linked-list

问题 I've implemented my own version of a singly linked list in Rust as one of the challenges for me to learn it, and I'm satisfied with everything I have there except for the .pop() method. Using 2 while loops is very ugly and inefficient, but I found no other way to overcome the problem of setting the node at the index len() - 2 to None (popping the list), and using the data from the node at the index len() - 1 for the Some(data) return value (returns the element that was popped). GitHub Link

问题 I was trying to create a function in C that deletes every odd positioned node. For example 1,2,3,4 becomes 2,4 . Here is what I tried but it doesn't seem to be working. Im talking about the deletee function. I modified it but the list doesn't seem to be changing. #include <stdio.h> #include <stdlib.h> typedef struct node { int val; struct node *next; } node; typedef struct ll { node *head; } ll; ll *newll() { ll *k = malloc(sizeof(ll)); k->head = NULL; return k; } void insert(ll *l, int vl) {

问题 Is there a built in implementation in java for hash map whose values are linked lists? like, if I put: map.put(1, "A"); map.put(1, "B"); then it automatically add A and B to the linked list. When I retrieve from the map, as: map.get(1) I get back a list containing both of them? 回答1: Java does not have it but you can use MultiMap from Google Guava. A collection similar to a Map, but which may associate multiple values with a single key. If you call put(K, V) twice, with the same key but

问题 Say you have a simple DLL (doubly-linked list) implementation in C like so: struct list { list* prev; list* next; } And you intend to implement elements in a list like this: struct element { int value; struct list link; } With an insert operation like this: void list_insert(struct list* list, struct list* element) { element->prev = list; element->next = list->next; list->next = element; element->next->prev = element; } And, lastly, you use your implementation like this: // Initialize empty

问题 So I've got a "daily dashboard" report in SSRS 2005. It has a parameter, @pDate, which defaults to "=Now". I'd like to use this same report in a linked report to show yesterday's final dashboard (which would then be mailed out via subscription), and override the parameter default with another expression, "=dateadd(d,-1,Now)." But when I change the default parameter, I get a data mismatch error (natch). I'm assuming that's the end of the line and I just need to deploy a copy of the daily

问题 I am looking at how to insert a new node before the first node of a doubly-linked list. I'm getting confused with the auxiliary nodes required for this operation and the sequence of steps in which to perform the operation. I would be grateful for a hint on how to solve this problem i.e. what is wrong with my insertBeforeFirst method. As it stands the method causes a nullPointerException which i find hard to troubleshoot. (note: this is a follow-on to a previous post.) public DLL() { header =

问题 I am trying to solve this algorithmic problem based on linked list data structure. The question is as follows: Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. For example, Given 1->4->3->2->5->2 and x = 3, return 1->2->2->4->3->5. My solution to the problem is: /** * Definition for singly-linked list. * public class ListNode

问题 I'm not very advanced in the sorting part of programming yet, so I was looking for some help with my algorithm. void sortList() { Item_PTR tmpNxt = current->nextItem; Item_PTR tmpPTR = current; int a, tmp; while(tmpNxt != NULL) { a = tmpPTR->value; while(tmpNxt != tmpPTR && tmpNxt->value < a) { tmp = a; tmpPTR->value = tmpNxt->value; tmpNxt->value = tmp; tmpPTR = tmpPTR->nextItem; } tmpPTR = current; tmpNxt = tmpNxt->nextItem; } } The list state before sorting: 9 8 7 6 5 4 3 2 1 after sorting

问题 Visual Studio 2008 C What I can't understand about this linked list is the adding to the tail in the else part of the if statement. When the head and tails is assigned the memory address of the node_temp to both tail and head both point to the same memory location. However, in the else part is the head in fact still pointing to the tail. There is just something I can't explain and don't understand about the else part? I hope some one can explain better for me. static struct convert_temp {

问题 I have following piece of code for reversing the linked list. I am getting confused in while loop and so would certainly appreciate if someone can provide visual explanation of how actually it's working. static void Reverse (struct node** headRef) { struct node* result = NULL; struct node* current = *headref; struct node* next; while(current != NULL) { next = current->next; current->next = result; result = current; current = next; } *headRef = result; } 回答1: OK, here's my attempt to make