How to repeat a function call in jQuery
问题 I have this code: <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.3.min.js"></script> <script type="text/javascript"> $(document).ready(function() { function loop(){ $('#picOne').fadeIn(0).fadeOut(8000); $('#picTwo').delay(2000).fadeIn(6000).fadeOut(5000); $('#picTree').delay(10000).fadeIn(2000).fadeOut(16000); $('#picFour').delay(12000).fadeIn(16000).fadeOut(5000); } loop(); }); </script> But when the last pic fades out, the code doesn't repeat. What is the problem? 回答1