.htaccess

问题 Hi i'm trying to create a REST API method in core php I created a controller class and method class to call my function as per the reference http://phppot.com/php/php-restful-web-service/ I have my files in sub-folder in my server where i'm currently creating this i face issue on accessing rewrite URL , how can u solve this issue below is the htaccess rule which i tried. RewriteEngine on RewriteBase /test/rest/ # map neat URL to internal URL RewriteRule ^/test/rest/mobile/list/$ /test/rest

问题 I am using following rules which skips files if paths to them is already provided. RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^$ public/index.php [NC,L] RewriteCond %{REQUEST_URI} !^/public/ RewriteRule ^(.+)$ public/index.php?r=$1 [L,QSA] But this makes me, to access the files like site.com/public/js/somefile.js , which is not intented. Can we check if file exists inside a directory

问题 I am using following rules which skips files if paths to them is already provided. RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^$ public/index.php [NC,L] RewriteCond %{REQUEST_URI} !^/public/ RewriteRule ^(.+)$ public/index.php?r=$1 [L,QSA] But this makes me, to access the files like site.com/public/js/somefile.js , which is not intented. Can we check if file exists inside a directory

问题 I have a site tha is written in PHP and pulls data from a MySql DB. The site utilises query strings and I would like to map the query generated pages to the more search engine friendly page titles. For example I would like to acheive to the following mappings: content.php?id=1 to map to /aboutus content.php?id=2 to map to /contactus content.php?id=3 to map to /newfiles how can i do this, in a more simple way. is that simply changing .htaccess file, or is that related to rewrite mapping

问题 In my website, i want to restrict viewing certain files which are stored in a directory called "/content" such that only logged in users can view the files as it stands right now anyone who types in xxxxxxx.com/content/4dc32b1c0a630.png into the browser can see this image file I've added Options -Indexes to my .htaccess file but that didn't do anything if it is helpful my site is built using codeigniter, so a PHP solution would be great, though I'd take any advice you might have! thank you,

问题 My laravel 5.2 app unable to fetch the stylesheet from the public/css directory on the production server but can fetch stylesheets on the local machine! here is how I am linking my files: <link href="{{asset('css/clock.css')}}" rel="stylesheet" media="all" /> I also tried bunch of different ways: <link href="{{URL::asset('css/clock.css')}}" rel="stylesheet" media="all" /> OR: {{HTML::style('css/clock.css')}} but nothing worked on server! but it is not able to fetch the css! when I check the

问题 I've created sub-domain URL on my site but it always shows "page not found" error. When I write foldername.website.com so it shows page not found but it works when I write website.com/foldername . I've removed all code of .htaccess from main folder and sub folder but still sub-domain URL is not working. 回答1: Your web folder design should be something like: website.com / <root> -----> <content for website> forum.website.com / <root> --------> <Content for subdomain website> You really can not

问题 I've created sub-domain URL on my site but it always shows "page not found" error. When I write foldername.website.com so it shows page not found but it works when I write website.com/foldername . I've removed all code of .htaccess from main folder and sub folder but still sub-domain URL is not working. 回答1: Your web folder design should be something like: website.com / <root> -----> <content for website> forum.website.com / <root> --------> <Content for subdomain website> You really can not

问题 I am trying to get a specific value from url like my url is http://www.example.biz/?_escaped_fragment=reader/i/1664 and I want to get output url is like below http://www.example.biz/seo/1664 I have tried this RewriteCond^(.*?)_escaped_fragment_=(.*)$ RewriteRule ^(.*)$ seo/%1 [NC] But Output url is coming below http://www.example.biz/seo/%1?_escaped_fragment=reader/i/1664 How will I do this? Any help appreciated. 回答1: You're not trying to match anything in your RewriteCond . RewriteCond %

问题 I have a URL which has been converted into SEO friendly url using .htaccess.But now i need to find the original url so that i can edit the file and locate it on the web server.The converted friendly url is Is is possible to get back the original url so that it can be located on the server.Thank you for your suggestions. .htaccess file view. # 1.To use URL Alias you need to be running apache with mod_rewrite enabled. # 2. In your opencart directory rename htaccess.txt to .htaccess. # For any