integer

问题 Does MySQL (5.0.45) like to do strange internal typecasts with unsigned maths? I am storing integers unsigned but when selecting basic arithmetic I get outrageous numbers: mysql> create table tt ( a integer unsigned , b integer unsigned , c float ); Query OK, 0 rows affected (0.41 sec) mysql> insert into tt values (215731,216774,1.58085); Query OK, 1 row affected (0.00 sec) mysql> select a,b,c from tt; +--------+--------+---------+ | a | b | c | +--------+--------+---------+ | 215731 | 216774

问题 Does MySQL (5.0.45) like to do strange internal typecasts with unsigned maths? I am storing integers unsigned but when selecting basic arithmetic I get outrageous numbers: mysql> create table tt ( a integer unsigned , b integer unsigned , c float ); Query OK, 0 rows affected (0.41 sec) mysql> insert into tt values (215731,216774,1.58085); Query OK, 1 row affected (0.00 sec) mysql> select a,b,c from tt; +--------+--------+---------+ | a | b | c | +--------+--------+---------+ | 215731 | 216774

问题 What is a scalable algorithm to print an N-binary-digit integer manually whose value does not fit in long long . I know printf and friends, along with <iostream> (which most likely piggy-backs on <cstdio> have this builtin for standard types, but I'd like to do it for an integer composed of N bytes. I have thought about this and googled a bit, but it always comes down to using a pre-existing bigint libirary like GMP (a codebase I am not at all familiar with) or "use printf" or the most

问题 What is a scalable algorithm to print an N-binary-digit integer manually whose value does not fit in long long . I know printf and friends, along with <iostream> (which most likely piggy-backs on <cstdio> have this builtin for standard types, but I'd like to do it for an integer composed of N bytes. I have thought about this and googled a bit, but it always comes down to using a pre-existing bigint libirary like GMP (a codebase I am not at all familiar with) or "use printf" or the most

问题 my code is: public class Box { public static void main(String[] args) { Integer z = new Integer(43); z++; Integer h = new Integer(44); System.out.println("z == h -> " + (h == z )); } } Output:- z == h -> false why the output is false when the values of both the objects is equal? Is there any other way in which we can make the objects equal? 回答1: You are trying to compare two different object and not their values. z and h points to two different Integer object which hold same value. z == h

问题 I have a string of integer "72101108108111" but it is a string representing bytes of original string "Hello". How can I convert "72101108108111" to Ascii string "Hello" in Ruby? 回答1: s = '72101108108111' pattern=/^[a-zA-Z]/ index,res=0,'' while index<s.size len=0 while (s[index..index+len].to_i.chr=~pattern).nil? len+=1 end res << s[index..index+len].to_i.chr index+=len+1 end p res Try this , because the length of every string to be decoded is not certain. For example, "72->'H' , 101->'e' ,

问题 I have some functions doing math stuff which needs to take integer agrmuents. I know that I can force using int by using condition isinstance(x, int) or more strict type(x) == int , but IMO it isn't pythonic. I think my Python code shouldn't reject 2.0 just because it's float . What's the best way to check if value is logically integer ? By logically integer I mean value of any type, which represents integer. It should be able to be used in arithmetic operations like int , but I don't have to

问题 I can't understand why this is not printing the expected value (400300) when I put extra zeros in front of the number: System.out.println(new Integer(0400300)); // prints 131264 System.out.println(0400300); // prints 131264 If I put one or more zeros in front of the number, the expected value is not printed. // JUnit test does not pass: assertTrue(0400300 == 400300); // returns false!? 回答1: Adding 0 to the front made the number an Octal literal . So: 0400300 = 3 * 8 ^ 2 + 4 * 8 ^ 5 = 131264

问题 I can't understand why this is not printing the expected value (400300) when I put extra zeros in front of the number: System.out.println(new Integer(0400300)); // prints 131264 System.out.println(0400300); // prints 131264 If I put one or more zeros in front of the number, the expected value is not printed. // JUnit test does not pass: assertTrue(0400300 == 400300); // returns false!? 回答1: Adding 0 to the front made the number an Octal literal . So: 0400300 = 3 * 8 ^ 2 + 4 * 8 ^ 5 = 131264

问题 This question already has answers here : Method Overloading for null argument (7 answers) Closed 3 years ago . I am confused with the Output of the following two programs. When I'm only having two methods with parameters as String and Object in Program 1 it gives me output as String . But when I add a new method with parameter as Integer in Program 2 it won't compile and gives error as The method nullTest(Object) is ambiguous for the type testNull Program 1 : package onkartest; public class