keyword

Is C++14 adding new keywords to C++?

巧了我就是萌 提交于 2019-12-20 08:24:02
问题 The C++ Standards Committee tends to shy away from adding new keywords to the language, yet with C++11 that was not the case. Some examples: constexpr decltype thread_local auto // New usage noexcept nullptr static_assert alignof alignas Are there any new keywords introduced with C++14? 回答1: Table 4 (Keywords) in N3936 (C++14): alignas continue friend register true alignof decltype goto reinterpret_cast try asm default if return typedef auto delete inline short typeid bool do int signed

Is C++14 adding new keywords to C++?

前提是你 提交于 2019-12-20 08:23:04
问题 The C++ Standards Committee tends to shy away from adding new keywords to the language, yet with C++11 that was not the case. Some examples: constexpr decltype thread_local auto // New usage noexcept nullptr static_assert alignof alignas Are there any new keywords introduced with C++14? 回答1: Table 4 (Keywords) in N3936 (C++14): alignas continue friend register true alignof decltype goto reinterpret_cast try asm default if return typedef auto delete inline short typeid bool do int signed

Is C++14 adding new keywords to C++?

白昼怎懂夜的黑 提交于 2019-12-20 08:22:05
问题 The C++ Standards Committee tends to shy away from adding new keywords to the language, yet with C++11 that was not the case. Some examples: constexpr decltype thread_local auto // New usage noexcept nullptr static_assert alignof alignas Are there any new keywords introduced with C++14? 回答1: Table 4 (Keywords) in N3936 (C++14): alignas continue friend register true alignof decltype goto reinterpret_cast try asm default if return typedef auto delete inline short typeid bool do int signed

In Java compiler,which type can be defined as identifier ( ID ) or Keyword (reserved word)?

≡放荡痞女 提交于 2019-12-20 05:02:08
问题 I have a simple question: In Java Compiler, Which type of method or variables can be defined as identifier (ID) or Keyword (reserved word)? For following example, ID should be : add , main , a , b , c , Test1 , What about print , is print an ID or keyword? Example: public class Test1 { public static int add(int a, int b) { return a + b; } public static void main() { int c; int a = 5; c = add(a, 10); if (c > 10) print("c = " + -c); else print(c); print("Hello World"); } } 回答1: An identifier is

Why does the xcode IDE think `friend` is a reserved-word

和自甴很熟 提交于 2019-12-20 04:10:30
问题 I've been working on a personal project and have the below code in a new class that I have created: @property (readonly, getter = isFriend) BOOL friend; There doesn't seem to be anything wrong with it and when I build it, it works compiles absolutely fine but when we look at this line of code in the xcode IDE it looks like My question is why does the xcode IDE seem to think that the word friend is a keyword/reserved-word? 回答1: Presumably because friend is a reserved word in C++. See

Why does the xcode IDE think `friend` is a reserved-word

独自空忆成欢 提交于 2019-12-20 04:09:20
问题 I've been working on a personal project and have the below code in a new class that I have created: @property (readonly, getter = isFriend) BOOL friend; There doesn't seem to be anything wrong with it and when I build it, it works compiles absolutely fine but when we look at this line of code in the xcode IDE it looks like My question is why does the xcode IDE seem to think that the word friend is a keyword/reserved-word? 回答1: Presumably because friend is a reserved word in C++. See

Does the initializer of an `open` class need to be open as well?

妖精的绣舞 提交于 2019-12-20 02:34:50
问题 Swift 3 introduced the new open keyword that I'm using in a framework. Does an open class in this framework require an open initialiser to be used outside of said framework, or does the init function inherit the open declaration on the class? For example: open class OpenClass { var A: String init() { // does this init() function need to be marked open? A = String() } } Side question: do the variables in the open class OpenClass inherit the open nature of their class? 回答1: From SE-0117 Allow

Why can't we override `||` and `&&`?

蹲街弑〆低调 提交于 2019-12-19 14:04:43
问题 David A. Black stated in his book: [T]he conditional assignment operator ||= , as well as its rarely spotted cousin &&=, both of which provide the same kind of shortcut as the pseudooperator methods but are based on operators, namely || and && , which you can’t override. Why did he specifically mention that we can't override || and && ? 回答1: Unlike some other operators on objects, who's behavior logically can depend on class, the boolean operators are part of the language. When you have an

Keyword Extraction in Python_RAKE

流过昼夜 提交于 2019-12-19 11:53:32
问题 I am a novice user and puzzled over the following otherwise simple "loop" problem. I have a local dir with x number of files (about 500 .txt files). I would like to extract the corresponding keywords from each unique file using RAKE for Python. I've reviewed the documentation for RAKE; however, the suggested code in the tutorial gets keywords for a single document. Can someone please explain to me how to loop over an X number of files stored in my local dir. Here's the code from the tutorial

Keyword Extraction in Python_RAKE

吃可爱长大的小学妹 提交于 2019-12-19 11:53:13
问题 I am a novice user and puzzled over the following otherwise simple "loop" problem. I have a local dir with x number of files (about 500 .txt files). I would like to extract the corresponding keywords from each unique file using RAKE for Python. I've reviewed the documentation for RAKE; however, the suggested code in the tutorial gets keywords for a single document. Can someone please explain to me how to loop over an X number of files stored in my local dir. Here's the code from the tutorial