jackson

来源： https://stackoverflow.com/questions/37882478/serializationfeature-wrap-root-value-as-annotation-in-jackson-json

来源： https://stackoverflow.com/questions/43825908/org-apache-catalina-connector-clientabortexception-java-io-ioexception-apr-err

来源： https://stackoverflow.com/questions/48579978/mapping-a-flat-map-to-a-nested-pojo-in-jackson

来源： https://stackoverflow.com/questions/53163648/jackson-yaml-serialize-null-as-empty-value

来源： https://stackoverflow.com/questions/53163648/jackson-yaml-serialize-null-as-empty-value

问题 I am using Jackson in Spring to serialize my class to JSON. When I serialize a class like the example below, Jackson is changing the names of certain fields from Camel Case to lower case. I know I can work around this by creating custom (de)serializers, yet I am hoping to turn this off globally. Perhaps by setting a property in application.properties. Per the default Jackson naming strategy, this is not supposed to happen: In absence of a registered custom strategy, default Java property

问题 JSON Request: { "notificationType" : "ISSUER_OTP1ee2asasa", "content" : "hi fff this is fff template content for SBI email good and mobile dfdfdfd and remaining balance is 333 and your name is hahaha.", "medium" : "EMAIL", "asa":"ddddd", "":"" } POJO: package com.innoviti.notification.model; import org.springframework.data.annotation.Id; import org.springframework.data.mongodb.core.mapping.Document; import com.fasterxml.jackson.annotation.JsonCreator; import com.fasterxml.jackson.annotation

问题 I have this code: static String createRequestJson(String apiKey, String apiSecret) { JsonNodeFactory factory = JsonNodeFactory.instance; ObjectNode root = factory.objectNode(); root.set("auth", factory.objectNode() .put("api_key", apiKey) .put("api_secret", apiSecret)); root.put("wait", true); return root.toString(); } It works, but the code looks more complicated than necessary. In particular, I’d like to get rid of the root variable. static String createRequestJson(String apiKey, String

问题 I got this error from volley library @Override public void onErrorResponse(VolleyError error) { error.printStackTrace(); } the error com.android.volley.ParseError: org.json.JSONException: Value [{"id":"admin","name":"Admin"}] of type org.json.JSONArray cannot be converted to JSONObject How can I receive the result as string and then I will process it using jackson ? 回答1: If you want to receive the result as a string don't use the JSONRequest. Go with the simple Request class. Your problem is

问题 we are developing a JSON web service to receive data via the @RequestBody annotation. In case a property is included in the request that does not match with the deserialized bean, we expect an HTTP 400 (Bad request) response, but instead the property is simply ignored. Here is an example: @RestController @Slf4j public class TestController { @RequestMapping(method = RequestMethod.POST, value = "/query") public void parse(@RequestBody Query query) { log.info("Received query: {}", query.toString