jpa-2.0

问题 I have this table which I would like to store a chain of records. CREATE TABLE table_name ( id INT, unique_id varchar, reference_id varchar, ); I want to implement SQL query for MariDB which prints all records by unique_id with all record reference_id. Something like this: | id | unique_id | reference_id | | | |----|-----------|--------------|---|---| | 43 | 55544 | | | | | 45 | 45454 | 43 | | | | 66 | 55655 | 45 | | | | 78 | 88877 | 66 | | | | 99 | 454 | 33 | | | I would like when I select

问题 I have defined my bindings in the following way <jaxb:bindings node="xs:complexType[@name='Parent']"> ........... <jaxb:bindings node="xs:element[@name='children']"> <hj:one-to-many name="children" fetch="EAGER"> <orm:order-column name="CHILD_PRIMARY_KEY"/> <orm:join-column name="PARENT_PRIMARY_KEY"/> </hj:one-to-many> </jaxb:bindings> </jaxb:bindings> But the generated class has OrderColumn annotation missing. i.e @OneToMany(targetEntity = Children.class, cascade = { CascadeType.ALL }, fetch

问题 From my entity I'm trying to rename the id column field defined in AbstractPersistable by Spring Data Jpa using AttributeOverride annotation. @Entity @AttributeOverride(name="id", column=@Column(name="user_id")) public class User extends AbstractPersistable<Long> { ... this is failing with the exception Caused by: org.hibernate.MappingException: Unable to find column with logical name: id in org.hibernate.mapping.Table(user) and its related supertables and secondary tables the only time the

问题 I have the following type of query that I wish to convert into a jpa criteria query and the following table structure: Table A 1-->1 Table B 1<--* Table C (proceedings) *-->1 Table D(prcoeedingsstatus) -------- -------- ------- ------- aID bID cID dID ... .... timestamp textValue f_bID .... f_bID f_dID 1 A has 1 B, 1 B has many proceedings and each proceeding has a proceedingstatus. SELECT a.* FROM ((a LEFT JOIN b ON a.f_b = b.id) LEFT JOIN proceedings ON b.id = proceedings.f_b) RIGHT JOIN

问题 Using the Google Eclipse Plugin, my project automatically comes with two files inside the META-INF folder: jdoconfig.xml and persistence.xml . Per the instructions on https://developers.google.com/appengine/docs/java/datastore/jpa/overview, my persistence file is supposed to have the following line for jpa datastore storage: <provider>org.datanucleus.store.appengine.jpa.DatastorePersistenceProvider</provider> But when I open the persistence file I found <?xml version="1.0" encoding="UTF-8" ?>

问题 I'm trying to use a OneToOne relationship to add optional data ( ExtraData ) to a main class ( MainItem ). All instances of ExtraData should be linked to an instance of MainItem , but not all instances of MainItem need to have an instance of ExtraData . (I'm primarily interested in a unidirectional relationship, but it seems that I need a bidirectional relationship to be able to cascade the updates and deletions of MainItem to ExtraData .) I'm having trouble using @Id , @OneToOne and

问题 How to get the value which being saved to database after entityManager.persist I am able to get the primary key value from database after calling persist not any other values. E.g. public void create(Project project) { entityManager.persist(project); System.out.println("Id -- " + project.getProjectId()); System.out.println("no -- " + project.getProjectNo()); } From the above code I am able to get the newly inserted value from project.getProjectId , however not able to get project.getProjectNo

问题 I generated the application with JHipster with Gradle as the build tool. When I created entity I added filtering support, which generated JPA static metamodel. But IntelliJ doesn't recognize the metamodels. I have enabled the annotation processor settings on IntelliJ but it doesn't seem to work. What settings do I have to change for IntelliJ to recognize the JPA static metamodels? 回答1: To get IntelliJ IDEA to recognize the generated classes, I had to add this line on build.gradle sourceSets {

问题 P6spy v2 has a support for xa datasources - P6spy on github In my jboss AS 7 standalone-full-ha.xml, i have the following datasource configurations. <xa-datasource jndi-name="java:jboss/datasources/MyDS" pool-name="v" enabled="true" use-java-context="true" use-ccm="false"> <xa-datasource-property name="ServerName"> localhost </xa-datasource-property> <xa-datasource-property name="PortNumber"> 5432 </xa-datasource-property> <xa-datasource-property name="DatabaseName"> MyDB </xa-datasource

问题 Hi does anyone know what the preferred way to do programmatically create a JPA EntityManagerFactory impl from Hibernate in Hibernate 4+? I used hsql to do this, but its depricated; Properties props = new Properties(); props.setProperty("hibernate.dialect", "org.hibernate.dialect.MySQLInnoDBDialect"); props.setProperty("hibernate.connection.driver_class", "org.hsqldb.jdbcDriver"); props.setProperty("hibernate.connection.url", "jdbc:hsqldb:mem:aname"); props.setProperty("hibernate.connection