laravel-4

Create migration from existing database in Laravel 4

只愿长相守 提交于 2019-12-04 11:23:31
Is it possible to create a migration in Laravel 4 from an existing database? jeanfrg Here is the linked script, that does, what is asked here. I also found this tool (actually a Gist code) and I highly prefer it for its simplicity. 来源: https://stackoverflow.com/questions/23514679/create-migration-from-existing-database-in-laravel-4

Where should I keep the Angularjs files in my web application and how should I structure my routes and resources? [closed]

半腔热情 提交于 2019-12-04 11:23:04
Closed . This question needs to be more focused. It is not currently accepting answers. Learn more . Want to improve this question? Update the question so it focuses on one problem only by editing this post . Closed 5 years ago . I am building a RESTful web service using Laravel and a single page application on the front end with Angluarjs. Now where should I place the Angularjs files? Should I place them in the public folder of the Laravel installation or should I keep them completely separate since the I would be issuing calls to the resources in the web service and it would return JSON data

Seeding database with path from code?

霸气de小男生 提交于 2019-12-04 11:20:28
I've been using Laravel's migrations with the path parameter like so: Artisan::call('migrate', array('--path' => 'path/to/my/Migrations')); Is there anyway I can run the seed command in the same way? I have a number of seed files I want to use but I don't want to run them all at the same time. Any advice appreciated. Thanks Instead of --path you can set --class with namespace to Seeder class. Artisan::call('db:seed', [ '--class' => 'Namespace\Seeds\DatabaseSeeder' ]); This work on Laravel 5.1 Seeding only Artisan::call('db:seed'); Re-run all migration under specified path & run seeds as well

Laravel date format in submission form (d-M-Y)

試著忘記壹切 提交于 2019-12-04 11:11:58
问题 In the submit form in the blade template I have the following date form and it works fine with default date like Y-m-d . But I want to show the date like d-M-Y , I have tried to find a usable solution with out luck Here is the code that works with default date: Here is the model public static $rules = [ 'birthday' => 'date' ]; protected $fillable = ['birthday']; Here is the Controller method public function update($id) { $kid = Kid::findOrFail($id); $validator = Validator::make($data = Input:

Gmail locks account when sending mail via Laravel

。_饼干妹妹 提交于 2019-12-04 11:09:34
问题 When I try to send an e-mail through my website running Laravel 4, I get this exception: Expected response code 250 but got code "535", with message "535-5.7.8 Username and Password not accepted. Learn more at 535 5.7.8 http://support.google.com/mail/bin/answer.py?answer=14257 wd7sm12843789wjc.36 - gsmtp " Here is my mail config: return array( 'driver' => 'smtp', 'host' => 'smtp.gmail.com', 'port' => 465, 'from' => array('address' => 'mymail@gmail.com', 'name' => 'myname'), 'encryption' =>

Laravel resource controllers for both API and non-API use

試著忘記壹切 提交于 2019-12-04 10:40:08
After creating a resource controller PhotosController for a website that also does AJAX calls to the API, it appears that the resource controller can be used on both the normal website and as the API. This displays a HTML page for Photo with id = 1 http://domain.com/photos/1 and Javascript uses the following which updates the Photo resource and returns a JSON response PUT http://domain.com/api/v1/photos/1 Question: Will we have 2 PhotoControllers , one to handle API usage and one for non-API? No. You can have two separate routes point to the same controller and action. Route::get('/photos/1',

Blade view: if statement with OR/AND condition

假装没事ソ 提交于 2019-12-04 10:09:20
问题 Is it possible in Laravel 4.0 -blade-view to do an if statment like so? @if ($var1 === '1' OR $var2 === '1') //Do my stuff @endif Or @if ($var1 === '1' || $var2 === '1') //Do my stuff @endif Or whatever syntax it is. I didn't find anything in the L4 docs, does it exist ? 回答1: It should support all of your standard PHP operators, including || (logical OR). I have tested it myself and it works fine. Additionally, I would recommend simply testing this yourself in future to confirm it works/doesn

Laravel API controller structure?

感情迁移 提交于 2019-12-04 10:00:53
Which one this controller structure for user api make sense Separate controller for UI and API for every api version /app/controllers/UsersController.php /app/controllers/api/v1/ApiUsersController.php or Separate controller for UI and API and handle versioning in code /app/controllers/UsersController.php /app/controllers/api/ApiUsersController.php or Use single controller, detect /api/ call within router. Return html/json depending on the url. /app/controllers/UsersController.php Definitely the first option is the best out of the three, and the reasons are scalability and maintenance . If you

Laravel 4: Publishing a Package's Assets

独自空忆成欢 提交于 2019-12-04 10:00:48
How to publish package assets? I've found a tutorial here: http://laravel-recipes.com/recipes/279 But when I tried to publish assets from my workbench, I get this error: [RuntimeException] Unable to publish assets. asset:publish [--bench[="..."]] [--path[="..."]] [package] My command code is: php artisan asset:publish --bench=Mypackage How can I get my package assets to be published. Thank you. When you want to publish assets that are developed and stored in your workbench you should use the --bench flag. In your case you want to publish a package in the vendor folder then provide "myVendor

Method Chaining based on condition

不想你离开。 提交于 2019-12-04 09:59:32
How can you do method chaining based on condition in laravel 4 ? Say if one value is not false then the method inside will be chained to the method called before the if statement. Is it possible in laravel? $data = User::where('username', $somevariable ); if(isset( $somevar_again )) { $data->where('age', 21); } $data->orderBy('reg_date', 'DESC')->get(); return $data->first(); // tried code above and its giving me wrong result in codeigniter I can do this $this->db->select('e.*, v.name_en as v_name_en') ->from($this->table_name . ' e, ' . $this->ptc_venues . ' v'); $this->db->where('e.venue_id