interpolation

Generate colors between red and green for an input range [duplicate]

我们两清 提交于 2019-11-27 11:56:17
Possible Duplicate: Color coding based on number I want for a user to be able to select from a range from 1-100, where as the numbers become less than 50, the color of the area becomes darker green, and as the color becomes closer to 100, the color becomes more red. I am trying to make it so that as the range in more towards the center, the color should be close to white (where 50 = full white). I tried the answer from here: Generate colors between red and green for a power meter? to no avail.... 50 ends up being a muddled green... I have the following html: <span><span class="value">50</span>

Fast interpolation over 3D array

只谈情不闲聊 提交于 2019-11-27 11:47:07
问题 I have a 3D array that I need to interpolate over one axis (the last dimension). Let's say y.shape = (nx, ny, nz) , I want to interpolate in nz for every (nx, ny) . However, I want to interpolate for a different value in each [i, j] . Here's some code to exemplify. If I wanted to interpolate to a single value, say new_z , I'd use scipy.interpolate.interp1d like this # y is a 3D ndarray # x is a 1D ndarray with the abcissa values # new_z is a number f = scipy.interpolate.interp1d(x, y, axis=-1

How do you do bicubic (or other non-linear) interpolation of re-sampled audio data?

拥有回忆 提交于 2019-11-27 11:09:18
I'm writing some code that plays back WAV files at different speeds, so that the wave is either slower and lower-pitched, or faster and higher-pitched. I'm currently using simple linear interpolation, like so: int newlength = (int)Math.Round(rawdata.Length * lengthMultiplier); float[] output = new float[newlength]; for (int i = 0; i < newlength; i++) { float realPos = i / lengthMultiplier; int iLow = (int)realPos; int iHigh = iLow + 1; float remainder = realPos - (float)iLow; float lowval = 0; float highval = 0; if ((iLow >= 0) && (iLow < rawdata.Length)) { lowval = rawdata[iLow]; } if ((iHigh

Interpolate NaN values in a numpy array

寵の児 提交于 2019-11-27 10:36:35
Is there a quick way of replacing all NaN values in a numpy array with (say) the linearly interpolated values? For example, [1 1 1 nan nan 2 2 nan 0] would be converted into [1 1 1 1.3 1.6 2 2 1 0] eat Lets define first a simple helper function in order to make it more straightforward to handle indices and logical indices of NaNs : import numpy as np def nan_helper(y): """Helper to handle indices and logical indices of NaNs. Input: - y, 1d numpy array with possible NaNs Output: - nans, logical indices of NaNs - index, a function, with signature indices= index(logical_indices), to convert

Math - mapping numbers

China☆狼群 提交于 2019-11-27 10:11:18
How do I map numbers, linearly, between a and b to go between c and d. That is, I want numbers between 2 and 6 to map to numbers between 10 and 20... but I need the generalized case. My brain is fried. If your number X falls between A and B, and you would like Y to fall between C and D, you can apply the following linear transform: Y = (X-A)/(B-A) * (D-C) + C That should give you what you want, although your question is a little ambiguous, since you could also map the interval in the reverse direction. Just watch out for division by zero and you should be OK. Konrad Rudolph Divide to get the

Reverse complex 2D lookup table

爷,独闯天下 提交于 2019-11-27 09:22:15
I have some function which maps some input to the output . The output is a complex number. What I'm actually interested in is the inverse function . But since this inversion can't be done in a analytical way I need to do it with a numerical approximation. Since is computationally expensive my idea was to use a lookup table approach. I can generate a 2D lookup table with the dimensions (forward lookup table), but what I actually need is the inverse of this lookup table—yielding based on a given . For the inversion of the lookup table the simplest approach I can think of is using the entries of

Color Interpolation Between 3 Colors in .NET

南笙酒味 提交于 2019-11-27 09:07:45
I would like to smoothly interpolate color from Color A (let's call it red) to Color C (let's call it green) going through color B (let's call it yellow), based on the value of a certain variable. If the variable = 100, I want pure green. If the variable = 50, I want pure yellow. If the variable = 0, I want pure red. I understand you can treat each RGB triplet as a coordinate in 3-dimensional space. What I'm looking for is a quick-and-dirty linear interpolation trick that works cleanly with the specific layout of the .NET Color type (separate values for ARGB etc). jason First, you ask for

Matlab: Find a root of y-values given by a differential equation

冷暖自知 提交于 2019-11-27 08:31:52
问题 I've solved an initial value differential equation and plotted the Y values given by ODE45. From the plot I can vaguely tell where the root should be, but in the given task I need to find it with great accuracy. My first guess was to adjust a polynom to my X and Y values, and then solve the polynom equation. But I used polyfit and had 69 know values which gave me a polynom of the 68grade which I couldn't solve. So, does anyone know how I could find a "root" to a set of given Y values without

How to interpolate a 2D curve in Python

大城市里の小女人 提交于 2019-11-27 07:33:53
问题 I have a set of x & y coordinate which is a curve / shape, I want the smooth the curve / sharp and plot a graph. I tried different interpolation to smooth the curve / shape, But it still cannot fit my expectation. Using point to draw a smooth curve / shape. Like the following, using x, y point to get a smooth circle / curve However, I get something like circle.jpg curve.jpg square.jpg I also get trouble on spline interpolation, and rbf interpolation. for cubic_spline_interpolation, I got

Cubic spline interpolation vs polynomial interpolation

狂风中的少年 提交于 2019-11-27 07:28:24
问题 I am asked to investigate the different types of interpolation using Matlab for the following points: x = [32 34 35 36 37 38] y = [26 28 31 30 29 25] and find the values for f(33) , f(33.5) and f(35) . When plotting x and y, I can see that f(33) should be around 27, which is also what I get using interp1(x,y,33) . I am not sure if this is the correct way of using the Cubic spline interpolation function but I used spline(x,y,33) and got ans = 24.3906 . Shouldn't I still get the same value for