local

This question already has an answer here: Dynamically set local variable [duplicate] 7 answers Is it possible to create a local variables with Python code, given only the variable's name (a string), so that subsequent calls to "'xxx' in locals()" will return True? Here's a visual : >>> 'iWantAVariableWithThisName' in locals() False >>> junkVar = 'iWantAVariableWithThisName' >>> (...some magical code...) >>> 'iWantAVariableWithThisName' in locals() True For what purpose I require this trickery is another topic entirely... Thanks for the help. If you really want to do this, you could use exec :

I created a Java application which opens an xml file that looks something like this: <AnimalTree> <animal> <mammal>canine</mammal> <color>blue</color> </animal> <!-- ... --> </AnimalTree> And I can open it using: File fXmlFile = getResources.getXml("res/xml/data.xml"); DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); Document doc = dBuilder.parse(fXmlFile); doc.getDocumentElement().normalize(); NodeList animalNodes = doc.getElementsByTagName("animal"); Then I can simply create a node, push the object into a

I have JavaScript application in OpenLayers 3, and my base layer is created from local tiles. I work only in my computer so I do not know why I have CORS error. var newLayer = new ol.layer.Tile({ source: new ol.source.OSM({ url: 'E:/Maperitive/Tiles/vychod/{z}/{x}/{y}.png' }) }); var schladming = [21.6187, 48.7327]; // longitude first, then latitude // since we are using OSM, we have to transform the coordinates... var schladmingWebMercator = ol.proj.fromLonLat(schladming); var map = new ol.Map({ layers: [ newLayer ], controls: [], target: 'mapid', view: new ol.View({ center:

This is my code #include <iostream> using namespace std; int x = 5; int main() { int x = 1; cout << "The variable x: " << x << endl; } I get as output 1 , but I would like to have 5 , as in accessing the global x variable. Is this possible? You should be using ::x in order to access global variable in local scope. The operator :: is unary scope resolution operator. So your code should be: #include <iostream> using namespace std; int x = 5; int main() { int x = 1; cout << "The variable x: " << ::x << endl; } Note: :: operator has two meanings in C++: Binary scope resolution operator. Unary