insertion-sort

问题 When implementing Insertion Sort, a binary search could be used to locate the position within the first i - 1 elements of the array into which element i should be inserted. How would this affect the number of comparisons required? How would using such a binary search affect the asymptotic running time for Insertion Sort? I'm pretty sure this would decrease the number of comparisons, but I'm not exactly sure why. 回答1: Straight from Wikipedia: If the cost of comparisons exceeds the cost of

问题 function insertSort(inputArray = myChart.data.datasets[0].data) { let inputArrayLength = inputArray.length; let outerIndex = 1; let innerIndex = 0; while(outerIndex<inputArrayLength) { innerIndex = outerIndex - 1; temp = outerIndex; while(innerIndex>=0){ if (inputArray[temp]<inputArray[innerIndex]){ inputArray[innerIndex] = [inputArray[temp], inputArray[temp] = inputArray[innerIndex]][0]; temp = innerIndex; innerIndex--; } else { innerIndex--; } } sleep(1000); console.log('Intermediate result

问题 How would the algorithm's (of Insertion Sort of O(n^2) ) complexity change if you changed the algorithm to use a binary search instead of searching previous values until you found where to insert your current value. Also, When would this be useful? 回答1: Your new complexity is still quadratic , since you need to move all of the sorted parts rightward. Therefore, using binary search is only marginally better. I would recommend a fast sorting algorithm (in O(n log n) time) for large arrays, the

问题 How would the algorithm's (of Insertion Sort of O(n^2) ) complexity change if you changed the algorithm to use a binary search instead of searching previous values until you found where to insert your current value. Also, When would this be useful? 回答1: Your new complexity is still quadratic , since you need to move all of the sorted parts rightward. Therefore, using binary search is only marginally better. I would recommend a fast sorting algorithm (in O(n log n) time) for large arrays, the

问题 I am making an uno card game with structure of card with fields: struct card { int rank char *color char *action. } I am able to make it sort by color with insertion. I wonder how could I first sort the array of uno card by color, then sort the rank of each color. 回答1: Thanks to Bo Persoson, this is the solution to my question void sort(card *a, int length) { int j; for (int i = 1; i < length; i++) { j = i; while (j > 0 && a[j].color < a[j - 1].color || (a[j].color == a[j - 1].color && a[j]

问题 I am making an uno card game with structure of card with fields: struct card { int rank char *color char *action. } I am able to make it sort by color with insertion. I wonder how could I first sort the array of uno card by color, then sort the rank of each color. 回答1: Thanks to Bo Persoson, this is the solution to my question void sort(card *a, int length) { int j; for (int i = 1; i < length; i++) { j = i; while (j > 0 && a[j].color < a[j - 1].color || (a[j].color == a[j - 1].color && a[j]

问题 I am making an uno card game with structure of card with fields: struct card { int rank char *color char *action. } I am able to make it sort by color with insertion. I wonder how could I first sort the array of uno card by color, then sort the rank of each color. 回答1: Thanks to Bo Persoson, this is the solution to my question void sort(card *a, int length) { int j; for (int i = 1; i < length; i++) { j = i; while (j > 0 && a[j].color < a[j - 1].color || (a[j].color == a[j - 1].color && a[j]

来源： https://stackoverflow.com/questions/64050409/lottery-insertion-sort-algorithm

来源： https://stackoverflow.com/questions/64058935/gives-out-key-error-0-when-using-insertion-sort-in-python

来源： https://stackoverflow.com/questions/64050409/lottery-insertion-sort-algorithm