linked-list

问题 I have to generate random numbers and put them in a linked list sorted. my code runs fine on my home computer on cygwin, however when I run it on the schools system, i keep getting that the list is empty. Not sure what the issue is. #include<stdio.h> #include<stdlib.h> typedef struct node{ int num; struct node *next; }node_t; node_t* insertNodeSorted(node_t *head, int x); void printList(node_t *head); void deleteList(node_t *head); int main(int argc, char *argv[]) { node_t *dummy; int counter

问题 public void addNode(Car newCarEntry){ ListNode currentNode; ListNode previousNode; ListNode newNode = new ListNode(newCarEntry); if (head == null || newCarEntry.isNewerThan(head.carItem)){ newNode.next = head; head = newNode; }else{ currentNode = head.next; previousNode = head; while(currentNode != null && !newCarEntry.isNewerThan(currentNode.carItem)){ currentNode = currentNode.next; previousNode = currentNode; } newNode.next = currentNode; newNode = previousNode.next; } } 回答1: You have a

问题 Hello I have a problem to returned variable from my pop function. I will be happy if you could help me. The function receives a pointer to the top of the list and should return the answer but I have a problem with a pointer to the list and intger the answer. Function Code - int pop(Node* top) { Node* tmp = top; int ans = tmp->next; top = top->next; delete tmp; return ans; } Node - struct Node { int num; Node* next; } Node* top = new Node; 回答1: The line int ans = tmp->next; appears to be the

问题 I am trying to get a linked list to sort, then be able to display it. The problem with my code is, I can display it before sorting, but after sorting, it won't display, it will crash. I think it has to do with the "top" variable, because through debugging, it doesn't contain anything. How can I call the first element in the linked list and use that to display them all? I am just really confused. Below is only the display and sort functions. //Sort and display all employees void displayAllEmps

问题 I need help with this code. I need to call the quicksort method without any parameters in the main method. But this program has a parameter. How can I make it work and not have any parameter when calling it in the main method? Please help. Employee Class public class Employee { private String firstname; private int idNumber; private String lastname; Employee(String lname,String fname, int id) { lastname = lname; firstname = fname; idNumber = id; } public void setLastName(String lname)

问题 I am implementing a linked list class' copy constructor which will make a deep copy. This is the code that i have: List( const List & rhs ) { Node* rhsFront = rhs.header->next; Node* prev = header; while (rhsFront) { prev->next = new Node(rhsFront->data, nullptr); rhsFront = rhsFront->next; prev = prev->next; } } However, it crashes at this line: prev->next = new Node(rhsFront->data, nullptr); What did I do wrong? 回答1: Node* prev = header; I would guess the header there not to be initialised,

问题 When i display after removing a element from linked list, 0 is displayed in place of removed element. I am having trouble updating the nodes.Can anyone Please explain what is happening? Why 0 is displayed? #include<iostream> #include<stdlib.h> using namespace std; class node { public: int data; node *link; }; class linkedlist { node *head; public: linkedlist() { head=NULL; } int add(int data1) { node *insertnode=new node; insertnode->data=data1; insertnode->link=NULL; node *temp=head; if(temp

问题 So I am trying to create a function in C++ that should add an element at the end of an linked list. This function that adds the elements should be called within the main -method. It should be possible to call it even if there is no element in the list. What I have so far is the following: int main() { ListElement* l = new ListElement; l->digit = 9; l->next = NULL; appendList(l, 5); appendList(l, 7); printList(l); return 0; } void appendList(ListElement *&l, int newDigit) { ListElement *lh =

问题 This LinkedList function uses a very dodgy method to avoid client code needing to know about the linking nodes. Each list creates a unique string which is used to intrusively insert properties into the objects being added to the list. Does anyone know of a better way to do this? I should mention that removing objects in constant time is a requirement. It does mean that client code looks like: var myList = new LinkedList() var a = new Something() var b = new SomethingElse() myList.addTail(a)

问题 i have been working with this iterative function since Sunday without any success, I want to create iterative function for sorted insert but after hour of node drawings, I think i would need some help with the function: struct declaration: typedef struct E_Type * List; struct E_Type { int data; struct E_Type* next; }; the function: bool insert(List & l, int data) { while (l != 0) { for (List p = l; p; p = p->next) { if (p->data == data) return false; } if (l->data > data) { List new_list =