intervals

Subtract months from current date sql

北城以北 提交于 2021-02-17 05:22:05
问题 I am trying to substract dates from today (Get a 1 month ago till forever report). So far I've tried DATE_SUB(NOW(), INTERVAL 1 MONTH) Here is the context: SELECT contracts.currency , ROUND(SUM( CASE WHEN contracts.currency = 'USD' THEN contracts.value*550 WHEN contracts.currency = 'UF' THEN contracts.value*22000 ELSE contracts.value END),2) AS real_value FROM contracts WHERE currency IN ('USD','UF','CLP') AND date >=DATE_SUB(NOW(), INTERVAL 1 MONTH) GROUP BY currency ORDER BY currency ASC

Subtract months from current date sql

浪子不回头ぞ 提交于 2021-02-17 05:21:12
问题 I am trying to substract dates from today (Get a 1 month ago till forever report). So far I've tried DATE_SUB(NOW(), INTERVAL 1 MONTH) Here is the context: SELECT contracts.currency , ROUND(SUM( CASE WHEN contracts.currency = 'USD' THEN contracts.value*550 WHEN contracts.currency = 'UF' THEN contracts.value*22000 ELSE contracts.value END),2) AS real_value FROM contracts WHERE currency IN ('USD','UF','CLP') AND date >=DATE_SUB(NOW(), INTERVAL 1 MONTH) GROUP BY currency ORDER BY currency ASC

With `pandas.cut()`, how do I get integer bins and avoid getting a negative lowest bound?

旧巷老猫 提交于 2021-02-07 05:35:06
问题 My dataframe has zero as the lowest value. I am trying to use the precision and include_lowest parameters of pandas.cut() , but I can't get the intervals consist of integers rather than floats with one decimal. I can also not get the left most interval to stop at zero. import pandas as pd import seaborn as sns import matplotlib.pyplot as plt sns.set(style='white', font_scale=1.3) df = pd.DataFrame(range(0,389,8)[:-1], columns=['value']) df['binned_df_pd'] = pd.cut(df.value, bins=7, precision

What does x += x & -x mean?

谁都会走 提交于 2021-02-07 03:28:38
问题 I found that many people use x += x & -x , x -= x & -x to solve the interval tree problem. Can you explain what that equation means? void update(int m, int x) { m++; while (m < N) { t[m] = t[m] + x; m += m & -m; } } int query(int m) { int result= 0; m++; while (m > 0) { result = result + t[m]; m -= m & -m; } return result; } 回答1: Note: This answer (like the method itself) assumes signed integers are represented in two's complement form. The expression x & -x is a quick - but admittedly arcane

return empty rows for not existsting data

陌路散爱 提交于 2021-02-04 20:43:50
问题 Ok, i have a table with a date column and a integer column, and i want to retrieve all the rows grouped by date's day within a certain date range; since there are not rows for every day, is it possible to make mysql return rows for those days with a default value? example source table: date value 2020-01-01 1 2020-01-01 2 2020-01-03 2 2020-01-07 3 2020-01-08 4 2020-01-08 1 Standard behaviour after group ing by date and sum ming values: 2020-01-01 3 2020-01-03 2 2020-01-07 3 2020-01-08 5

Plot date and time interval and duration

ⅰ亾dé卋堺 提交于 2021-01-29 09:26:08
问题 I have a list of date+time start and stop that I would like to plot as bars. The X-axis should go from 00:00-23:59 with date on the Y-axis I tried plotting in gnuplot , but my skills are not good enough. The data is in the following format: Date Start Stop 06.03.2019 09:45 11:17 06.03.2019 14:40 15:20 07.03.2019 08:35 10:15 07.03.2019 14:05 14:45 08.03.2019 09:15 10:20 08.03.2019 13:55 14:45 09.03.2019 08:55 09:50 09.03.2019 13:15 14:36 10.03.2019 09:05 10:00 I would like to get a plot

How to get 30 min interval in time picker in Android N

淺唱寂寞╮ 提交于 2020-12-26 05:14:48
问题 I want to get 30 min interval from time picker dialog and below code works proper below Android N but not working in latest device. Below is my code for activity . public class MainActivity extends AppCompatActivity { private TextView tvSelectedTime; private Button btnOpentimePickerDialog; private int intHour, intMinute; private String strMin = ""; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); getIds(

How to get 30 min interval in time picker in Android N

瘦欲@ 提交于 2020-12-26 05:14:36
问题 I want to get 30 min interval from time picker dialog and below code works proper below Android N but not working in latest device. Below is my code for activity . public class MainActivity extends AppCompatActivity { private TextView tvSelectedTime; private Button btnOpentimePickerDialog; private int intHour, intMinute; private String strMin = ""; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); getIds(

Extract left and right limit from a Series of pandas Intervals

强颜欢笑 提交于 2020-12-25 00:58:21
问题 I want to get interval margins of a column with pandas intervals and write them in columns 'left', 'right'. Iterrows does not work (documentation says it would not be use for writing data) and, anyway it would not be the better solution. import pandas as pd i1 = pd.Interval(left=85, right=94) i2 = pd.Interval(left=95, right=104) i3 = pd.Interval(left=105, right=114) i4 = pd.Interval(left=115, right=124) i5 = pd.Interval(left=125, right=134) i6 = pd.Interval(left=135, right=144) i7 = pd

Extract left and right limit from a Series of pandas Intervals

…衆ロ難τιáo~ 提交于 2020-12-25 00:54:43
问题 I want to get interval margins of a column with pandas intervals and write them in columns 'left', 'right'. Iterrows does not work (documentation says it would not be use for writing data) and, anyway it would not be the better solution. import pandas as pd i1 = pd.Interval(left=85, right=94) i2 = pd.Interval(left=95, right=104) i3 = pd.Interval(left=105, right=114) i4 = pd.Interval(left=115, right=124) i5 = pd.Interval(left=125, right=134) i6 = pd.Interval(left=135, right=144) i7 = pd