lambda

Creating a lambda expression at runtime

痞子三分冷 提交于 2021-02-07 18:49:10
问题 I have a repository class which has a GetAsQueryable method defined as follows: public class Repository<TEntity> : IDisposable, IRepository<TEntity> where TEntity : class { internal DbSet<TEntity> _DbSet; public virtual IQueryable<TEntity> GetAsQueryable( Expression<Func<TEntity, bool>> filter = null, Func<IQueryable<TEntity>, IOrderedQueryable<TEntity>> orderBy = null, string includeProperties = "") { IQueryable<TEntity> query = _DbSet; if (filter != null) { query = query.Where(filter); }

Apply function to pandas dataframe row using values in other rows

送分小仙女□ 提交于 2021-02-07 14:53:55
问题 I have a situation where I have a dataframe row to perform calculations with, and I need to use values in following (potentially preceding) rows to do these calculations (essentially a perfect forecast based on the real data set). I get each row from an earlier df.apply call, so I could pass the whole df along to the downstream objects, but that seems less than ideal based on the complexity of objects in my analysis. I found one closely related question and answer [1], but the problem is

Is it possible to break from lambda when the expected result is found

流过昼夜 提交于 2021-02-07 14:48:41
问题 I am Python newbie, and just become very interested in Lambda expression. The problem I have is to find one and only one target element from a list of elements with lambda filter. In theory, when the target element is found there is no sense to continue anymore. With for loop it is pretty simple to break the loop, but what about by using lambda ? is it after all possible to do this? I search from Google, but did not find the expected solution 回答1: From https://docs.python.org/3/library

Is it possible to break from lambda when the expected result is found

南笙酒味 提交于 2021-02-07 14:48:15
问题 I am Python newbie, and just become very interested in Lambda expression. The problem I have is to find one and only one target element from a list of elements with lambda filter. In theory, when the target element is found there is no sense to continue anymore. With for loop it is pretty simple to break the loop, but what about by using lambda ? is it after all possible to do this? I search from Google, but did not find the expected solution 回答1: From https://docs.python.org/3/library

C++17: Wrapping callable using generic variadic lambda

蓝咒 提交于 2021-02-07 14:48:13
问题 I want to wrap a callable of any type (e.g. a lambda) transparently inside another callable to inject additional functionality. The wrapper's type should have the same characteristics as the original callable: Identical parameter types Identical return type Perfect forwarding of passed arguments Same behaviour when used in SFINAE constructs I attempted to use generic variadic lambdas as wrappers: #include <iostream> #include <type_traits> template<class TCallable> auto wrap(TCallable&&

C++17: Wrapping callable using generic variadic lambda

随声附和 提交于 2021-02-07 14:45:43
问题 I want to wrap a callable of any type (e.g. a lambda) transparently inside another callable to inject additional functionality. The wrapper's type should have the same characteristics as the original callable: Identical parameter types Identical return type Perfect forwarding of passed arguments Same behaviour when used in SFINAE constructs I attempted to use generic variadic lambdas as wrappers: #include <iostream> #include <type_traits> template<class TCallable> auto wrap(TCallable&&

Java Method reference not expected here

爷,独闯天下 提交于 2021-02-07 14:26:28
问题 How exactly do you chain method references for instances with Java 8? Example: Collections.sort(civs,Comparator.comparing(Civilization::getStrategy.getStrategLevel)); getStrategy of a Civilization instance returns a Strategy object instance which has the instance method getStrategyLevel . Why doesn't the Comparator.comparing method return a comparator with it's functional interface implemented by the lambda expression? 回答1: In that case, you should use a lambda, you can't apply a method

Lambda not supporting NLTK file size

爱⌒轻易说出口 提交于 2021-02-07 14:19:28
问题 I am writing a python script that analyses a piece of text and returns the data in JSON format. I am using NLTK, to analyze the data. Basically, this is my flow: Create an endpoint (API gateway) -> calls my lambda function -> returns JSON of required data. I wrote my script, deployed to lambda but I ran into this issue: Resource \u001b[93mpunkt\u001b[0m not found. Please use the NLTK Downloader to obtain the resource: \u001b[31m>>> import nltk nltk.download('punkt') \u001b[0m Searched in: - '

Lambda not supporting NLTK file size

ε祈祈猫儿з 提交于 2021-02-07 14:17:36
问题 I am writing a python script that analyses a piece of text and returns the data in JSON format. I am using NLTK, to analyze the data. Basically, this is my flow: Create an endpoint (API gateway) -> calls my lambda function -> returns JSON of required data. I wrote my script, deployed to lambda but I ran into this issue: Resource \u001b[93mpunkt\u001b[0m not found. Please use the NLTK Downloader to obtain the resource: \u001b[31m>>> import nltk nltk.download('punkt') \u001b[0m Searched in: - '

Kotlin filter lambda array using iteration index

北城余情 提交于 2021-02-07 12:19:01
问题 I would like to filter an array into an array of every nth item. For examples: fun getNth(array: Array<Any>, n: Int): Array<Any> { val newList = ArrayList<Any>() for (i in 0..array.size) { if (i % n == 0) { newList.add(array[i]) } } return newList.toArray() } Is there an idiomatic way to do this using for example Kotlin's .filter() and without A) provisioning a new ArrayList and B) manually iterating with a for/in loop? 回答1: filterIndexed function is suited exactly for this case: array