interpolation

问题 Hi i am trying to plot a basic interpolation graph, interpolate data1 with data2 and SecondData1 with SecondData2.. But i not sure where i can put my first data set and second data set in. I been struck in this for almost a day.. import numpy as np import matplotlib.pyplot as plt # first data set data1 = [15000, 11000, 8000, 4000, +1000, +552, -708, -8000, -8, 10000, +15000] data2 = [30E-06, 13E-06, 2E-06, -179E-06, -7E-06, -19E-06, -30E-06, -10E-06, -1.9E-06, 30E-06, 30E-06] X1 = np.linspace

问题 I'm making a medical imaging equipment. I want to use CUDA for making faster equipment I receive 1024 size 1d data from CCD 512 times. before I perform IFFT I have to apply high performance interpolation algorithm (like cubic spline interpolation) to the 1024 size data each (then 1d interpolation 512 times). Is there any CUDA library to perform cubic spline interpolation? (I found that there is one library, but it is for 2 or 3 dimensional image. Since I need to perform other complicated

问题 I am using SQL Server 2012. I have the following query: SELECT p.PortfolioGroupID, p.PortfolioGroupCode, p.DisplayOrder, p.MemberCode, m.ContactCode, m.Custom01, 'Separator' As 'PDFType' FROM [APXFirm].[AdvApp].[vPortfolioGroupMemberFlattened] p LEFT OUTER JOIN [APXFirm].[AdvApp].[vPortfolioInterestedParty] m on p.memberid = m.PortfolioID WHERE m.ContactCode is not null and p.PortfolioGroupCode like '%_Package' order by m.ContactCode, p.MemberCode Current Result Set PortfolioGroupID

问题 I tried building a minimal example to reproduce a problem I was having. Please ignore the randomly generated data arrays x and y . I am feeding perfectly meaningful data into the zSpline call inside plot_surface . You could try replacing the penultimate line with - surf=ax.plot_surface(xg,yg,z,rstride=1,cstride=1,cmap=cm.coolwarm,linewidth=0.1) where I have replaced the ZSpline with the coarse data z . This works which indicates to me that I am not mistaken on syntax. My code is- import numpy

问题 I'm writing a function that slowly turns exactly 90 degreees over the course of a period of time. So far everything is working fine, I just need to figure out how to make it rotate around a point instead of rotation around the transforms center. protected bool _isRotating = false; public IEnumerator RotateWithEasing(GameHelper.Axis axis, Vector3 isolatedAxisPoint, float inTime) { if(_isRotating) { yield break; } _isRotating = true; var degrees = this.GetDegreesFromAxis(axis); Quaternion

问题 I have a df similar to this: print(df) A B C DATE_TIME 2016-10-08 13:57:00 in 5.61 0 2016-10-08 14:02:00 in 8.05 0 2016-10-08 14:07:00 out 7.92 0 2016-10-08 14:12:00 in 7.98 1 2016-10-08 14:17:00 out 8.18 0 2016-10-08 14:22:00 out 7.59 0 print (df.dtypes) A object B float64 C int64 dtype: object I want to resample this df to a 1S frecuency, so that I can concatenate it with another df . The problem I can't solve is that for the columns type object and int64 I want the same value repeated for

问题 A while ago I implemented a Polynom approximation for a game I programmed. I am using Newton's pyramide method. It took me quite a while to figure it out, but my solution requires to calculate the binomial coefficients and I also have to sum up all the coefficients for the final coefficient of each power (since solving this problem is similar to squaring, cubing.. terms and calculating the binomial coefficients) For example: pick k out of n of the bionomeal terms and add them one pick is

问题 <th :class="{'c-' + column, active: sortKey == column}" v-for="column in getColumns()" @click="sortBy(column)"> {{ column }} </th> I get invalid expression: Unexpected token + in but the syntax is supposed to be correct. I tried like 20 other ways and everyone fails Even if I put only column in there i get [Object object] instead of the actual column name so, this doesn't work at all inside es6 template syntax. It only works if I put the templates inside <script> tags in the index.html file

问题 I have some 2D sampling points for which I need the polynomial equation. I only found something like this: from scipy.interpolate import barycentric_interpolate // x and y are given as lists yi = barycentric_interpolate(x, y, xi) But in this case I can only get the y-values belonging to certain xi-values - that's not what I want. I need the equation (the parameter for the polynomial equation). How can I receive this? 回答1: numpy.polyfit Fit a polynomial p(x) = p[0] * x**deg + ... + p[deg] of

问题 What I want is to extend an array of length m to an array of length n (n>m) , and interpolate the missing values linearly. For example, I want to extend this array [1,5,1,7] to an array of length 7 , the result should be [1, 3 ,5, 3 ,1, 5 ,7], where the bold figures result from linear interpolation. Is there an easy way to do this in Python? Thanks in advance. 回答1: The interp function from numpy can do what you want. Example: >>> xp = [1, 2, 3] >>> fp = [3, 2, 0] >>> np.interp(2.5, xp, fp) 1