java.library.path

How do I modify Eclipse's library.path?

旧街凉风 提交于 2019-12-11 12:46:20
问题 I have rather perhaps general question... I am using Eclipse as my IDE... When I go to ->HELP ->ABOUT ECLIPSE SDK ->INSTALLATION DETAILS ->CONFIGURATION, I see the line entries: -Djava.class.path =C:\Eclipse\etc... and java.library.path =C:\Eclipse\etc... I have two questions on this... 1) What does -Djava.class.path mean in the context of ECLIPSE environment? 2) How do I alter/modify java.library.path option for eclipse, so that the changes that I make are visible in the eclipse's

Obtain path of jar when running inside a .app on mac os x

依然范特西╮ 提交于 2019-12-11 11:39:13
问题 I've my javafx jar running inside a .app. Now if I execute System.getProperty("user.dir") I get location of user home i.e. /Users/DevAccount/ where DevAccount is system user name instead of location of .app file or .jar file. How do I find where the .app is actually running from at runtime? Alternatively please suggest how to set java.library.path to a folder within a .app bundle. Note: If I run jar outside .app I'm able to set java.library.path as desired but when .app is run, user.dir

Add java.library.path to java manifest

ぐ巨炮叔叔 提交于 2019-12-10 11:24:23
问题 The java.library.path can be set before or during the execution of a java app (either by setting the global environment variables of the java library path or by using a flag when running the java exec jar). Can it be set inside the manifest file of the java jar, as is done for classes with Class-Path? Sounds like a feature that should be supported, if it does not exist. EDIT : since as stdunbar mentioned, the manifest file does not support java.library.path mappings, I've added an answer with

java.lang.UnsatisfiedLinkError: com.jacob.com.D...

与世无争的帅哥 提交于 2019-12-07 15:30:41
最近做一个系统的维护改善工作,从来没接触过的业务,代码中没有一句注释。各种bug堆积转狂。 一条改到导出word的功能的时候,系统使用了jacob操作但是系统一直报错, Exception in thread "main" java.lang.UnsatisfiedLinkError: no jacob in java.libr ary.path 查了下资料 ,基本都是说没正确的放入library中,并提供了3处以上的位置,实际测试后只要放在 \Java\jdk1.6.0_32\jre\bin下就可以了。 重新配置了myeclipse的jre 选择了tomcat的jdk 重新启动后发现系统仍然报着个错误,考虑我用的是win7 64位 安装的是64位的jdk,重新下载了一个32位的安装了一下,仍然用jacob-1.17-M2-x86.dll 。依据报如上的错误。 于是我将dll重新命名成jacob.dll运行在系统中。 系统报错 j ava.lang.UnsatisfiedLinkError: com.jacob.com.Dispatch.createInstance(Ljava/lang/String;)V 我查了一下大体上是说jar和dll的版本存在冲突,我调试了用最新的版本仍然存在这个问题。 于是怀疑是自己的项目有问题,但是也没有找到什么疑问点。就重新写了一个新项目

Where and when is the instance of PathClassLoader created in android source code?

戏子无情 提交于 2019-12-07 12:24:26
问题 When I was studying android source code, I noticed that the general class loader in app is an instance of PathClassLoader , and there is two constructors in this class. One is like: public PathClassLoader(String dexPath, ClassLoader parent) { super(dexPath, null, null, parent); } and the other is like: public PathClassLoader(String dexPath, String libraryPath, ClassLoader parent) { super(dexPath, null, libraryPath, parent); } But I cannot find the call of the second constructor in the source

How can I set the java.library.path used by eclipse from a POM?

杀马特。学长 韩版系。学妹 提交于 2019-12-07 02:05:43
问题 I'm using maven to define my projects. One of my dependencies requires a native DLL at runtime, and consequently it's needed in tests and for debugging. The native DLL is available at a known location. I want a solution that I can check in once and will work for all developers without manual setup by each dev. I know I can set the java.libary.path manually in "run configurations", which will allow it to find the native DLL, but this requires manual setup for each developer. I know I can also

Multiple directories in -Djava.library.path

笑着哭i 提交于 2019-12-06 16:36:54
问题 How can I point to two differents java.library.path in eclipse project - run configurations? I need these two libraries: -Djava.library.path=/opt/hdf-java/build/bin -Djava.library.path=/opt/opencv-2.4.10/build/lib Regards. 回答1: On Linux, use colon : as separator (as you will do with the classpath option) as in: -Djava.library.path=/opt/hdf-java/build/bin:/opt/opencv-2.4.10/build/lib 回答2: Use the platform's File.pathSeparator , i.e. ; on Windows and : on *nix, to separate directories, just

Exception in thread “main” java.lang.UnsatisfiedLinkError: no opencv_java249 in java.library.path

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-06 08:12:36
问题 I'm currently trying to set up OpenCV on my 32-bit laptop, but I keep getting an error message which is confusing me: Exception in thread "main" java.lang.UnsatisfiedLinkError: no opencv_java249 in java.library.path at java.lang.ClassLoader.loadLibrary(Unknown Source) at java.lang.Runtime.loadLibrary0(Unknown Source) at java.lang.System.loadLibrary(Unknown Source) at hello.main(hello.java:8) I've tried switching a few things around, like going into User Libraries and changing the Native

Exporting to Runnable jar with extra native code libraries in eclipse

非 Y 不嫁゛ 提交于 2019-12-05 21:11:58
问题 I am having trouble exporting my java project from eclipse as a jar executable file. My java project uses an external library (its called jri). I have exported the jri.jar file and set the library path for its native library in eclipse, and it works great in development in eclipse. However, when I export it as an executable jar file I get the following error: Cannot find JRI native library! Please make sure that the JRI native library is in a directory listed in java.library.path. I have

Where and when is the instance of PathClassLoader created in android source code?

一笑奈何 提交于 2019-12-05 20:41:22
When I was studying android source code, I noticed that the general class loader in app is an instance of PathClassLoader , and there is two constructors in this class. One is like: public PathClassLoader(String dexPath, ClassLoader parent) { super(dexPath, null, null, parent); } and the other is like: public PathClassLoader(String dexPath, String libraryPath, ClassLoader parent) { super(dexPath, null, libraryPath, parent); } But I cannot find the call of the second constructor in the source code during the procedure of app launching. So where does the value of libraryPath param come from? As