jpql

问题 I have an Entity: @Entity(name = "target_group") public class TargetGroup extends AbstractEntity { private String name; private String description; @ManyToMany(fetch = FetchType.LAZY) private List<Customer> customers = new ArrayList<>(); getter.setter... } And I have a code, to get a list about the groups with the stableId (which is in the Abstract Class): public TargetGroup getTargetGroupByStableId(String stableId) { TargetGroup tg = null; try { Query q = em.createQuery("SELECT tg FROM

问题 I'm fairly new to JPA (and JPQL by extension). Hopefully, someone will be able to enlighten me with this problem. The query I'm trying to execute ... String query = "select u from user u where u.email = '" + userEmail + "' and u.password = sha1('"+ userPassword + "')"; List resultList = emf.createEntityManager().createQuery(query).getResultList(); And I'm getting the follwowing exception ... Caused by: Exception [EclipseLink-8025] (Eclipse Persistence Services - 2.2.0.v20110202-r8913): org

问题 I have a full Java EE web application with a presentation layer and a database. I'm using derby with glassfish 3.1 and JPA to handle persistence. I've created a Read ok but now I'm having troulbe doing a Create and persisting to the database. I think I'm close but something is not right with the way I'm trying to do the create. Here is my EAO code: /** * Session Bean implementation class XRSSeao */ @Stateless @LocalBean public class XRSSeao { @PersistenceContext EntityManager em; public

问题 I'd like to search a requested value in my database using the entity manager createquery function. Whenever I executed my method, I got the following error message: llegalArgumentException: You have attempted to set a value of type class java.lang.String for parameter searchvalue with expected type of int from query string It says that a int value is required, but I think that every like expression requires a string value? Entity: public class Contract implements Serializable { private static

问题 I needed to change my JPQL query because it turned out that the last element of types ( contains 5 elements ) contains a wildcard so it can itself contain many elements basically. So now I changed the original query to only check if the TestcaseEntity contains 4 types instead of 5 and all the testcases coming out of this query I check now if they have any of the typesVariants ( previous 5 element ) which should deliver the resulting testcases. So now I wrote a subselect . What I found out now

问题 How I can made a select of a property of type list on JPQL? example: @Entity public class Person { @id private Long id; private String name; private String lastname; private String birthdate; @OneToMany private List<Phone> getPhones(); ... } @Entity public class Phone { @id private Long id; private String number; ... } And on repository I want a projection, so: public interface IPersonProjection { Long getId(); String getName(); List<Phone> phones(); } @Repository public interface

问题 Given the following table layout: CREATE TABLE things ( id BIGINT PRIMARY KEY NOT NULL, foo BIGINT NOT NULL, bar BIGINT NOT NULL ); An entity class (Kotlin): @Entity @Table(name = "things") class Thing( val foo: Long, val bar: Long ) : AbstractPersistable<Long>() And a repository: interface ThingRepository : JpaRepository<Thing, Long> { @Query("SELECT t FROM Thing t WHERE t.foo IN ?1") fun selectByFoos(foos: Iterable<Long>): Iterable<Thing> @Query("SELECT t FROM Thing t WHERE (t.foo, t.bar)

问题 I'm trying to make a very simple JPQL using a join but I'm having zero success. I want to get the most recent log in date of a user, given a user id. I am using Spring Data JPA + Hibernate. I have a MySQL database which contains the table Activity: @Table(name = "activity") @SuppressWarnings("serial") public class Activity implements Serializable { @Id @GeneratedValue private Long id; @Column(name = "date", insertable = true, nullable = false, updatable = false) @Temporal(TemporalType

问题 I want to convert varchar to int in jpql. The field is varchar, but all the data will be in integer format only. My JPA library version is 1.9 I already used CAST and CONVERT methods, but it did not working. My query is: select SUM(Cast(model.wagonsRequired as INT)) from IptRailcargolines model where model.iptRailwayindent.id=7 or select SUM(CONVERT(INT, model.wagonsRequired)) from IptRailcargolines model where model.iptRailwayindent.id=7 and my java console error is: Caused by: Exception

问题 How to change this complex sql statement into JPQL? select a.name, a.surname, b.street, c.location, c.location_desc from table1 join table2 on b.id = a.some_fk left join table3 d on d.id = a.id left join table4 c on c.some2_id = d.some2_fk where a.id = 400; If this is possible to present in the JPQL form? 回答1: Impossible to give a definitive answer without knowing the entities and their mapping, but the query would look like this: select a.name, a.surname, b.street, c.location, c.locationDesc