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ARM GIC

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GIC 简介 GIC 的全称为 General Interrupt Controller，主要作用可以归结为：接受硬件中断信号并进行简单处理，通过一定的设置策略，分给对应的CPU进行处理。 Terminology IRI: Interrupt Routing Infrastructure. The Distributor, Redistributor and ITS are collectively known as an IRI. The IRI performs interrupt grouping, interrupt prioritization, and controls the forwarding of interrupts to the CPU interfaces. ITS: Interrupt translation service, is an OPTIONAL hardware mechanism in the GICv3 architecture that routes LPIs to the appropriate Redistributor, and the GICv4 implementations must include at least one ITS. ARM 中断源分类 SGI: Software Generated Interrupt

Intel Compiler 18.0 Toolset raises exception with msbuild

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问题 I reinstalled my machine and installed Visual Studio 2017 , Visual Studio 2019 (Preview) and the Intel Compiler 18 . Due to unknown reasons, my projects do not work anymore, and I can't figure out what's causing it. Did anyone ever experience the following error message? My project uses the Intel C++ Compiler 18.0 toolset. Visual Studio 2017 error message : 1>C:\Program Files (x86)\Microsoft Visual Studio\2017\Professional\VC\Tools\MSVC\14.16.27023\include\xmemory0(178): error : identifier "_

C preprocessor TIMESTAMP in ISO 8601:2004

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问题 How can I have a __TIMESTAMP__ replacement in ISO 8601:2004? __TIMESTAMP__ Sat Jul 6 02:50:06 2013 vs __TIMESTAMP_ISO__ 2013-07-06T00:50:06Z 回答1: Oh ye optimist! You wouldn't really expect one standard to pay attention to another, would you? The __TIMESTAMP__ define is not in standard C, just so as you are aware. It would be great to have a format like your proposed __TIMESTAMP_ISO__ (would you always want Zulu time, or would it be better to have the local time zone offset?), but frankly, the

Why does NaN - NaN == 0.0 with the Intel C++ Compiler?

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问题 It is well-known that NaNs propagate in arithmetic, but I couldn't find any demonstrations, so I wrote a small test: #include <limits> #include <cstdio> int main(int argc, char* argv[]) { float qNaN = std::numeric_limits<float>::quiet_NaN(); float neg = -qNaN; float sub1 = 6.0f - qNaN; float sub2 = qNaN - 6.0f; float sub3 = qNaN - qNaN; float add1 = 6.0f + qNaN; float add2 = qNaN + qNaN; float div1 = 6.0f / qNaN; float div2 = qNaN / 6.0f; float div3 = qNaN / qNaN; float mul1 = 6.0f * qNaN;

Why does NaN - NaN == 0.0 with the Intel C++ Compiler?

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Deleted Function in std::pair when using a unique_ptr inside a map

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问题 I have a piece of C++ code for which I am not sure whether it is correct or not. Consider the following code. #include <memory> #include <vector> #include <map> using namespace std; int main(int argc, char* argv[]) { vector<map<int, unique_ptr<int>>> v; v.resize(5); return EXIT_SUCCESS; } The GCC compiles this code without a problem. The Intel compiler (version 19), however, stops with an error: /usr/local/ [...] /include/c++/7.3.0/ext/new_allocator.h(136): error: function "std::pair<_T1, _T2

Make error: I want the make file to use gcc compiler flags but originally it uses intel

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问题 I also tried make -icpc="CXX" make -icc="cc" gives the error. make: invalid option -- 'c' make: invalid option -- 'c' make: invalid option -- '=' make: invalid option -- 'c' make: invalid option -- 'c' Currently Loaded Module files: gcc make python/2.7.11 openmpi/1.10.1-gnu hdf5/1.8.10-intel boost/1.60.0-gnu5 mkl/2013.5.192 mpich/3.1.2-gnu 来源： https://stackoverflow.com/questions/43528646/make-error-i-want-the-make-file-to-use-gcc-compiler-flags-but-originally-it-use

How to create a executable hex from elf file format

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问题 I am very very new to this, I have elf file input.out and need to create hex executable from it. I am using objcopy to create executable in intel hex format as follows objcopy -O ihex input.out out.hex by this out.hex contains data from all sections (.interp, .note.ABI-tag etc), but i am not sure if all of it is required for executable. Is just .text section enough for creating executable hex so can i just use as below or any more sections are required objcopy -j.text -O ihex input.out out

Getting Intel-syntax asm output from icc, instead of the default AT&T syntax?

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问题 I am stuck at a problem. I've been using gcc to compile/assemble my C code for a while and got used to reading Intel assembly syntax. I used the -masm=intel flag when generating the assembly files. Yet recently, due to company migrations, they obtained Intel's icc, claiming it is better. So now I need to use icc, but it was strange that it has the default assembly syntax as AT&T. I tried to change it but it didn't work, so I contacted Intel support and they also don't know and each person

Why is icc generating weird assembly for a simple main?

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问题 I have a simple program: int main() { return 2*7; } both GCC and clang with optimizations turned on hapily generate 2 instruction binary, but icc gives bizarre output. push rbp #2.1 mov rbp, rsp #2.1 and rsp, -128 #2.1 sub rsp, 128 #2.1 xor esi, esi #2.1 mov edi, 3 #2.1 call __intel_new_feature_proc_init #2.1 stmxcsr DWORD PTR [rsp] #2.1 mov eax, 14 #3.12 or DWORD PTR [rsp], 32832 #2.1 ldmxcsr DWORD PTR [rsp] #2.1 mov rsp, rbp #3.12 pop rbp #3.12 ret 回答1: I don't know why ICC chooses to align