ipython

问题 When I updated my Python version from 3.4 to 3.5 (on Mac El Capitan), I reinstalled Jupyter but when I run it and create a new Python 3 notebook, it immediately tells me that there has been a kernel error and if I click on this, then I get this error message: Traceback (most recent call last): File "/usr/local/lib/python3.5/site-packages/notebook/base/handlers.py", line 436, in wrapper result = yield gen.maybe_future(method(self, *args, **kwargs)) File "/usr/local/lib/python3.5/site-packages

问题 I wish to use anaconda distribution of ipython, but typing ipython at the terminal produces an error message: Traceback (most recent call last): File "/usr/local/bin/ipython", line 5, in <module> from pkg_resources import load_entry_point File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/pkg_resources.py", line 2603, in <module> working_set.require(__requires__) File "/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/pkg_resources.py",

问题 I'm having trouble getting the if __name == '__main__' trick to work in an IPython, Spyder environment. I've tried every approach given in this thread: if __name__ == '__main__' in IPython Here are my super simplified modules Module1.py Class UnitTest(): print 'Mod1 UnitTest!' if __name__ == '__main__': UnitTest() Module2.py import Module1 Class UnitTest(): print 'Mod2 UnitTest!' if __name__ == '__main__': UnitTest() So I run Module2.py and I always am seeing both Mod2 UnitTest and Mod1

问题 Recently I discovered IPython notebook which is a powerful tool. As an IT student, I was looking for a way to represent graphs in Python. For example, I would like to know if there's a library (like numpy or matplotlib ?) which can draw from this { "1" : ["3", "2"], "2" : ["4"], "3" : ["6"], "4" : ["6"], "5" : ["7", "8"], "6" : [], "7" : [], "8" : [] } something like this : Is there something like this ? 回答1: You can use networkx and, if you need to render the graph in ipython notebook, nxpd

问题 After I installed PyReadline, IPython won't work. When I uninstalled it, it starts working again. The stack trace for ipython: (py2.7_monitor)[root@vm10-136-8-98 monitor]# ipython WARNING: IPython History requires SQLite, your history will not be saved Traceback (most recent call last): File "/home/py2.7_monitor/bin/ipython", line 11, in <module> sys.exit(start_ipython()) File "/home/py2.7_monitor/lib/python2.7/site-packages/IPython/__init__.py", line 118, in start_ipython return launch_new

问题 I keep getting the same result when trying to push to git: Counting objects: 78, done. Delta compression using up to 4 threads. Compressing objects: 100% (67/67), done. Writing objects: 100% (71/71), 36.29 MiB | 637.00 KiB/s, done. Total 71 (delta 39), reused 0 (delta 0) remote: error: GH001: Large files detected. remote: error: Trace: 7e446266168df8617c74b6a319ec4538 remote: error: See http://git.io/iEPt8g for more information. remote: error: File lecture_2_github_io_numpy_pandas/data

问题 I am currently using Jupyter notebook and I would like to force it to print out Python logs to the output cell. I am using old notebook that used to work this way, probably in older version of Jupyter notebook. I have logging set as: import logging logging.basicConfig(format='%(levelname)s : %(message)s', level=logging.INFO) logging.root.level = 20 But when I then call: logging.info("hello world") It does not print anything in the output cell. It just prints out the stuff in the console in

问题 I have PyCharm Professional Edition 3.5 5.0 configured to use IPython when possible and in my Run/Debug Configurations I set show interpreter afterwards I use the interactive Interpreter a lot and I really like IPython, but there are some things that I don't like about the way this is handled in PyCharm: any input() in my programs return empty strings. Additionally, when an error occurs I can't interact with the Program anymore. (you can when you run a Python program with the -i flag) There

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 2 years ago . Let's say that I have a function which creates a pd.DataFrame according to some variable 'name': def function(name): ... ... ... return(DataFrame(name)) #parenthesis #here only to show that the DataFrame will be #different when a different name is given as input. My question is:

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago . In the image shown, how can i split 'Date' column into 'Date' and 'Time' column? ' 回答1: You can use str.split by whitespace what is default separator: df = pd.DataFrame({'Date':['4/1/2016 0.00','4/2/2016 0.05']}) print (df) Date 0 4/1/2016 0.00 1 4/2/2016 0.05 df[['Date','Time']] = df.Date.str