interface

login page and navigation bar

♀尐吖头ヾ 提交于 2020-02-02 13:18:43
问题 When first launching the apps, I want it to show a button to log in. After successfully logged in, I want the app to show a tab bar view.. So does this mean that I need to set my app delegate to point to the UITabBarController? How can I do this? 回答1: I load my UITabBarController in the app delegate, so before adding the login screen the last bit of the applicationDidFinishLaunchingWithOptions looks like this: [window addSubview:tabcontroller.view]; [window makeKeyAndVisible]; To add a view

login page and navigation bar

生来就可爱ヽ(ⅴ<●) 提交于 2020-02-02 13:18:05
问题 When first launching the apps, I want it to show a button to log in. After successfully logged in, I want the app to show a tab bar view.. So does this mean that I need to set my app delegate to point to the UITabBarController? How can I do this? 回答1: I load my UITabBarController in the app delegate, so before adding the login screen the last bit of the applicationDidFinishLaunchingWithOptions looks like this: [window addSubview:tabcontroller.view]; [window makeKeyAndVisible]; To add a view

Delphi: Calling a function from a vc++ dll that exports a interface / class

跟風遠走 提交于 2020-02-02 12:52:18
问题 i have some trouble accessing a dll written in vc++ that exports an interface. First i tried to use classes, but after some google-search i came to the solution, that this i not possible. I just want to make sure, that the plugin interface can accessed, by using other languages like c++. Delphi Interface IPlugIn = interface function GetName: WideString; stdcall; end; Delphi Plugin call procedure TForm1.Button5Click(Sender: TObject); var hLib: Cardinal; MLoadPlugIn: TLoadPlugIn; PlugIn:

Is it possible to use typescript mapped types to make a type of non-function properties of an interface?

感情迁移 提交于 2020-02-02 11:59:27
问题 so I was looking at Typescript's mapped types. Would it be possible to create an interface that wraps another type that removes functions from the original type? For example: interface Person{ name: string, age: number, speak(): void, } type Data<T> = ? const dataPerson: Data<Person> ={ name: "John", age: 20 //Speak removed because it is a function }; Thanks! 回答1: This is from the typescript documentation (https://www.typescriptlang.org/docs/handbook/advanced-types.html#conditional-types) and

Is it possible to use typescript mapped types to make a type of non-function properties of an interface?

走远了吗. 提交于 2020-02-02 11:58:07
问题 so I was looking at Typescript's mapped types. Would it be possible to create an interface that wraps another type that removes functions from the original type? For example: interface Person{ name: string, age: number, speak(): void, } type Data<T> = ? const dataPerson: Data<Person> ={ name: "John", age: 20 //Speak removed because it is a function }; Thanks! 回答1: This is from the typescript documentation (https://www.typescriptlang.org/docs/handbook/advanced-types.html#conditional-types) and

Invoke a function which is received as an interface variable in golang

六月ゝ 毕业季﹏ 提交于 2020-02-01 03:17:06
问题 I have a code which is similar to the following package main import "fmt" func PrintThis(arg string) { fmt.Printf("I'm printing %s", arg) } func PrintThisAndThat(arg1, arg2 string) { fmt.Printf("Now printing %s and %s", arg1, arg2) } func Invoke(fn interface{}, args ...string) { //fn(args...) } func main() { Invoke(PrintThis, "foo") Invoke(PrintThisAndThat, "foo", "bar") } This is not the actual production code, but this is a simplified version. Question :- If I uncomment the line //fn(args..

Why PHP Trait can't implement interfaces?

半世苍凉 提交于 2020-01-30 14:07:21
问题 I'm wondering why PHP Trait (PHP 5.4) cannot implement interfaces. Update from user1460043's answer => ...cannot require class which uses it to implement a specific interface I understand that it could be obvious, because people could think that if a Class A is using a Trait T which is implementing an interface I , than the Class A should be implementing the interface I undirectly (and this is not true because Class A could rename trait methods). In my case, my trait is calling methods from

base class implementing base interface while derived/concrete class implementing extended interface, why?

試著忘記壹切 提交于 2020-01-30 05:09:48
问题 I am following a book namely ".NET Domain Driven Design with C#". Question is based on scenario as shown in Class Diagram below: Figure: http://screencast.com/t/a9UULJVW0 In this diagram, A) IRepository interface is implemented by (abstract base class) RepositoryBase whereas, B) IRepository interface is also extended by interface ICompanyRepository (ICompanyRepository : IRepository). C) ICompanyRepository is implemented by CompanyRepository which is derived from SQLRepositoryBase which is

PHP: Passing Interface as Parameter

浪子不回头ぞ 提交于 2020-01-30 02:49:29
问题 In .NET I have done that I passed Interfaces as parameters in class methods. I want to know is it possible in PHP? My scnerio is that I have a class dealing with mqin system functionality. Now I want to integrate Notification system with it. I want to keep notification system separate since it is not the main part of the system plus I can use it somewhere else. If I have the following structure: Interface INotification { public set() public send() } And then I do: class MyClass { public

Private interface methods, example use-case?

社会主义新天地 提交于 2020-01-29 03:18:47
问题 "Support for private methods in interfaces was briefly in consideration for inclusion in Java SE 8 as part of the effort to add support for Lambda Expressions, but was withdrawn to enable better focus on higher priority tasks for Java SE 8. It is now proposed that support for private interface methods be undertaken thereby enabling non abstract methods of an interface to share code between them." So says the specification for http://openjdk.java.net/jeps/213 and says in bug report https:/