letter

Raphael — Changing the letter color of text string

*爱你&永不变心* 提交于 2019-12-08 08:52:29
(using Raphael_2.01, WindowsXP, Firefox8.0.1) Hello, I'm trying to change the letter color of text by referring to "Drawing Text" of http://www.html5rocks.com/en/tutorials/raphael/intro/ . I can display the text "HTML5ROCKS" but I can't change the color. var t = paper.text(50, 10, "HTML5ROCKS"); var letters = paper.print(50, 50, "HTML5ROCKS", paper.getFont("Courier"), 40); // I think "Vegur" is Mac font. So I change it to "Courier". letters[4].attr({fill:"orange"}); for (var i = 5; i < letters.length; i++) { letters[i].attr({fill: "#3D5C9D", "stroke-width": "2", stroke: "#3D5C9D"}); } What

Letter visualisation in TilePane in JavaFX

随声附和 提交于 2019-12-08 03:13:48
问题 What I need to do: I trying to write some code for visualise every pixel of any character. I decided best way for it will be show pixels as rectangle in Tile Pane. So this is effect which i need to reach: What's my problem: I wrote some code to make it by take snaphost of text1 and save it as WritableImage . Then i use PixelReader for read each pixel of this image by argb method. In loop when each integer rgb value is greater than TRESHOLD (is brighter) I add new tile with white background.

Draw letter(text) with UIBezierPath single line

这一生的挚爱 提交于 2019-12-07 19:01:37
问题 I am using this and this for reference. I am new for using UIBezierPath, and i want to draw path on character(letter) code i am using is as follow. CGMutablePathRef letters = CGPathCreateMutable(); CTFontRef font = CTFontCreateWithName(CFSTR("Courier New"), 200.0f, NULL); NSDictionary *attrs = [NSDictionary dictionaryWithObjectsAndKeys:CFBridgingRelease(font), kCTFontAttributeName,nil]; NSAttributedString *attrString = [[NSAttributedString alloc] initWithString:@"B" attributes:attrs];

Automatically capitalize first letter of first word in a new sentence in LaTeX

寵の児 提交于 2019-12-03 06:16:21
I know one of LaTeX's bragging points is that it doesn't have this Microsoftish behavior. Nevertheless, it's sometimes useful. LaTeX already adds an extra space after you type a (non-backslashed) period, so it should be possible to make it automatically capitalize the following letter as well. Is there an obvious way to write a macro that does this, or is there a LaTeX package that does it already? The following code solves the problem. \let\period. \catcode`\.\active \def\uppercasesingleletter#1{\uppercase{#1}} \def.{\period\afterassignment\periodx\let\next= } \def \periodx{\ifcat\space\next

How to access Letter Recognizer API in Android?

江枫思渺然 提交于 2019-12-03 05:57:10
问题 I am creating a gesture application. In the Gesture class docs http://developer.android.com/reference/android/gesture/Gesture.html) it reads: "A user-defined gesture can be recognized by a GestureLibrary and a built-in alphabet gesture can be recognized by a LetterRecognizer ." So how do you use the LetterRecognizer and where is the docs on it? There's no API for that in the docs, I've also searched android's code itself, and besides the same comment above in the code there's nothing. I've

How to access Letter Recognizer API in Android?

时光总嘲笑我的痴心妄想 提交于 2019-12-02 19:19:45
I am creating a gesture application. In the Gesture class docs http://developer.android.com/reference/android/gesture/Gesture.html ) it reads: "A user-defined gesture can be recognized by a GestureLibrary and a built-in alphabet gesture can be recognized by a LetterRecognizer ." So how do you use the LetterRecognizer and where is the docs on it? There's no API for that in the docs, I've also searched android's code itself, and besides the same comment above in the code there's nothing. I've implemented a letter recognizer manually by drawing the ABC letters to a gesture raw file and using the

python counting letters in string without count function

本小妞迷上赌 提交于 2019-12-02 03:12:19
I am trying to write a program to count the occurrences of a specific letter in a string without the count function. I made the string into a list and set a loop to count but the count is never changing and i cant figure out why. This is what I have right now: letter = 'a' myString = 'aardvark' myList = [] for i in myString: myList.append(i) count = 1 for i in myList: if i == letter: count == count + 1 else: continue print (count) Any help is greatly appreciated. Be careful, you are using count == count + 1 , and you must use count = count + 1 The operator to attribute a new value is = , the

python counting letters in string without count function

天大地大妈咪最大 提交于 2019-12-02 01:49:29
问题 I am trying to write a program to count the occurrences of a specific letter in a string without the count function. I made the string into a list and set a loop to count but the count is never changing and i cant figure out why. This is what I have right now: letter = 'a' myString = 'aardvark' myList = [] for i in myString: myList.append(i) count = 1 for i in myList: if i == letter: count == count + 1 else: continue print (count) Any help is greatly appreciated. 回答1: Be careful, you are

Counting letter occurrence

风格不统一 提交于 2019-12-01 12:24:26
问题 The program needs to count and display the number of times that the specified charector appears in the text file. Currently turning up zero for the total. I'm not if I should be using a different loop, I've also tried using a 'for' loop. // Hold user input and sum String fileName; // Holds the name of the file String letter; // Letter to search for in the file int total = 0; // Holds the total number of characters in the file // Get the name of the file and character from the user fileName =

Determine if string starts with letters A through I

烈酒焚心 提交于 2019-12-01 03:35:48
I've got a simple java assignment. I need to determine if a string starts with the letter A through I. I know i have to use string.startsWith(); but I don't want to write, if(string.startsWith("a")); all the way to I, it seems in efficient. Should I be using a loop of some sort? You don't need regular expressions for this. Try this, assuming you want uppercase only: char c = string.charAt(0); if (c >= 'A' && c <= 'I') { ... } If you do want a regex solution however, you can use this ( ideone ): if (string.matches("^[A-I].*$")) { ... } if ( string.charAt(0) >= 'A' && string.charAt(0) <= 'I' ) {