integer

Errors after changing NSNumber to Int/Double

无人久伴 提交于 2021-01-07 06:58:28
问题 I have this class to get data from Firestore: struct Spty: Identifiable{ var id: String var spty: String var r: NSNumber var g: NSNumber var b: NSNumber } class SptyViewModel: NSObject, ObservableObject{ @Published var specialities = [Spty]() @Published var search = "" func fetchData(){ let db = Firestore.firestore() db.collection("specialities").addSnapshotListener { (querySnapshot, error) in guard let documents = querySnapshot else {return } self.specialities = documents.documents

Integer.parseInt() and Integer.toString() runtime

你。 提交于 2021-01-05 07:45:10
问题 Would the runtime of Integer.parseInt(String i) and Integer.toString(int i) both be O(n)? 回答1: Yes both of them Integer.parseInt("1000") and Integer.toString(1000) have time complexity O(N) The internal code of Integer.parseInt("1000") reads the the strings char by char and covert to decimal in while loop The internal code of Integer.toString(1000) reads the integers and convert every digit to char and stores in byte[] buf then creates new string from the byte array Here is the code of

How do I print an integer with a set number of spaces before it?

亡梦爱人 提交于 2021-01-04 07:10:36
问题 C has printf("%Xd", Y); , which just prints the integer X and makes it take Y spaces on the console window. For example: printf("%3d", 10); console: " 10"` printf("%5d", 5); console: " 5" How do I use this in python 3? 回答1: This print("{0:10d}".format(5)) will print 5 after 9 blanks. For more reference on formatting in python refer this. 回答2: I would do something like this: >>> print(10*' ',10) 10 >>> print(5*' ',5) 5 >>> x=5 >>> print(x*' ',x) 5 >>> 回答3: Using ljust or rjust: These python

How do I print an integer with a set number of spaces before it?

落爺英雄遲暮 提交于 2021-01-04 07:09:39
问题 C has printf("%Xd", Y); , which just prints the integer X and makes it take Y spaces on the console window. For example: printf("%3d", 10); console: " 10"` printf("%5d", 5); console: " 5" How do I use this in python 3? 回答1: This print("{0:10d}".format(5)) will print 5 after 9 blanks. For more reference on formatting in python refer this. 回答2: I would do something like this: >>> print(10*' ',10) 10 >>> print(5*' ',5) 5 >>> x=5 >>> print(x*' ',x) 5 >>> 回答3: Using ljust or rjust: These python

Choosing an integer type in core data

蓝咒 提交于 2021-01-02 20:40:40
问题 When I create models in core data, I'm always a little perplexed by which integer type I should choose—16, 32, 64. I'm almost always needing something for a simple, basic number: a count of people in the household, for my present case. Probably going to be a number between 1-20. Or, I have an incrementing case id number in another instance...can't imagine that going further than few hundred people. And here's the deal...It's clear that true computer science folk think of numbers differently,

Choosing an integer type in core data

荒凉一梦 提交于 2021-01-02 20:39:53
问题 When I create models in core data, I'm always a little perplexed by which integer type I should choose—16, 32, 64. I'm almost always needing something for a simple, basic number: a count of people in the household, for my present case. Probably going to be a number between 1-20. Or, I have an incrementing case id number in another instance...can't imagine that going further than few hundred people. And here's the deal...It's clear that true computer science folk think of numbers differently,

Choosing an integer type in core data

旧时模样 提交于 2021-01-02 20:39:49
问题 When I create models in core data, I'm always a little perplexed by which integer type I should choose—16, 32, 64. I'm almost always needing something for a simple, basic number: a count of people in the household, for my present case. Probably going to be a number between 1-20. Or, I have an incrementing case id number in another instance...can't imagine that going further than few hundred people. And here's the deal...It's clear that true computer science folk think of numbers differently,

Choosing an integer type in core data

匆匆过客 提交于 2021-01-02 20:39:10
问题 When I create models in core data, I'm always a little perplexed by which integer type I should choose—16, 32, 64. I'm almost always needing something for a simple, basic number: a count of people in the household, for my present case. Probably going to be a number between 1-20. Or, I have an incrementing case id number in another instance...can't imagine that going further than few hundred people. And here's the deal...It's clear that true computer science folk think of numbers differently,

Python: return float 1.0 as int 1 but float 1.5 as float 1.5 [duplicate]

跟風遠走 提交于 2020-12-29 08:54:55
问题 This question already has answers here : How to check if a float value is a whole number (13 answers) How to make python print 1 as opposed to 1.0 (3 answers) Closed last year . In Python is there a way to turn 1.0 into a integer 1 while the same function ignores 1.5 and leaves it as a float ? Right now, int() will turn 1.0 into 1 but it will also round 1.5 down to 1 , which is not what I want. 回答1: Continuing from the comments above: Using is_integer(): Example from the docs : >>> (1.5).is

C++ read integers from file and save into array

隐身守侯 提交于 2020-12-26 20:22:49
问题 I'm making a program that reads only integers from text file. I want to make a function that reads integers and stores them in an array so I can use that array later to sort them with bubble sort. This is what I have so far but the output I get is some random -803234.... number : void read(int A[max], int& numbers) { ifstream file("ints.txt"); if (file.is_open()) { file >> numbers; for (int i = 0; i < numbers; i++) { cout << "numbers: " << A[i] << endl; } file.close(); } cout << "numbers in