java-ee-6

Hi friends of StackOverflow, I do not understand how to roll back I read the documentation of Spring, but I still do not understand. Basically I'm going to persist an object in the db (with primary key manually) all the way here all right, the object is inserted into the db. But when you persist the object again with the same primary key I have caused an exception, and rightly so, a violation of restriction of uniqueness. In this case I would get a Transaction rollback and warn you that there was the problem and continue running the program This is my class: public class ServiceDaoImpl{

I am working on spring hibernate with jpa specification when my web application try to connect to database it gives the above exception Caused by: java.sql.SQLException: Access denied for user 'sandip'@'localhost' (using password: YES) , sandip is my linux user. data source set is like....... @Bean public DataSource getDataSource() { DriverManagerDataSource ds = new DriverManagerDataSource( env.getProperty("url")); ds.setDriverClassName(env.getProperty("driver")); ds.setUsername(env.getProperty("user")); ds.setPassword(env.getProperty("pass")); // Set up JPA and transactionManager @Bean public

I'm using JSF 2.0 this is my faces-config.xml <?xml version="1.0" encoding="UTF-8"?> <!-- This file is not required if you don't need any extra configuration. --> <faces-config version="2.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation=" http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-facesconfig_2_0.xsd"> <navigation-rule> <from-view-id>/pages/test/test.html</from-view-id> <navigation-case> <from-outcome>write</from-outcome> <to-view-id>/pages/test/test-write.html</to-view-id> </navigation-case> <

I am using a JEE6 stack including JPA 2.0, JSF 2.0, EJB 3.1 etc. The way my architecture is setup is the following: I have JPA annotated DAOs using hibernate as my JPA provider. I have JSF Managed beans which correspond to my facelet/xhtml pages. I have EJBs that handle all of my database requests. My XHTML pages have JSF EL which make calls to my Managed beans. My managed beans contain references to my DAO entities which are managed by EJBs. For example, I have a user entity which is mapped to a db table. I have a user EJB which handles all CRUD operations that return Users. I have a page

I have a login.java servlet and, as its name says, it provides login facilities to my web application. I'm a newbie and I'm using EJB 3.1 and EE 6. In my LoginBean.java EBJ I have a no-arguments constructor and another one that has some parameters (email, password, etc). At certain point in the servlet code I have the calling to instantiate my EJB: @EJB LoginBean loginBean; I'd like to know if it's possible (and how) to call the other constructor instead of the zero-arguments one. Thanks a lot. Cheers. You don't want to do that. The one and same servlet is shared among all users, so the EJB is

I am new to JPA 2.0/EclipseLink/Glassfish/JEE6, and have kind of a basic question. I have a DAO in which most of the entities are mapped directly to columns using JPA annotations, so I use the EntityManager, and it works great with no issues. However there are some tables in which I am constructing the SQL statements myself b/c they use oracle-specific functions (spatial), and I want very fine-grained control of the SQL. So I am building it with string concatenation. I would like to be able to enroll my SQL executions in the current transaction, if there is one already underway. So naturally I