histogram

问题 This is my code and the result I got. Something is not right — I used histfit(cntH,NumBins,'kernel') , and I was expecting the distribution line to start from zero and fit into the bars How can I fix that? clear all clc % yG = total load yH % specify number of bins and edges of those bins; this example evenly spaces bins NumBins = 100; BinEdges = linspace(0,35,70); % use histcounts and specify your bins cntH = histcounts(yH,'BinEdges',BinEdges); % plot figure(1); cla; hold on; % convert bin

问题 I've been playing around with some old code, and I came across a function that I made a while ago that calculates the number of times each alphabetical letter appears in a given string. In my initial function, I would loop through the string 26 times counting the number of times each letter appears as it loops through. However, I knew that was really inefficient, so instead I tried to do this: int *frequency_table(char *string) { int i; char c; int *freqCount = NULL; freqCount = mallocPtr

问题 I produced a histogram which looks something like this: Code that I used to produce this plot: sns.countplot(table.column_name) As you can notice, the entire histogram gets clustered at the left end due to uneven distribution of data. How do I zoom in at the left end? One way that I tried and it gave me a marginally better result was : plt.xlim(0,25) Is there a better way to do this? 回答1: Looks like the data would be better viewed on a logarithmic scale. On your matplotlib plot axis, ax , use

问题 I produced a histogram which looks something like this: Code that I used to produce this plot: sns.countplot(table.column_name) As you can notice, the entire histogram gets clustered at the left end due to uneven distribution of data. How do I zoom in at the left end? One way that I tried and it gave me a marginally better result was : plt.xlim(0,25) Is there a better way to do this? 回答1: Looks like the data would be better viewed on a logarithmic scale. On your matplotlib plot axis, ax , use

问题 I produced a histogram which looks something like this: Code that I used to produce this plot: sns.countplot(table.column_name) As you can notice, the entire histogram gets clustered at the left end due to uneven distribution of data. How do I zoom in at the left end? One way that I tried and it gave me a marginally better result was : plt.xlim(0,25) Is there a better way to do this? 回答1: Looks like the data would be better viewed on a logarithmic scale. On your matplotlib plot axis, ax , use

问题 Hi to whole stackoverflow group, I am having a series of problems when defining the axes range in my graphic and format in general, and I would like to share it with you to see if among all we can find the error I have found on this website a user who has made it similar. My idea is to have something similar like the graphic of the link below. But for some reason, it's probably silly, it does not appear correctly. My code is as following: set term post eps enhanced color "Times-Roman" 14 set

问题 I have used formula: ((L-1)/MN) ni where L is total no of graylevels,M N is size of image, ni is cumulative frequency But I am getting full black image always.I have tried with other images as well. import numpy as np import cv2 path="C:/Users/Arun Nambiar/Downloads/fingerprint256by256 (1).pgm" img=cv2.imread(path,0) #To display image before equalization cv2.imshow('image',img) cv2.waitKey(0) cv2.destroyAllWindows() a=np.zeros((256,),dtype=np.float16) b=np.zeros((256,),dtype=np.float16)

问题 I believe my question is very similar to this post. Only difference is my aes fill is a factor with multiple levels. This what I am after and this is how far I have gotten set.seed(123) n = 100 LoanStatus = sample(c('Chargedoff', 'Completed', 'Current', 'Defaulted', 'PastDue'), n, replace = T, prob = NULL) ProsperScore = sample(1:11, n, replace = T, prob = NULL) df = data.frame(ProsperScore,factor(LoanStatus)) df = data.frame(ProsperScore,LoanStatus) probs = data.frame(prop.table(table(df),1)

问题 I don't get how to make the bars of an histogram to appears in descending order with ggplot. Heres my code with a dataframe that everyone can use : library(ggplot2) library(scales) chol <- read.table(url("http://assets.datacamp.com/blog_assets/chol.txt"), header = TRUE) ggplot(chol) + geom_histogram(aes(x = AGE, y = ..ncount.., fill = ..ncount..), breaks=seq(20, 50, by = 2), col="red", alpha = .2) + scale_fill_gradient("Percentage", low = "green", high = "red") + scale_y_continuous(labels =

问题 I've got a set with >10000 integers attaining values between 1 and 500. I want to plot the values in form of a histogram, however, since only a few integers attain values greater than 200, I want to use a logarithmic scale for the y-axis. A problem emerges, when one bin has a count of zero, since the logarithmic value goes to -infinity. To avoid this, I want to add a pseudocount of 1 to each bin. In a standard hist()-plot I can do this like follows: hist.data = hist(data, plot=F, breaks=30)