linked-list

Meaning of NEXT in Linked List creation in perl

我们两清 提交于 2019-12-13 18:05:13
问题 So I am trying to learn Linked Lists using Perl. I am reading Mastering Algorithms with Perl by Jon Orwant. In the book he explains how to create a linked list. I understand most of it, but I just simply fail to understand the command/index/key NEXT in the second last line of the code snippet. $list=undef; $tail=\$list; foreach (1..5){ my $node = [undef, $_ * $_]; $$tail = $node; $tail = \${$node->[NEXT]}; # The NEXT on this line? } What is he trying to do there? Is $node a scalar, which

Efficiently finding nth from last element in a linked list

别等时光非礼了梦想. 提交于 2019-12-13 17:16:38
问题 What is an efficient way of finding nth from last element in a singly/doubly linked list? 回答1: Here's an efficient way of finding nth from last element in a linked list. struct Node{ int data; struct Node *next; }; int getNthFromLast(struct Node *head, int n){ struct Node *curr = head; struct Node *nthFromLast=NULL; int count=0; int value=-1; while(curr!=NULL){ count++; curr=curr->next; if(count==n){ nthFromLast=head; }else if(count>n){ nthFromLast=nthFromLast->next; } } if(count>=n){ value

Returning multiple values from a recursive function

天大地大妈咪最大 提交于 2019-12-13 16:42:07
问题 I have this problem where I have to convert a decimal number to binary and then store the bits in a linked list where the head node is the most significant bit and the last node is the least significant bit. Solving the problem itself is actually easy as you only need to keep taking the modulo of 2 recursively and add the result in the list until the decimal number becomes 0. Where I'm stuck is that I have to write the function such that it returns a pair of number, (whether an array or a

Add to linked list via tail pointer without 3 levels of indirection

邮差的信 提交于 2019-12-13 16:28:55
问题 I am working on a project that requires an implementation of a linked list. Before I started the project, I was reviewing the classic method of creating a linked list. I realized that in the past, I had been adding elements to a linked list via the head pointer that traverses the list until it reaches the null pointer. I figured out that there is no need to do it this way, and to implement it in a way that involves a tail pointer, but the only way I could think of is a one that involves a

Linked list storing prime numbers from 1 to 1000

被刻印的时光 ゝ 提交于 2019-12-13 15:26:19
问题 As you will see in the comments of the following program, I am supposed to create a list that stores all prime numbers from 1 to 1000 and free the node. Only two of of the functions are my work. However, I haven't figured out for ages why this program does not compile. Do you guys see the mistake? This is an already handed in homework, so this is just for my personal reference. #include <stdio.h> #include <stdlib.h> #include <math.h> /* given data structure declaration */ struct record { int

Sorted Doubly Linked List Python

核能气质少年 提交于 2019-12-13 14:34:15
问题 I'm having trouble understanding and implementing a Doubly Linked List. I can grasp most of the concepts of a Linked List. Here is my code so far (in Python) *This is a purely academic exercise. I would normally use list and dict. class DoublyNode(object): """A node of the SortedDoublyLL object. DoublyNode(item, next=None, previous=None) -> a new DoublyNode with data as its data, and next and previous as its neighbors.""" def __init__(self, data, next = None, previous = None): """Make a new

Detecting loop in a Linked List

Deadly 提交于 2019-12-13 14:16:57
问题 How to detect loop in a linked list using only single pointer? (Don't want slow and fast pointers(Hare and Tortoise)) 回答1: You could use a hastable to store visited nodes as you go forward along the linked list, if you don't mind the extra O(N) memory. At each node you check whether the node already exists in the hashtable. If it does, you have found a loop. Otherwise you add it to the hashtable and move on to the next node. 回答2: Brent's algorithm is clearly the best here: For loop-free lists

How to copy linked list in Python?

故事扮演 提交于 2019-12-13 11:27:22
问题 class _ListNode: class _ListNode: def __init__(self, value, next_): """ ------------------------------------------------------- Initializes a list node. Use: node = _ListNode(value, _next) ------------------------------------------------------- Preconditions: _value - data value for node (?) _next - another list node (_ListNode) Postconditions: Initializes a list node that contains a copy of value and a link to the next node in the list. -------------------------------------------------------

Creating a list with elements other lists (same struct)

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-13 11:03:29
问题 Lets say i have 3 lists : list1,list2,list3. Their struct of each element of those lists : struct node { char value[20] ; struct node * next ; int occurs; } ; typedef struct node Node; typedef Node * List; but i dont think it matters. I want to create a new list but every element of it has to be each of those 3 lists.My new struct for this matter is that(its correct): typedef struct listoflists{ List list; struct listoflists*next; }Nested; My new function to make the list : void

How to make two dimensional LinkedList in java?

梦想的初衷 提交于 2019-12-13 10:50:08
问题 for example: public static LinkedList<String, Double> ll = new LinkedList<String, Double>; 回答1: from your question, I think (not 100% sure) you are looking for java.util.LinkedHashMap<K, V> in your case, it would be LinkedHashMap<String, Double> from java doc: Hash table and linked list implementation of the Map interface, with predictable iteration order. This implementation differs from HashMap in that it maintains a doubly-linked list running through all of its entries. if you do want to