ipv6

问题 I've just submitted my app to Appstore and got this error: At WWDC 2015 we announced the transition to IPv6-only network services in iOS 9. Starting June 1, 2016 all apps submitted to the App Store must support IPv6-only networking. Most apps will not require any changes because IPv6 is already supported by NSURLSession and CFNetwork APIs. If your app uses IPv4-specific APIs or hard-coded IP addresses, you will need to make some changes. Learn how to ensure compatibility by reading Supporting

问题 I don't know java but as you can see from this question ( Oracle Regular Expression (REGEXP_LIKE) Too Long Error - ORA-12733 ) java seems to be the easiest to accomplish validating if an IPv6 address is formatted correctly. I tried regular expressions, came close, but was a nightmare, and the expression is too long for PL/SQL. I have the java in Oracle way working. I only want to validate the format, not that the address really exists. So does java.net.Inet6Address.getByName literally go out

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . Sorry for my poor title. Here is my situation： Our lab has a centos server which has an local ipv4 addr 10.x.x.x and an public ipv6 addr. I also have a ramnode server which has a public ipv4 addr and a public ipv6 addr. And I only get an ipv4 addr at home, the question is how can I access the centos server using

问题 My app was rejected today due to 'not supporting IPv6'. I've attached screenshots of the error they received which comes from a Parse.com API call. I could really use some help on this, as I have no clue where to start with this. Does anyone know if Parse.com supports IPv6? Or do I need to add something to my code? Do I need to migrate to Parse Server? Please help =\ ---- EDIT ---- 9/22/16 OK so, after my first rejection due to "IPv6" issues, I re-submitted and the app was approved. I'd still

问题 I'm using PHP version 5.2.17, and I see that the following works as expected: $x = inet_pton('::F'); $y = inet_ntop($x); print "::F -> $y\n"; Output: ::F -> ::f But the following does not: $a = inet_pton('::FEEF:1886'); $b = inet_ntop($a); print "::FEEF:1886 -> $b\n"; Output: ::FEEF:1886 -> ::254.239.24.134 I would have expected the second code snippet to produce this output: ::FEEF:1886 -> ::feef:1886 What is it about the IPv6 address ::FEEF:1886 that makes PHP think it is really an IPv4

问题 This application publishes its own address for other systems to connect to using .net remoting. It gets all the addresses of the computer with something like: IPAddress[] IPList = Dns.GetHostEntry(Environment.MachineName).AddressList; string ipAddress = IPList[ipIndex].ToString(); if(ipAddress.contains(":")) { // ip6 address url = "tcp://[" + ipAddress + "]:" + port + "/" + name; } else { url = "tcp://" + ipAddress + ":" + port + "/" + name; } I added the square brackets in case it was

问题 When using Dns.GetHostAddresses("fred") it returns only IPv4 addresses in response. How to get the IPv6 addresses as well? Is there different method I shall use? Socket.OSSupportsIPv6 returns true and IPv6 connections work fine. The OS is Windows 2008 R2, .Net version is 3.5. 回答1: IPv6 still uses DNS to resolve addresses so in order for this to work you will need to add an IPv6 entry to your zone file for this domain name. It'll then resolve properly. I suspect that Ping will fall back to

问题 Following the advice given here, I'm using the check the ipaddress module to perform checks of type: In [25]: IPv4Address(u'100.64.1.1') in IPv4Network(u'100.64.0.0/10') Out[25]: True Works fine in IPython. Yet when I turn it into a function: import ipaddress def isPrivateIp(ip): ip4addressBlocks = [u'0.0.0.0/8', u'10.0.0.0/8', u'100.64.0.0/10', u'127.0.0.0/8', u'169.254.0.0/16', u'172.16.0.0/12', u'192.0.0.0/24', u'192.0.2.0/24', u'192.88.99.0/24', u'192.168.0.0/16', u'198.18.0.0/15', u'198

问题 i can trying to use GetAddrInfo to resolve ipv6.google.com: wsaError = getaddrinfo("ipv6.google.com", null, null, ref addrInfo); The returned socket error code is 11001 (No such host is known). Note : The deprecated legacy function GetHostByName does not support IPv6. It has been replaced with GetAddrInfo. The strange thing is that i can use nslookup and it can find the address just fine: Question SendRequest(), len 33 HEADER: opcode = QUERY, id = 4, rcode = NOERROR header flags: query, want

问题 As IPV6 address has 16 bytes and their is no data type to store it in c++, i wanted to store the IPV6 address, and do some comparisions between to IPv6 address, please let me know how to do it 回答1: You can store those as plain arrays of unsigned char s as you would do in C. Like unsigned char ipv6[16]; for example. You could then compare them using any array comparison algorithm out there. Using char* algorithms wouldn't be an option as some bytes of your ipv6 addresses could be 0x00 and thus