introspection

Suppose myapp/foo.py contains: def info(msg): caller_name = ???? print '[%s] %s' % (caller_name, msg) And myapp/bar.py contains: import foo foo.info('Hello') # => [myapp.bar] Hello I want caller_name to be set to the __name__ attribute of the calling functions' module (which is 'myapp.foo') in this case. How can this be done? ars Check out the inspect module: inspect.stack() will return the stack information. Inside a function, inspect.stack()[1] will return your caller's stack. From there, you can get more information about the caller's function name, module, etc. See the docs for details:

Is there any way to get the name of an object in Python? For instance: my_list = [x, y, z] # x, y, z have been previously defined for bla in my_list: print "handling object ", name(bla) # <--- what would go instead of `name`? # do something to bla Edit: Some context: What I'm actually doing is creating a list of functions that I can specify by the command line. I have: def fun1: pass def fun2 pass def fun3: pass fun_dict = {'fun1': fun1, 'fun2': fun2, 'fun3': fun3} I get the name of the function from the commandline and I want to call the relevant function: func_name = parse_commandline() fun

Is there a straightforward way to find all the modules that are part of a python package? I've found this old discussion , which is not really conclusive, but I'd love to have a definite answer before I roll out my own solution based on os.listdir(). Yes, you want something based on pkgutil or similar -- this way you can treat all packages alike regardless if they are in eggs or zips or so (where os.listdir won't help). import pkgutil # this is the package we are inspecting -- for example 'email' from stdlib import email package = email for importer, modname, ispkg in pkgutil.iter_modules

I have a dict, which I need to pass key/values as keyword arguments.. For example.. d_args = {'kw1': 'value1', 'kw2': 'value2'} example(**d_args) This works fine, but if there are values in the d_args dict that are not accepted by the example function, it obviously dies.. Say, if the example function is defined as def example(kw2): This is a problem since I don't control either the generation of the d_args , or the example function.. They both come from external modules, and example only accepts some of the keyword-arguments from the dict.. Ideally I would just do parsed_kwargs = feedparser

Given a Django model, I'm trying to list all of its fields. I've seen some examples of doing this using the _meta model attribute, but doesn't the underscore in front of meta indicate that the _meta attribute is a private attribute and shouldn't be accessed directly? ... Because, for example, the layout of _meta could change in the future and not be a stable API? Is _meta an exception to this rule? Is it stable and ready to use or is it considered bad practice to access it? Or is there a function or some other way to introspect the fields of a model without using the _meta attribute? Below is

I am trying to dynamically create a class instance based type using generics, however I am encountering difficulty with class introspection. Here are the questions: Is there a Swift-equivalent to Obj-C's self.class ? Is there a way to instantiate a class using the AnyClass result from NSClassFromString ? Is there a way to get AnyClass or otherwise type information strictly from a generic parameter T ? (Similar to C#'s typeof(T) syntax) Jiaaro Well, for one, the Swift equivalent of [NSString class] is .self (see Metatype docs , though they're pretty thin). In fact, NSString.class doesn't even