jpa-2.0

I have spent three days trying to find the solution to this problem to no avail. I am desperate to figure this out. I have a simple spring app, running in servlet 2.5 with jstl tags 1.2, running in tomcat with spring 3.1, using hibernate and the hibernate jpa implementation. I can list data from a page, but I cannot complete an insert. The record goes back, it appears to fire through with no problems. Yet no insert takes place. I know there are other posts similar but I have looked through them all and have not been able to find a solution anywhere. If I run the exact same code via a MAIN

I have two entities Like SmsOut and SmsIn . The relation between two entities contains OneToMany where smsIn.id is primary key and smsOut.sms_in_id is foreign key . Now I want to pass parameter like smsIn.mobileNumber , smsIn.smsText and so on, on the query SELECT so FROM SmsOut so order by id desc Following is my database diagram: Edited Following is my code : String sql = "SELECT so FROM SmsOut so WHERE so.smsInId.mobileNumber =:mobileNumber AND so.smsInId.smsText =:smsText AND so.smsInId.shortCode =:shortCode between so.smsOutDate =:startDate and so.smsOutDate =:endDate order by id desc";

The JPA 2.0 Provider Hibernate is throwing exception while preparing configuration for entity manager factory, I am using DB2 v9.5 database and DB2 v9.5 JDBC type 2 driver . java.sql.SQLException: [IBM][JDBC Driver] CLI0626E getDatabaseMajorVersion is not supported in this version of DB2 JDBC 2.0 driver. at COM.ibm.db2.jdbc.app.SQLExceptionGenerator.throwNotSupportedByDB2(Unknown Source) at COM.ibm.db2.jdbc.app.DB2DatabaseMetaData.getDatabaseMajorVersion(Unknown Source) at org.hibernate.cfg.SettingsFactory.buildSettings(SettingsFactory.java:117) at org.hibernate.cfg.Configuration

I have the following entity class (ID inherited from PersistentObjectSupport class): @Entity public class AmbulanceDeactivation extends PersistentObjectSupport implements Serializable { private static final long serialVersionUID = 1L; @Temporal(TemporalType.DATE) @NotNull private Date beginDate; @Temporal(TemporalType.DATE) private Date endDate; @Size(max = 250) private String reason; @ManyToOne @NotNull private Ambulance ambulance; /* Get/set methods, etc. */ } If I do the following query using the Criteria API: CriteriaBuilder cb = em.getCriteriaBuilder(); CriteriaQuery<AmbulanceDeactivation

am new to JPA and am able to get it quickly, I had been trying a select query using "IN" operator in the query and had been getting the error as down. What I do is, i get a array of (long) message ids from a function and i use it to select the record based on those ids. Here is my query select t from MessageTable t where t.messageId IN (:id) query.setParameter("id", id); I had just shown you part of the code, in entity messageId is long and in Oracle DB its number. When i try as just as long variable it works, it doesn't seem to work when i pass long array. Had any one come across such a

I have "post" entity/table with this "schema": @Id @GeneratedValue(strategy = GenerationType.AUTO) int id; @GeneratedValue(strategy = GenerationType.AUTO) private Integer postId; private Integer revisionId; private Boolean isCurrentRevision; So, table contains posts, each of them has multiple revisions, but only of them (for each post) is current. Now, let's say I want to persist another revision of existing post (i.e. update post): I need to find highest existing revisionId for this postId, increment it and set it to revisionId. Also this is the new current revision and so it should be marked