int

How to convert an Int into NSData in Swift?

跟風遠走 提交于 2020-01-01 01:16:07
问题 In Objective-C I use the following code to Convert an Int variable into NSData , a packet of bytes. int myScore = 0; NSData *packet = [NSData dataWithBytes:&myScore length:sizeof(myScore)]; Use the converted NSData variable into a method. [match sendDataToAllPlayers: packet withDataMode: GKMatchSendDataUnreliable error: &error]; I tried converting the Objective-C code into Swift: var myScore : Int = 0 func sendDataToAllPlayers(packet: Int!, withDataMode mode: GKMatchSendDataMode, error:

list comprehension replace for loop in 2D matrix

旧城冷巷雨未停 提交于 2019-12-31 12:12:08
问题 I try to use list comprehension to replace the for loop. original file is 2 3 4 5 6 3 1 2 2 4 5 5 1 2 2 2 2 4 for loop line_number = 0 for line in file: line_data = line.split() Cordi[line_number, :5] = line_data line_number += 1 output is [[2 3 4 5 6 3] [1 2 2 4 5 5] [1 2 2 2 2 4]] if use list comprehension instead, for what I can think of is (I have to change the data type to int, so it can be plotted in later part of the program) Cordi1= [int(x) for x in line.split() for line in data] but

Integer value comparison

帅比萌擦擦* 提交于 2019-12-31 11:37:29
问题 I'm a newbie Java coder and I just read a variable of an integer class can be described three different ways in the API. I have the following code: if (count.compareTo(0)) { System.out.println(out_table); count++; } This is inside a loop and just outputs out_table . My goal is to figure out how to see if the value in integer count > 0 . I realize the count.compare(0) is the correct way? or is it count.equals(0) ? I know the count == 0 is incorrect. Is this right? Is there a value comparison

Integer value comparison

ε祈祈猫儿з 提交于 2019-12-31 11:37:22
问题 I'm a newbie Java coder and I just read a variable of an integer class can be described three different ways in the API. I have the following code: if (count.compareTo(0)) { System.out.println(out_table); count++; } This is inside a loop and just outputs out_table . My goal is to figure out how to see if the value in integer count > 0 . I realize the count.compare(0) is the correct way? or is it count.equals(0) ? I know the count == 0 is incorrect. Is this right? Is there a value comparison

Get user input as int or str

丶灬走出姿态 提交于 2019-12-31 04:37:06
问题 I'm very new to python and believe me, I've searched endlessly for a solution to this but I just can't get it. I have a csv with a list of monitoring plots. With the code below, I have been able to display the 2dlist and get the user to enter a number to choose a particular plot (there's 11 of them), based on the list index. But when prompting the user to choose, I'd like to include an option '....or press 'q' to quit'. Now obviously raw_input is set to receive integers only but how can I

Parse a negative prefix integer from string in java

别等时光非礼了梦想. 提交于 2019-12-31 04:02:58
问题 Hi i have a string looking something like this 10 -1 30 -2 and i want to read the numbers between spaces. I can do this using a FOR statement and the code Character.toString(myString.charAt(i)); and Integer.parseInt(myString); But i face a problem when i try to read negative number like -1 and i got the error message: 09-09 13:06:49.630: ERROR/AndroidRuntime(3365): Caused by: java.lang.NumberFormatException: unable to parse '-' as integer Any ideas how to solve this ?? 回答1: You're trying to

Python 3 int() function is not converting input string to integer

做~自己de王妃 提交于 2019-12-31 03:54:13
问题 I am working on a small program that reads data from a CSV file. As part of the program, user input is used to only select data that >= but I get TypeError: unorderable types: str() >= int() when I run the code. Looks like the sting is not converting to integer. def get_csv_data(data_type, num): import csv ga_session_data = {} ga_pageviews_data = {} with open('files/data.csv', 'r') as csvfile: reader = csv.reader(csvfile) for row in reader: page, sessions, pageviews = row ga_session_data[page

Python class methods changing self

[亡魂溺海] 提交于 2019-12-31 03:30:09
问题 This isn't for anything I'm working on yet, it's just some test code as I'm just learning class methods and suck. But say I have the following code class Test(int): def __init__(self,arg): self = arg def thing(self): self += 10 and going, foo=Test(12) sets foo to 12. However I want it, so when I do, foo.thing(), foo increases by 10. So far, going foo.thing() just keeps it at 12. How would I change this code to do that. 回答1: Because int is a immutable, you cannot magically turn it into a

Upper limits for fibonnacci

孤街醉人 提交于 2019-12-31 02:31:51
问题 I was reading about the DP version of fibonnaci. In Sedgewick I saw: int[] T = new int[47]; for storage of the previous calculations. Elsewhere I saw that the max input for fibonacci should be less than 92 . It is not clear to me how does these numbers come up? I understand that it has to do with overflow and size of int but I am not clear how we end up with these limits. Any help? 回答1: Well, the fibonacci series grows (approximately) exponentially with a ratio of 1.618 (the golden ratio). If

Behavior of int and short in c

限于喜欢 提交于 2019-12-31 01:59:10
问题 I want to know what is the reason of the output of the following codes: unsigned short a=10,aa=-1; if(a>-1) printf("surprise"); else printf(" No surprise"); This gives output "Surprise" unsigned int a=10,aa=-1; if(a>-1) printf("surprise"); else printf("No surprise"); This gives output "No Surprise" and unsigned short a=10,aa=-1; if(a>aa) printf("surprise"); else printf("No surprise"); This gives the output "No Surprise" 回答1: See this Stack Exchange question: In a C expression where unsigned