leap-year

问题 Hello and thanks in advance for the assistance. I have a program that is supposed to print the current month calendar based on the user inputs of month and year. The program mostly work but i am having issues with formatting and the first day of the month is not starting under the proper date. Example output: October 2020 ------------------------------ Sun Mon Tue Wed Thu Fri Sat 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 October 2020 will begin on a

问题 Hello and thanks in advance for the assistance. I have a program that is supposed to print the current month calendar based on the user inputs of month and year. The program mostly work but i am having issues with formatting and the first day of the month is not starting under the proper date. Example output: October 2020 ------------------------------ Sun Mon Tue Wed Thu Fri Sat 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 October 2020 will begin on a

问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . Improve this question I'm having trouble with an exercise on my homework. I have to make a function that tells me when the next leap year is given an n (or n if it's a leap year). I already tackled the last part, but I'm having trouble with the "next leap year" part. I assume I have to

问题 I am Tony and I am new to c++ programming. I would like to ask a question related to creating a program to check for leap year. In the following codes, I try to create a bool function to check whether the input is a leap year. If the input is negative, I will cout "Bye!" and stop the program immediately. If the input is positive, then I will check whether it is a leap year using the bool function I built until the input is a negative number then I will exit the program. However, I am not able

问题 I am Tony and I am new to c++ programming. I would like to ask a question related to creating a program to check for leap year. In the following codes, I try to create a bool function to check whether the input is a leap year. If the input is negative, I will cout "Bye!" and stop the program immediately. If the input is positive, then I will check whether it is a leap year using the bool function I built until the input is a negative number then I will exit the program. However, I am not able

问题 Here is my requirements. Determine If a Year Is a Leap Year Algorithm: If the year can be evenly divided by 4, then it is a leap year Except when the year can be evenly divided by 100, then it is not a leap year Except when the year can be evenly divided by 400, then it is a leap year Otherwise, it is not a leap year I need to know if i did right? private static boolean isLeapYear(int userInput){ boolean leapYear= false; if (userInput % 4 == 0 ){ leapYear = true; if (userInput % 4 == 0 &&

问题 When I need to insert date into the database I need to check 2 things: If this month has 31 days in case day 31 was selected If February is selected, I need to check if it's a leap year in case the user selected 29 Currently I'm checking this using a long function filled with if's and else's . Is there any method in C# that can check a date if it's valid or not before I insert it? 回答1: DateTime temp; if (DateTime.TryParse(yourString, out temp)) { //valid, use temp to insert into DB. } else {

问题 I want to get the number of days in the month which the user specifies. I am using this it works for most months except for Feb and leap year. It shows 28 days and not 29. Can you solve this? begin declare @year int declare @month int select @year = 2012 select @month = DATEPART(mm,CAST('August'+ ' 2012' AS DATETIME)) select datediff(day, dateadd(day, 0, dateadd(month, ((@year - 2012) * 12) + @month - 1, 0)), dateadd(day, 0, dateadd(month, ((@year - 2012) * 12) + @month, 0))) as number_of

问题 Is there an easy way to determine if a year is a leap year? 回答1: Use Date#leap?. now = DateTime.now flag = Date.leap?( now.year ) e.g. Date.leap?( 2018 ) # => false Date.leap?( 2016 ) # => true 回答2: For your understanding: def leap_year?(year) if year % 4 == 0 if year % 100 == 0 if yearVar % 400 == 0 return true end return false end return true end false end This could be written as: def leap_year?(year) (year % 4 == 0) && !(year % 100 == 0) || (year % 400 == 0) end 回答3: Try this: is_leap

问题 This question already has answers here : Java Code for calculating Leap Year (20 answers) Closed 2 years ago . Here is what I have: Scanner input = new Scanner(System.in); System.out.print("Enter a year: "); int Year = input.nextInt(); System.out.print("Enter a month (first three letters with the first" + " letter uppercase): "); String Month = input.next(); String ThirtyOne = "Jan" + "Mar" + "May" + "Jul" + "Aug" + "Oct" + "Dec"; String DaysThirtyOne = ThirtyOne.substring(21) + "31"; String