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问题 I am trying to pass a pointer to a system call by passing a message with that call. The pointer should be to an int[]. However the message definition expects a char pointer to be passed. How can I send an int pointer? int pidarray[j]; m.m1_p1 = pidarray; Is it possible to convert the pointer types? 回答1: Is it possible to convert the pointer types? Yes this is possible. e.g.: (char*) intPointer 来源： https://stackoverflow.com/questions/34063927/c-system-calls-and-messages

问题 I am trying to pass a pointer to a system call by passing a message with that call. The pointer should be to an int[]. However the message definition expects a char pointer to be passed. How can I send an int pointer? int pidarray[j]; m.m1_p1 = pidarray; Is it possible to convert the pointer types? 回答1: Is it possible to convert the pointer types? Yes this is possible. e.g.: (char*) intPointer 来源： https://stackoverflow.com/questions/34063927/c-system-calls-and-messages

问题 I have a weird bug here. I'm subclassing UIImageView to pass some custom properties to my views. If I don't add an init method to my subclass, everything's fine. But if I do add the init (and I'm required to do so), then when I'm creating the frame view the compiler complains that an Int is not convertible to CGFloat. Le subclass with Le init : class CustomUIImageView : UIImageView { let someParameter : Bool init(someParameter: Bool) { self.someParameter = someParameter println("\

问题 I have a while loop that scans in an input set of integers. It scans and prints all of the numbers with "..." at the end and skips to the next line. However, the script does not: execute past the while loop and print TEST. For example, I enter: 3 44 62 1 It prints: 3... 44... 62... 1... When it should print: 3... 44... 62... 1... TEST while(scanf("%d", &n) != -1) { x[i] = n; i++; printf("%d", n); printf("...\n"); } printf("TEST"); What am I doing wrong? 回答1: scanf("%d", &n) != 1 is wrong. It

问题 I'm new to Python (running Python 3), have searched every where and still stuck on this. I understand that I have a string but need to get it into a integer as a final answer. Below is the code I inputted to test it out. I'm stuck on the error that I get. This is for a compound interest calculator where the user has to input the principal, annual interest rate, how often it's compounded, and the year(s). I did some research and noticed that i can use ('inf') for p,n,and r as a statement

问题 I am new to cpp programing, and new to stackoverflow. I have a simple situation and a problem that is taking more time than reasonable to solve, so I thought I'd ask it here. I want to take one digit from a rand() at a time. I have managed to strip of the digit, but I can't convert it to an int which I need because it's used as an array index. Can anyone help? I'd be appreciative. Also if anyone has a good solution to get evenly-distributed-in-base-10 random numbers, I'd like that too... of

问题 I am new to cpp programing, and new to stackoverflow. I have a simple situation and a problem that is taking more time than reasonable to solve, so I thought I'd ask it here. I want to take one digit from a rand() at a time. I have managed to strip of the digit, but I can't convert it to an int which I need because it's used as an array index. Can anyone help? I'd be appreciative. Also if anyone has a good solution to get evenly-distributed-in-base-10 random numbers, I'd like that too... of

问题 I have the following code: %include "io.inc" section .data msg db 'Hello World...$' section .text global CMAIN CMAIN: ;write your code here mov ah,09 mov dx,OFFSET msg int 21h xor eax, eax xor dx,dx ret and it gets the next error: [19:28:32] Warning! Errors have occurred in the build: C:/Users/user/AppData/Local/Temp/SASM/program.asm:12: error: comma, colon, decorator or end of line expected after operand gcc.exe: error: C:/Users/user/AppData/Local/Temp/SASM/program.o: No such file or

问题 I would like to use the value calculated in the second, "for i in range" statement to calculate a new value using the fourth, "for i in range" statement; however, I receive the error: "could not convert string to float: 'E2*37.5'" How do I call upon the numerical value calculated in, sheet['F{}',format(i)] ='E{}*37.5'.format(i) instead of the formula/string? import openpyxl wb = openpyxl.load_workbook('camdatatest.xlsx', read_only= False, data_only = True) # Assuming you are working with

问题 Iam programming in C++ and Iam comming with another "stupid" problem. If I have 4 chars like these: char a = 0x90 char b = 0x01 char c = 0x00 char d = 0x00 when that all means hexadecimal number 0x00000190 which is 400 decimal number. How do I convert these chars to one int? I know i can do int number = a; but this will convert only one char to int. Could anybody help please? 回答1: You may use: int number = (a & 0xFF) | ((b & 0xFF) << 8) | ((c & 0xFF) << 16) | ((d & 0xFF) << 24); It would be