integer

问题 integer = input("Number: ") rslt = int(integer)+2 print('2 + ' + integer + ' = ' + rslt) double = input("Point Number: ") print('2.5 + ' +double+' = ' +(float(double)+2.5)) Gives me Traceback (most recent call last): File "C:\...", line 13, in <module> print('2 + ' + integer + ' = ' + rslt) TypeError: Can't convert 'int' object to str implicitly I'm fairly new to programming and my background is mostly just the basics of C# so far. I wanted to try to learn Python through doing all my C#

问题 integer = input("Number: ") rslt = int(integer)+2 print('2 + ' + integer + ' = ' + rslt) double = input("Point Number: ") print('2.5 + ' +double+' = ' +(float(double)+2.5)) Gives me Traceback (most recent call last): File "C:\...", line 13, in <module> print('2 + ' + integer + ' = ' + rslt) TypeError: Can't convert 'int' object to str implicitly I'm fairly new to programming and my background is mostly just the basics of C# so far. I wanted to try to learn Python through doing all my C#

问题 I have a data.table called enc.per.day for encounters per day. It has 2403 rows in which a date of service is specified and the number of patients seen on that day. I wanted to see the median number of patients seen on any type of weekday. enc.per.day[,list(patient.encounters=median(n)),by=list(weekdays(DOS))] That line gives an error Error in [.data.table (enc.per.day, , list(patient.encounters = median(n)), : columns of j don't evaluate to consistent types for each group: result for group 4

问题 How can I generate a random number in MATLAB between 13 and 20? 回答1: If you are looking for Uniformly distributed pseudorandom integers use: randi([13, 20]) 回答2: http://www.mathworks.com/help/techdoc/ref/rand.html n = 13 + (rand(1) * 7); 回答3: r = 13 + 7.*rand(100,1); Where 100,1 is the size of the desidered vector 回答4: ocw.mit.edu is a great resource that has helped me a bunch. randi is the best option, but if your into number fun try using the floor function with rand to get what you want. I

问题 How can I generate a random number in MATLAB between 13 and 20? 回答1: If you are looking for Uniformly distributed pseudorandom integers use: randi([13, 20]) 回答2: http://www.mathworks.com/help/techdoc/ref/rand.html n = 13 + (rand(1) * 7); 回答3: r = 13 + 7.*rand(100,1); Where 100,1 is the size of the desidered vector 回答4: ocw.mit.edu is a great resource that has helped me a bunch. randi is the best option, but if your into number fun try using the floor function with rand to get what you want. I

问题 I'm writing a program which calculates the check digit of an ISBN number. I have to read the user's input (nine digits of an ISBN) into an integer variable, and then multiply the last digit by 2, the second last digit by 3 and so on. How can I "split" the integer into its constituent digits to do this? As this is a basic homework exercise I am not supposed to use a list. 回答1: Just create a string out of it. myinteger = 212345 number_string = str(myinteger) That's enough. Now you can iterate

问题 I'm writing a program which calculates the check digit of an ISBN number. I have to read the user's input (nine digits of an ISBN) into an integer variable, and then multiply the last digit by 2, the second last digit by 3 and so on. How can I "split" the integer into its constituent digits to do this? As this is a basic homework exercise I am not supposed to use a list. 回答1: Just create a string out of it. myinteger = 212345 number_string = str(myinteger) That's enough. Now you can iterate

问题 how to write a code snippet Ruby that will flatten an array of arbitrarily nested arrays of integers into a flat array of integers. e.g. [[1,2,[3]],4] -> [1,2,3,4]. Please don't use any built-in flatten functions in either language. 回答1: Here's one solution without using the built-in flatten method. It involves recursion def flattify(array) array.each_with_object([]) do |element, flattened| flattened.push *(element.is_a?(Array) ? flattify(element) : element) end end I tested this out in irb.

问题 how to write a code snippet Ruby that will flatten an array of arbitrarily nested arrays of integers into a flat array of integers. e.g. [[1,2,[3]],4] -> [1,2,3,4]. Please don't use any built-in flatten functions in either language. 回答1: Here's one solution without using the built-in flatten method. It involves recursion def flattify(array) array.each_with_object([]) do |element, flattened| flattened.push *(element.is_a?(Array) ? flattify(element) : element) end end I tested this out in irb.

问题 how to write a code snippet Ruby that will flatten an array of arbitrarily nested arrays of integers into a flat array of integers. e.g. [[1,2,[3]],4] -> [1,2,3,4]. Please don't use any built-in flatten functions in either language. 回答1: Here's one solution without using the built-in flatten method. It involves recursion def flattify(array) array.each_with_object([]) do |element, flattened| flattened.push *(element.is_a?(Array) ? flattify(element) : element) end end I tested this out in irb.