java-8

Lambda expressions and Java 1.8 in IdeaUIDesigner

安稳与你 提交于 2019-12-30 03:09:12
问题 I'm trying to use Java 1.8 with lambda expressions with Idea UI Designer , I have in maven: <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>ideauidesigner-maven-plugin</artifactId> <executions> <execution> <goals> <goal>javac2</goal> </goals> </execution> </executions> <configuration> <fork>true</fork> <debug>true</debug> <failOnError>true</failOnError> </configuration> </plugin> and dependency <dependency> <groupId>com.intellij</groupId> <artifactId>forms_rt</artifactId> <version>7

Virtual Extension Methods in upcoming Java 8 release

牧云@^-^@ 提交于 2019-12-30 03:05:21
问题 When I see code snippets like interface A { void a(); void b() default { System.out.println("b"); }; void c() final { System.out.println("c"); }; } I have one question. Haven't we already got enough sh*t in Java? Why one might need this? 回答1: I suggest you to look at this conference : http://medianetwork.oracle.com/media/show/16999 This explain everything. The most interesting thing to do is to allow an interface to evolve without rewritting your whole codebase. This is key to allow a big

Any way to stream a map like “(k,v)” instead of working with (entry)?

99封情书 提交于 2019-12-30 03:05:11
问题 Basically I look for a way to avoid working with entry -> entry.getValue and entry -> entry.getKey similar to what Map.forEach() does. If only I could get a way to work as map.stream().filter((k,v) -> ) ... and so on It seems the interface is called BiConsumer. Perhaps with a converter to BiConsumer or a Stream.generate() someway 回答1: Since this is a repeating question, I will throw a full solution into the ring. It’s a PairStream type that is by default a simple wrapper around an ordinary

java 8 lambda expression for FilenameFilter

梦想的初衷 提交于 2019-12-30 02:53:04
问题 I am going through the lambda expression in java 8 when i changed the code of thread it's working fine new Thread(new Runnable() { @Override public void run() { System.out.println("run"); } }).start(); is converted to lambda expression as new Thread( () -> System.out.println("Hello from thread") ).start(); But i am not able to convert the FilenameFilter Expression File file = new File("/home/text/xyz.txt"); file.list(new FilenameFilter() { @Override public boolean accept(File dir, String name

Java Collectors.groupingBy()---is List ordered?

China☆狼群 提交于 2019-12-30 02:45:29
问题 For the Collectors.groupingBy() that returns Map<K,List<T>> is it implied that the List<T> is in order that the stream is evaluated? I see no explicit description of the ordering of the list, whereas the concurrent version explicitly states no ordering. If it weren't ordered somehow, I'd expect it to be a Collection though, and I don't see what other ordering it could possibly be, other than order received. I'm hoping it's guaranteed that the last value in each list is the last value received

Cumulative Sum using Java 8 stream API

做~自己de王妃 提交于 2019-12-30 02:07:54
问题 I have a List of Integer say list1, and I want to get another list list2 which will contain the cumulative sum up until the current index from start. How can I do this using Stream API java 8 ? List<Integer> list1 = new ArrayList<>(); list1.addAll(Arrays.asList(1, 2, 3, 4)); List<Integer> list2 = new ArrayList<>(); // initialization list2.add(list1.get(0)); for(int i=1;i<list1.size();i++) { // increment step list2.add(list2.get(i-1) + list1.get(i)); } How can I change above imperative style

Merge Map<String, List<String> Java 8 Stream

独自空忆成欢 提交于 2019-12-30 01:07:08
问题 I would like to merge two Map with JAVA 8 Stream: Map<String, List<String>> mapGlobal = new HashMap<String, List<String>>(); Map<String, List<String>> mapAdded = new HashMap<String, List<String>>(); I try to use this implementation: mapGlobal = Stream.of(mapGlobal, mapAdded) .flatMap(m -> m.entrySet().stream()) .collect(Collectors.groupingBy(Map.Entry::getKey, Collectors.mapping(Map.Entry::getValue, Collectors.toList()) )); However, this implementation only create a result like: Map<String,

In java, What does such enum type compile to?

流过昼夜 提交于 2019-12-30 00:33:05
问题 Below is the code that defines enum type. enum Company{ EBAY(30), PAYPAL(10), GOOGLE(15), YAHOO(20), ATT(25); private int value; private Company(int value){ super(this.name()); this.value = value; } public int getValue(){ return value; } } that gets internally compiled to, final class Company extends Enum<Company>{ public final static Company EBAY = new Company(30); public final static Company PAYPAL = new Company(10); public final static Company GOOGLE = new Company(15); public final static

Has anybody yet backported Lambda Expressions to Java 7?

我的未来我决定 提交于 2019-12-29 18:19:00
问题 Reading about what kind of bytecode Java 8 produces from lambdas, it came to my mind the time when Java 5 was released. Back then there was Retroweaver and other tools for converting bytecode compiled with JDK 5 to run on JRE 1.4. Has anybody yet created such a backporting tool for Java 8 lambdas? It would let Java developers start using lambdas already today on production-quality Java 7 JREs, without having to wait 6-12 months for Java 8's GA release. Here is my analysis of why such as

Has anybody yet backported Lambda Expressions to Java 7?

安稳与你 提交于 2019-12-29 18:18:56
问题 Reading about what kind of bytecode Java 8 produces from lambdas, it came to my mind the time when Java 5 was released. Back then there was Retroweaver and other tools for converting bytecode compiled with JDK 5 to run on JRE 1.4. Has anybody yet created such a backporting tool for Java 8 lambdas? It would let Java developers start using lambdas already today on production-quality Java 7 JREs, without having to wait 6-12 months for Java 8's GA release. Here is my analysis of why such as