interpolation

Python - Problems contour plotting offset grid of data

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-12 05:48:04
问题 My data is regularly spaced, but not quite a grid - each row of points is slightly offset from the one below. The data is in the form of 3 1D arrays, x, y, z, with each index corresponding to a point. It is smoothly varying data - approximately Gaussian. The point density is quite high. What is the best way to plot this data? I tried meshgrid, but it gives me some bad contours through regions that have no data points near the contour's value. I have tried rbf interpolation according to this

Interpolating an irregular grid

♀尐吖头ヾ 提交于 2019-12-12 04:34:49
问题 I have a dataset with lat/lon and depth parameters, taken on an irregular grid. I'd like to plot an interpolated bathymetry map. I've seen several solutions for regular grids, but that just doesn't apply... Any suggestions would be appreciated. A 50-point subset of my data: df <- structure(list(Lat = c(49.33805, 49.33805, 49.33817, 49.33819, 49.33823, 49.33823, 49.33827, 49.33829, 49.33834, 49.33844, 49.33846, 49.33846, 49.33847, 49.33847, 49.33847, 49.33848, 49.33849, 49.33849, 49.33849, 49

Create a surface from “pre-gridded” points

女生的网名这么多〃 提交于 2019-12-12 04:23:42
问题 I have a large data.frame which has 3 variables Longitude , Latitude and Temp . The data is arranged so that it is regularly spaced on a "grid" of 1/4 degree - so that dput(head(dat)) gives: structure(list(Longitude = c(0.125, 0.375, 0.625, 0.875, 1.125, 1.375), Latitude = c(0.125, 0.125, 0.125, 0.125, 0.125, 0.125 ), Temp = c(25.2163, 25.1917, 25.1593, 25.125, 25.0908, 25.0612 )), .Names = c("Longitude", "Latitude", "Temp"), row.names = c(NA, 6L), class = "data.frame"). I am having problems

Leave-one-out cross validation for IDW in R

核能气质少年 提交于 2019-12-12 03:55:14
问题 I am trying to check the results of IDW interpolation by leave-one-out cross validation and then get the RMSE to see the quality of the prediction. From github Interpolation in R, I found some hints and apply it in my case as following: I have 63 locations which is saved as a SpatialPointDataFrame, named x_full_utm_2001 . For each location, there is attached precipitation data, named sumdata_2001 . idw.out<- vector(length = length(sumdata_2001$Jan)) for (i in 1:length(sumdata_2001$Jan)) { idw

Stylus Iteration + Interpolation with nth-of-type

笑着哭i 提交于 2019-12-12 02:41:49
问题 I'm attempting to use the counter provided when looping thru a list of items like so: colors = red blue orange green yellow li for color, i in colors &:nth-of-type({i}n) background-color: color This example does not work, but the intended output I'm looking for is: li:nth-of-type(1n) { background-color: red; } li:nth-of-type(2n) { background-color: blue; } li:nth-of-type(3n) { background-color: orange; } ... Is this possible? 回答1: Actually your example's output is almost correct. It starts

Interpolate the time stamped patient data

此生再无相见时 提交于 2019-12-12 02:04:38
问题 Question: I am dealing with a patient data, where parameters are recorded at different sampling frequency, so having a different time stamp. I want to create a matrix where data is interpolated by "Last known value" till the new original value changes in the time. So at the end I have uniform matrix where each parameter have values at every time stamp. Data is in following format: Time Hear Rate(Variable) 18:00:00 PM 74 18:02:00 PM 75 18:04:00 PM 85 18:06:00 PM 71 18:08:00 PM 79 18:10:00 PM

Good interpolation method for color mixing?

≡放荡痞女 提交于 2019-12-12 01:43:49
问题 This question addresses in particular the question of curve fitting in the context of color mixing of paints, pigments, etc. I am trying to guess the required proportions of two paints, let's say "Brown" (B) and "white" (W) to get to a given lightness value L. I have made a "calibration curve" in the same fashion as one does so for applying the Beer-lambert law in chemistry. However, the curve is not linear so I cannot use the Beer-Lambert law. Here's what I've done : (1) I have measured the

Programmatically interpolating among multiple column values in PostgreSQL

最后都变了- 提交于 2019-12-12 01:37:09
问题 I have a table in my PostgreSQL db containing data of number of vehicles sold from 1995 to 2015 (with a gap of 5 years) like this: ID. veh_1995 veh_2000 veh_2005 veh_2010 veh_2015 1 200 425 526 725 623 2 400 478 1000 1500 2000 3 150 300 400 700 1100 4 700 800 1000 2000 5000 5 900 1500 1600 2000 2500 I would like to progammatically interpolate the values for the missing years and for all IDs so that I have number of sold vehicles' records from 1995 to 2015. Could anyone suggest me how to do

Add another custom interpolator in Angularjs

不打扰是莪最后的温柔 提交于 2019-12-12 01:06:53
问题 I still want {{1+2}} to be evaluated as normal. But in addition to the normal interpolator, I want to create a custom one that I can program to do whatever I want. e.g. <p>[[welcome_message]]</p> should be a shortcut for <p>{{'welcome_message' | translate}}</p> , or <p translate="welcome_message"></p> . That way, i18n apps would be much more convenient to write. Is anything like that possible? I'm currently going through the angular.js source code, but the interpolation system looks pretty

Separating data into bins and calculating averages

三世轮回 提交于 2019-12-12 00:22:22
问题 I have this sample data Time(s) Bacteria count 0.4 2 0.82 5 6.67 8 7.55 11 8.21 14 8.89 17 9.4 20 10.18 23 10.85 26 11.35 29 11.85 32 12.41 35 13.36 38 13.86 41 14.57 44 15.08 47 15.67 50 16.09 53 16.59 56 18.53 59 24.43 62 25.32 65 25.97 68 26.37 71 26.93 74 27.87 77 28.33 80 29.1 83 29.88 84 30.88 85 31.99 86 35.65 87 36.06 88 36.46 89 36.96 90 37.39 91 37.95 92 38.56 93 39.22 94 39.79 95 40.56 96 41.47 97 42.02 98 42.73 99 43.4 100 43.93 101 44.67 102 45.24 103 45.9 104 46.58 105 47.22 106