battery drain, but I guess this is a shortcut and that only GPS really drains the battery. I think that such a use of network provider wouldn't drain the battery. Any thoughts?

I have this table in sqlite Locations ID Lat ( latitude) Lon ( longitude) Type Name City I have for example 100 records what I need is to get (using my own coordinates) the nearest point in my table. What I did is to get the shortest distance between my current point and each one in the table, and return the shortest one, but I am searching for a better solution Thanks Matthew A possible solution is to use a grid for the whole map your are interested in and pre-assign points to a particular row/column. Then: Calculate the grid location of your new point - add a column to the database for this.

# Load configuration files for the default server block. include /etc/nginx/default.d/*.conf; #根据路由设置，避免出现404 location ^~ /api/ { add_header 'Access-Control-Allow-Origin' '*'; proxy_pass http://service.xxxx.com/; } location / { try_files $uri $uri/ @router;#需要指向下面的@router否则会出现vue的路由在nginx中刷新出现404 index index.html index.htm; } #对应上面的@router，主要原因是路由的路径资源并不是一个真实的路径，所以无法找到具体的文件 #因此需要rewrite到index.html中，然后交给路由在处理请求资源 location @router { rewrite ^.*$ /index.html last; } error_page 404 /404.html; location = /40x.html { } error_page 500 502 503 504 /50x.html; location = /50x.html { } } 来源： https://www

I'm new on Swift Programming, and I'm trying to build an app that I can get the coordinates of the center of the view with MapKit and Swift 2. I already can get the current location, but I need if I move on the map, the location set to the new point which will be the center of the screen. Can you help me with this please?. Regards, You can use the regionDidChangeAnimated delegate method and call mapView.centerCoordinate. It will look like the following: func mapView(mapView: MKMapView, regionDidChangeAnimated animated: Bool) { var center = mapView.centerCoordinate } Also make sure that your

内容涉及：关键字定位，列表去重复，路径组装，文件夹创建，文件拷贝，字符串分割 list.txt的内容为包含关键字的文件路径，如：关键字 ’181‘ org/20190523/1/2019052320196231816923IMG039x030.JPG_n_1_1375_220_1475_320.png org/20190523/7/2019052320196171812302IMG007x030.JPG_p_7_287_191_387_291.png ... ... import os import numpy as np import re from shutil import copyfile def getlist(path,name): listall = [] for n in open(path): location = re.search(name, n) #定位关键字 bingli_Id = n[location.start():location.start()+7] #找到关键字后面7位长度字符 listall.append(bingli_Id) #添加到列表中 return set(listall) #去除重复内容 def mkdir(file1, bingId): #建立文件夹 if not os.path.exists(file1): os.mkdir

Is there any such API where given a location (in terms of latlong), I could find whether the given point is on road/street or not. And if possible also gives me nearest street/road to that location. I found API from [Find nearby Streets] -> http://www.geonames.org/maps/us-reverse-geocoder.html#findNearbyStreets , but it just gives solution for US. Help me if u know of any better solution/algorithm. ( I am particularly interested in India.) Mathias Schwarz You can use the Google Maps Geocoding API which does exactly that: https://developers.google.com/maps/documentation/geocoding/intro Take a

概述：接着上一节 获取Nginx服务器安装文件的路径 nginx服务器安装部署之前的准备工作 Windows平台下nignx服务器的安装部署 Linux平台下Nignx服务器的编译和安装 认识Nginx服务器的配置文件，以及如何进行基本配置 初步学习通过优化Nginx配置，提高Nginx服务器的性能 展示一个Nginx配置的完整实例 2.4、Nginx服务器基础配置指令 找安装配置文件， 安装目录根目录/conf/nginx.conf （这里取消注释部分） worker_processes 1; #全局生效 events { worker_connections 1024; #在Events部分中生效 } http { include mime.types; #以下指令在http部分中生效 default_type application/octet-stream; sendfile on; keepalive_timeout 65; server { listen 80; #以下指令在http的server部分中生效 server_name localhost; location / { #以下指令在 http/server的location中生效 root html; index index.html index.htm; } error_page 500 502 503

I want to develop an application in which, if i open the app, it will show current location of my device. I want to do it without using gps. I have write a code for it. But it will show United States location while opening the map. I want it to show my current location (i.e Pune, India). How do i get my approximate correct location? Here is my code protected void onCreate(Bundle arg0) { // TODO Auto-generated method stub super.onCreate(arg0); setContentView(R.layout.main); LocationManager mlocManager = (LocationManager)getSystemService(Context.LOCATION_SERVICE); LocationListener locListener =

HashRouter包裹下访问根服务：假设为 localhost:3000/ 1 import { HashRouter as Router, Route, Redirect } from 'react-router-dom'; 2 // as的作用为将HashRouter重命名为Router,这样的好处是在反复测试HashRouter和BrowserRouter时,可以免去组件修改 3 4 import Home from './pages/Home/index'; 5 import Hooks from './pages/Hooks/index'; 6 7 export default function App() { 8 return ( 9 <Router> 10 <Route path="/"> 11 <Redirect to="/home" /> 12 </Route> 13 <Route path="/home" component={Home} /> 14 <Route path="/hooks" component={Hooks} /> 15 </Router> 16 ) 17 } 操作一: 浏览器直接输入 localhost:3000/ 结果: 路由自动变为 localhost:3000/#/home ,可正常访问. 操作二: 浏览器直接输入 localhost