largenumber

问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: Working with large numbers in PHP. I run a completely useless Facebook app. I'm having a problem with PHP's support for integers. Basically, users give themselves ridiculous numbers of points. The current "king" has 102,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,002,557,529,927 points. PHP does not seem to play well with large integers. When someone tries to add more than a certain

问题 I would like to change the precision in a calculation of R. For example I would like to calculate x^6 with x = c(-2.5e+59, -5.6e+60) . In order to calculate it I should change the precision in R, otherwise the result is Inf , and I don't know how to do it. 回答1: As Livius points out in his comment, this is an issue with R (and in fact, most programming language), with how numbers are represented in binary. To work with extremely large/small floating point numbers, you can use the Rmpfr library

问题 I need a algorithm to perform arithmetic operations on large numbers(that are way above range of float, double int or any other data type for that matter). I am required to write the code in C. I tried looking up here: Knuth, Donald, The Art of Computer Programming, ISBN 0-201-89684-2, Volume 2: Seminumerical Algorithms, Section 4.3.1: The Classical Algorithms but couldn't stand it. I just need the algorithm not the code. 回答1: For addition, as far as I know, you won't get much better than the

问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 6 years ago . I need to get the largest sum of n consecutive digits in a range of a large number. For example, the range could be 5^150000 , within this range I want

问题 Note: Corrected the silly mistake pointed out in the line for i in xrange(10000) I am writing a code for calculating and plotting MittagLeffler functions using a series expansion, import numpy as np import scipy as sp from decimal import Decimal import pylab as plt from math import gamma def MLf(x,a): mlf = Decimal(0) X = (x) term = Decimal(0) for j in xrange(100): term = Decimal((-1)**j*(X**(j*a)))/Decimal(gamma(a*j+1)) mlf = Decimal( term + mlf ) return mlf x = np.arange(0,1000,0.1) y = np

问题 I wrote a program to divide large numbers using strings in C++. That is a string is used to store each digit of the number. I used continuous subtraction to get the remainder and quotient. For ex: 16/5 Subtract 16-5=11 11-5=6 6-5=1 1 is less than 5 so stop quotient = 3 and remainder = 1 But the problem is this method is extremely slow for very large numbers. What other possible method is there to make it fast? 回答1: One approach to get fast bignum computation is to use high values for the base

问题 What is the best way to compare two very large numbers contained in string literals? For example I want to compare the followings: "90000000000000000000000000000000000000000000000000000000000000000000000000001" "100000000000000000000000000000000000000000000000000000000000000000000000000009" or "0000000000111111111111111111111111111111111111111111111111111111111111111111" "0000001111111111111111111111111111111111111111111111111111111111111111111111" In both cases obviously the second one is

问题 I am doing a puzzle where I have to deal with numbers of order 10^18. However, I find python isn't able to handle very large numbers in all areas. To be specific, if we assign a = 1000000000000000000 (10^18) and do basic arithmetic calculations (+, -, /, *), its responding. However, its showing OverflowError when I use it in range() >>> a = 1000000000000000000 >>> a/2 500000000000000000L >>> a*2 2000000000000000000L >>> a+a 2000000000000000000L >>> a*a 1000000000000000000000000000000000000L >

问题 For an ObjectId in MongoDB, I work with a 24 digit hexadecimal number. Because I need to keep track of a second collection, I need to add 1 to this hexadecimal number. In my case, here's my value var value = "55a98f19b27585d81922ba0b" What I'm looking for is var newValue = "55a98f19b25785d81922ba0c" I tried to create a function for this function hexPlusOne(hex) { var num = (("0x" + hex) / 1) + 1; return num.toString(16); } This works with smaller hex numbers hexPlusOne("eeefab") => "eeefac"

问题 I am trying to multiply very large floats by very large integers in Python and am noticing small inaccuracies. For example: a = 45310630.0 b = 1023473145 c = int(a * b) print(c) The answer I am getting is 46374212988031352 but I know the answer should be 46374212988031350. When I change variable "a" to an integer, the multiplication is performed correctly. However, since "a" comes from a division (and might not be a whole number), I can't simply convert it to an integer. 回答1: If you use