jinja2

Creating link to an url of Flask app in jinja2 template

泪湿孤枕 提交于 2019-12-17 21:48:20
问题 In my Flask app, I have a view which displays a post @post_blueprint.route('/post/<int:year>/<int:month>/<title>') def get_post(year,month,title): # My code To display the last 10 entries, I have following view: @post_blueprint.route('/posts/') def get_all_posts(): # My code return render_template('p.html',posts=posts) Now when I display the last 10 posts, I want to convert the title of a post into a hyperlink. Currently I have to do the following in my jinja template to achieve this: <a href

How do you include flask/jinja2 code inside a markdown file?

蓝咒 提交于 2019-12-17 20:42:04
问题 I am using a markdown editor which is converted by post_body = markdown(text_from_markdown_editor) but when i render the html, the actual jinja2 code is displayed This is a post by {{ post.author }} instead of the actual value. 回答1: I've been seeing this issue come up a lot lately in various different places, both in relation to Jinja and Django Templates. There seems to be a fundamental misunderstanding (among some users) about how templates systems work and how that relates to Markdown text

Convert integer to string Jinja

被刻印的时光 ゝ 提交于 2019-12-17 17:53:36
问题 I have an integer {% set curYear = 2013 %} In {% if %} statement I have to compare it with some string. I can't set curYear to string at the beginning because I have to decrement it in loop. How can I convert it? 回答1: I found the answer. Cast integer to string: myOldIntValue|string Cast string to integer: myOldStrValue|int 来源: https://stackoverflow.com/questions/19161093/convert-integer-to-string-jinja

Link to a specific location in a Flask template

橙三吉。 提交于 2019-12-17 16:38:21
问题 In HTML I can link directly to a specific location on a page, assuming there's an element with the given id: <a href="http://www.example.com/stuff.html#exactlocation">Go there</a> In Flask I tried to add the anchor to render_template but I get jinja2.exceptions.TemplateNotFound: stuff.html#exactlocation . @main.route('/exactlocation') def exactlocation(): return render_template('stuff.html#exactlocation') How do I link to a specific location in a template? 回答1: Thanks to dirn's comments I

Ansible - Could not use lookup file module for a file under /etc/

丶灬走出姿态 提交于 2019-12-17 15:00:50
问题 I am deploying a CentOS machine and one among the tasks was to read a file that is rendered the Consul service which places it under /etc/sysconfig . I am trying to later read it in a variable using the lookup module but it is throwing an error below: fatal: [ansible_vm1]: FAILED! => {"failed": true, "msg": "could not locate file in lookup: /etc/sysconfig/idb_EndPoint"} But I am running the lookup task way below the point where the idb_EndPoint file is generated and also I looked it up

How to get the first element of a list from the output of setup module in Ansible?

▼魔方 西西 提交于 2019-12-17 07:42:34
问题 I received the following data from the setup module: "ansible_nodename": "3d734bc2a391", "ansible_os_family": "RedHat", "ansible_pkg_mgr": "yum", "ansible_processor": [ "AuthenticAMD", "AMD PRO A10-8700B R6, 10 Compute Cores 4C+6G" ], "ansible_processor_cores": 1, "ansible_processor_count": 1, "ansible_processor_threads_per_core": 1, I want to retrieve the 1st value of ansible_processor and use it in a Jinja2 template. If I use {{ ansible_processor }} , it's giving me both values:

Python Flask Render Text from Variable like render_template

孤人 提交于 2019-12-17 06:54:03
问题 I know the flask function render_template . I have to give the file name of the template. But now I want to render the string of a template (that is the content of the template). That makes sense. but I don't want to explain now why. How can I render the text of a template simply? 回答1: You can use render_template_string: >>> from flask import render_template_string >>> render_template_string('hello {{ what }}', what='world') 'hello world' 回答2: you can use from_string template = "text {{ hello

Python Flask Render Text from Variable like render_template

笑着哭i 提交于 2019-12-17 06:52:24
问题 I know the flask function render_template . I have to give the file name of the template. But now I want to render the string of a template (that is the content of the template). That makes sense. but I don't want to explain now why. How can I render the text of a template simply? 回答1: You can use render_template_string: >>> from flask import render_template_string >>> render_template_string('hello {{ what }}', what='world') 'hello world' 回答2: you can use from_string template = "text {{ hello

Comments not working in jinja2

核能气质少年 提交于 2019-12-17 04:08:34
问题 I have a template(test.html) as follows: {% extends 'base.html' %} {% from "_formhelpers.html" import render_field %} {% block content %} <div class="container"> <div class="row"> <div class="span6 offset3"> <form class="form-horizontal" action="/create_user/" method="post"> {{ form.csrf_token }} <dl> {{ render_field(form.name) }} {{ render_field(form.members) }} <!--<div class="control-group"> <label class="control-label"> {{ form.task.label }} </label> <div class='controls'> {{ form.task}}

Comments not working in jinja2

谁都会走 提交于 2019-12-17 04:08:25
问题 I have a template(test.html) as follows: {% extends 'base.html' %} {% from "_formhelpers.html" import render_field %} {% block content %} <div class="container"> <div class="row"> <div class="span6 offset3"> <form class="form-horizontal" action="/create_user/" method="post"> {{ form.csrf_token }} <dl> {{ render_field(form.name) }} {{ render_field(form.members) }} <!--<div class="control-group"> <label class="control-label"> {{ form.task.label }} </label> <div class='controls'> {{ form.task}}