ios-simulator

Possible Duplicate: How can I develop for iPhone using a Windows development machine? Can anybody shortly describe solutions to start develop for iPhone on PC? You do not need necessarily a Mac. It depends on your requirements for the application. What you can always do is creating a web application for the iPhone. Here is a nice tutorial with Aptana (Eclipse based IDE for web development). Aptana seems to have some kind of iPhone simulator integrated. There are various toolkits available, e.g. iui and jQTouch , to simulate the Look&Feel of iPhone apps. Get a Mac or run OSX server under VMWare

This question already has an answer here: How to resize the iPhone/iPad Simulator? 11 answers I am working on a Philips 19" and upgraded Xcode to version 4.3.2. On the new "Retina Display" on iPad 3 (oh, sorry, on The New iPad) my iPad simulator changes it's resolution and the simulator has vertical and horizontal scroll bars! How do I change the resolution of the an iOS simulator? The following hotkeys should be helpful: Command ⌘ + 1 (100%) Command ⌘ + 2 (75%) Command ⌘ + 3 (50%) Command ⌘ + 4 (33%) Command ⌘ + 5 (25%) Look at menu: "Window --> Scale" to see the options. You can enable the

Today morning I build and run my xcode project. When simulator launched I saw this: The screen is scaled , I see only 1/4 part, other 3/4 parts are hidden . Did anybody faced with same problem? The issue happens in xCode6, Xcode5 , also in AppCode . I tried to Clean project, switched to iPhone5 screen , iPad , the same problem. Also, this happens with my other iOS projects. Finally, I got the reason why this bug appears at work and not at home :) Because at work I don't have external display ( monitor ), but at home (DELL, non-retina off course) If you want this bug not to appear, just connect

I was following one of Ray Wenderlich's tutorials on localization but I can't seem to get it working. I've set my project up for localization in English and French and I have a locaziable.strings file for each: The French file has the correct (well as far as Google translate goes) French versions of my string: I'm setting the strings by calling the correct key from the localizable.strings file: NSString* strTitle = [NSString stringWithFormat:NSLocalizedString(@"Title", Nil)]; And I have the simulator set to French (BTW: Whenever I do a language change the simulator crashes). But it is not

I'm getting an warning as 'SpringBoard failed to launch application with error: -3'. This happens when trying to run application in Xcode 5. Jayprakash Dubey Finally...found solution! Solution 1 : Just quit Simulator and clean Xcode. The fresh build will not show this Alert again. The possible reason for this might be switching between 64-bit simulator and 32-bit simulator. Solution 2 : If the problem still persists then delete the App from Simulator and re-run the code. This will work since the app contents are freshly loaded. Springboard (also known as Home Screen) is the standard

class ViewController: UIViewController { override func viewDidLoad() { super.viewDidLoad() var timer = NSTimer.scheduledTimerWithTimeInterval(1, target: self, selector: Selector("update"), userInfo: nil, repeats: true) } func update() { println("Something cool") } } It's ok for the Simulator ，I will get continuous "Something cool" through I tapped the home button. But it worked out when I debug the app with my iPhone. I did't get anything when I tapped the home button and make my app run background. Someone told me I can play a long blank music to make my App run in the background.But I don't

There were many articles written and questions asked about iPhone 6 and iPhone 6 Plus screen sizes. This article provides a great explanation. However, I am confused when testing my app in the simulator. I have the following code in AppDelegate . - (BOOL) application: (UIApplication *) application didFinishLaunchingWithOptions: (NSDictionary *) launchOptions { UIScreen *screen = [UIScreen mainScreen]; NSLog(@"Screen width %.0f px, height %.0f px, scale %.1fx", (double) screen.bounds.size.width, (double) screen.bounds.size.height, (double) screen.scale); return YES; } I get the following