jpa-2.1

Getting error Could not locate appropriate constructor on class

╄→гoц情女王★ 提交于 2019-12-02 20:31:16
I am trying to map native SQL result to my POJO. Here is the configuration. I am using spring. <bean id="ls360Emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" > <property name="dataSource" ref="ls360DataSource" /> <property name="jpaVendorAdapter" ref="vendorAdaptor" /> <property name="packagesToScan" value="abc.xyz"/> <property name="jpaProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop> <prop key="hibernate.max_fetch_depth">3</prop> <prop key="hibernate.jdbc.fetch_size">50</prop> <prop key="hibernate.jdbc.batch_size"

how to make database configuration configurable of persistance.xml file through database.properties file

感情迁移 提交于 2019-12-02 18:41:17
问题 I would like to get confirmation on the query "Is there any way to make database configurations configuration through database.properties using in persistance.xml ". Is the below possible? My following configuration works absolutely fine, <?xml version="1.0" encoding="UTF-8"?> <persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns

Add WHERE IN clause to JPA Specification

你。 提交于 2019-12-02 18:19:33
问题 I'm trying to implement search functionality limited by IN clause: I want to implement search implementation with filter limitation: @GetMapping("find") public Page<MerchantUserDTO> getAllBySpecification( @And({ @Spec(path = "name", spec = LikeIgnoreCase.class), @Spec(path = "login", spec = LikeIgnoreCase.class), @Spec(path = "email", spec = LikeIgnoreCase.class), }) Specification<Users> specification, @SortDefault(sort = "login", direction = Sort.Direction.DESC) Pageable pageable ) { return

Auto generate data schema from JPA 2.1 annotated entity classes without a database connection

自闭症网瘾萝莉.ら 提交于 2019-12-02 07:30:40
Two years ago I was working on a project using: spring 4.0.3.RELEASE jpa 2.0 hibernate 4.2.7.Final java 1.6.X This project has a maven task hibernate3-maven-plugin which allow us to generate a database schema without any connection to a database (MySQL). Now we are upgrading this project with: java 1.8 jpa 2.1 spring 4.2.4.RELEASE hibernate 5.0.6.Final I understand that hibernate3-maven-plugin does not work on JPA 2.1 and hibernate > 4.3. All the solution I have found need a connection to a database. For instance: Auto generate data schema from JPA annotated entity classes . Does anyone know

Entity Table is not creating using JPA 2.1

夙愿已清 提交于 2019-12-01 23:55:21
问题 I am using JPA 2.1 in Netbeans to create my entity. If my database has no table then it should create table from entities. When I deploy and run my enterprise application, the userEntity table does not appear in my mySQL database. Any help here? :) Below are my codes. persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml

How to use Constructor Mapping with Spring JPA Repositories

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-01 18:09:37
I have a Spring repository as follows: import org.springframework.data.repository.Repository; import org.springframework.stereotype.Component; import com.test.domain.My; @Component public interface MyRepository extends Repository<My, String> { My findOne(String code); My findByName(String name); } The entity class is: import javax.persistence.ColumnResult; import javax.persistence.ConstructorResult; import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.SqlResultSetMapping; import javax.persistence.Table; import com.fasterxml.jackson.annotation.JsonCreator;

Unexpected token (START_OBJECT), expected VALUE_STRING: need JSON String that contains type id (for subtype of java.lang.Object)

风格不统一 提交于 2019-12-01 12:57:32
I already went through the below few links, but it did not solved my problem: Java Jackson: deserialize complex polymorphic object model: JsonMappingException: Unexpected token (START_OBJECT), expected VALUE_STRING Java Jackson - Unexpected token (START_ARRAY), expected VALUE_STRING In my project, we've 15 batch jobs. I am converting 15 batch jobs into 15 different micro-services. For that I have created one Spring Boot module, which has Entity classes, JPA repository layer and service layer. That jar I will import into each micro-services (batch jobs), so that batch job should work fine. I am

Schema generation with EclipseLink and Hibernate (JPA2.1) - @ForeignKey ignored

不羁岁月 提交于 2019-11-30 22:58:47
I am testing JPA2.1 and the new "schema generation" feature. For that, I tested two implementations under the HyperSQL database : EclipseLink 2.5.2-M1 which is the reference implementation. Hibernate 4.3 I don't have any preference for an implementation (not even for performance). I tested EclipseLink because it was the first JPA2.1 implementation available, but now, Hibernate 4.3 is here and JPA2.1 compliant. The only thing I want is to get something independent from the JPA provider - except for the configuration (like cache, logging, static weaving, ...). As for schema generation, several

IN clause with a composite primary key in JPA criteria

旧街凉风 提交于 2019-11-30 20:12:36
I have a table named group_table in MySQL with only two columns user_group_id and group_id (both of them are of type VARCHAR ). Both of these columns together form a composite primary key. I need to execute a statement using a sub-select IN() to select rows based on a list of values passed to the query. @Override @SuppressWarnings("unchecked") public List<GroupTable> getList(List<GroupTable> list) { CriteriaBuilder criteriaBuilder=entityManager.getCriteriaBuilder(); CriteriaQuery<GroupTable> criteriaQuery=criteriaBuilder.createQuery(GroupTable.class); Root<GroupTable> root = criteriaQuery.from

Named Entity Graph Sub-Subgraph

本秂侑毒 提交于 2019-11-30 13:38:35
问题 I am new to JPA 2.1 and started using only recently Named Entity Graphs. For my project I am mapping the following relation in JPA 2.1: Order -> OrderDetail -> Product -> ProductLine The question: I want to instruct JPA to join and fetch properly all the needed data. So far this works flawlessly for Order -> OrderDetail -> Product but I have not managed so far to add a Sub-Sub Graph in order to go as deep as the ProductLine class. How do I make a subgraph of a subgraph ? Ex get the