infinite-loop

问题 I am relatively new to C, but I have been programming for a few years now. I am writing a program for a college class, and I am confused why the scanf function below is not called, resulting in an infinite loop. I have tried having my scanf outside the function, calling it twice, once from within, once from out, and a few other ways. I read online that the fflush might help, but it hasn't Any suggestions? // store starting variables int players; // print title printf("*-----------------------

问题 I had a strange behavior in a program and I spent long time trying to deduce why. it was an infinite loop with no sense. Testing these lines of code(under suspicion) i got the same result. Every time I type in a non-numeric value such a symbol, the program runs through an infinite loop printing zeros, which i guess is how cout represents the wrong value entered. I'd like to know why is that weird behavior from cin, printing all those zeros instead of stopping when it finds a wrong reading.

问题 I had a strange behavior in a program and I spent long time trying to deduce why. it was an infinite loop with no sense. Testing these lines of code(under suspicion) i got the same result. Every time I type in a non-numeric value such a symbol, the program runs through an infinite loop printing zeros, which i guess is how cout represents the wrong value entered. I'd like to know why is that weird behavior from cin, printing all those zeros instead of stopping when it finds a wrong reading.

问题 I have the following method in C++ that only removes the elements associated with a particular tableId from a map. 69 void 70 ObjectFinder::flush(uint64_t tableId) { 71 72 RAMCLOUD_TEST_LOG("flushing object map"); 74 // find everything between tableId, 0 75 // keep scanning util find all the entries for that table 76 std::map<TabletKey, ProtoBuf::Tablets::Tablet>::const_iterator it; 79 for (it = tableMap.begin(); it != tableMap.end(); it++) { 80 TabletKey current = it->first; 81 if (tableId =

问题 var matches; while(matches = /./g.exec("abc")) { console.log("hey"); } This never terminates. I expect it to terminate after 3 loops. Warning: Don't run it in Chrome because the infinite log lines freeze your entire system. It's safe to run it in IE (it still freezes your webpage but you can go to the location bar and press enter to reload). 回答1: This is how you should execute exec in a loop: var matches; var re = /./g; while(matches = re.exec("abc")) { if (matches.index === re.lastIndex) re

问题 Since Smalltalk scheduling is non-preemptive, processes must explicitly yield or wait on a semaphore Does this mean that one object entering an infinite loop could stall the entire system? the loop can be interrupted at any time. Even an atomic loop like [true] whileTrue can be interrupted before "executing" the true object By what can it be interrupted? 回答1: It is the Virtual Machine who may interrupt the image. Under a normal execution flow, the VM is basically sending messages, one after

问题 Since Smalltalk scheduling is non-preemptive, processes must explicitly yield or wait on a semaphore Does this mean that one object entering an infinite loop could stall the entire system? the loop can be interrupted at any time. Even an atomic loop like [true] whileTrue can be interrupted before "executing" the true object By what can it be interrupted? 回答1: It is the Virtual Machine who may interrupt the image. Under a normal execution flow, the VM is basically sending messages, one after

问题 So I'm using size_t instead of int in any indexing for loop to prevent negative indices. But when counting down, this leads to an overflow: for (size_t i = 10; i >= 0; --i) { // Do something, f.ex. array[i] = i } What would be a nice way to prevent this? Using int instead? Using i == 0 as the termination condition? (This would however not work if I need the 0) I'd appreciate any feedback! 回答1: for (size_t i = 10; i <= 10; --i) // do something When overflow do happens, it will round to the

问题 So I'm using size_t instead of int in any indexing for loop to prevent negative indices. But when counting down, this leads to an overflow: for (size_t i = 10; i >= 0; --i) { // Do something, f.ex. array[i] = i } What would be a nice way to prevent this? Using int instead? Using i == 0 as the termination condition? (This would however not work if I need the 0) I'd appreciate any feedback! 回答1: for (size_t i = 10; i <= 10; --i) // do something When overflow do happens, it will round to the

来源： https://stackoverflow.com/questions/63650820/checking-options-in-empty-infinite-loop-vs-dosomething-infite-loop