hexdump | 易学教程

xxd binary dump problems

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问题 Is the above output in the format that should be expected from xxd or does the presence of the bizzare characters on the right suggest i've done something wrong? I'm attempting to serialise a simple linked list and that's the output i get. Would failing to remove the sentinal character "\0" from the serialisation cause the error? 回答1: I'm guessing you are serializing as binary not as strings , so this is normal. Each two hex digits on the left correspond to a one character on the right. This

Print binary representation of file

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问题 I need a function which will print out the binary representation of a read file like the xxd program in unix, but I want to make my own. Hexidecimal works just fine with %x but there is no built in format for binary. Anyone know how to do this? 回答1: I usually do not believe in answering these sorts of questions with full code implementations, however I was handed this bit of code many years ago and I feel obligated to pass it on. I have removed all the comments except for the usage, so you

hexadecimal dump to binary - xxd -r equivalent

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问题 In Linux bash shell, I use the following to convert a plain hexadecimal dump into binary $ echo "8cd59ef53c9aaa68311b73767e0975e7" | xxd -r -p > xxd_out.bin when I open the file in text viewer it looks like ŒÕžõ<šªh1sv~ uç or in xxd $ xxd -b xxd_out.bin 00000000: 10001100 11010101 10011110 11110101 00111100 10011010 ....<. 00000006: 10101010 01101000 00110001 00011011 01110011 01110110 .h1.sv 0000000c: 01111110 00001001 01110101 11100111 ~.u. or in Notepad++ Hex-Editor (plugin) view How can I

How to create binary file using Bash?

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问题 How can I create a binary file with consequent binary values in bash? like: $ hexdump testfile 0000000 0100 0302 0504 0706 0908 0b0a 0d0c 0f0e 0000010 1110 1312 1514 1716 1918 1b1a 1d1c 1f1e 0000020 2120 2322 2524 2726 2928 2b2a 2d2c 2f2e 0000030 .... In C, I do: fd = open("testfile", O_RDWR | O_CREAT); for (i=0; i< CONTENT_SIZE; i++) { testBufOut[i] = i; } num_bytes_written = write(fd, testBufOut, CONTENT_SIZE); close (fd); this is what I wanted: #! /bin/bash i=0 while [ $i -lt 256 ]; do h=$

磁盘存储和文件系统(二)

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磁盘存储和文件系统(二) 使用分区空间磁盘分区分区 55AA 代表一个16进制数，55是2个十六进制数，一个十六进制数占4个二进制数，2个十六进制数占8个二进制数，就是一个字节，AA又是一个字节，所以就是2个字节。 MBR分区结构 MBR分区结构 MBR结构 MBR中DPT结构备份恢复分区表备份分区表 dd if=/dev/sda of=/data/dpt bs=1 count=66 skip=446 查看备份文件 od /data/dpt od -c /data/dpt od -a /data/dpt od -t c /data/dpt od -t x /data/dpt xxd /data/dpt hexdump -C /data/dpt 模拟分区表被破坏 dd if=/dev/zero of=/dev/sda bs=1 count=2 seek=510 fdisk -l /dev/sda //看不到磁盘上的分区 lsblk //看到的是内存中的分区注：分区表在内存中有一份，在磁盘上也有一份恢复分区表 dd if=/data/dpt of=/dev/sda bs=1 count=2 skip=64 seek=510 硬盘分区表的备份与还原备份分区表，将备份拷贝到另一台机器上 [root@Centos7 ~]# hostname -I 192.168.209.10

Whats Hex Dump - What does it mean?

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问题 thegladiator:~/cp$ cat new.txt Hello World This is a Trest Progyy thegladiator:~/cp$ hexdump new.txt 0000000 6548 6c6c 206f 6f57 6c72 2064 6854 7369 0000010 6920 2073 2061 7254 7365 2074 7250 676f 0000020 7979 000a 0000023 How is that text data represented in Hex like that ? What is the meaning of this ? Please can anyone tell me . 回答1: it's just what it says, a dump of the data in hexidecimal format: H 48 e 65 l 6c l 6c o 6f It is odd though that all of the bytes are swapped (65 48 : e H) If

How to find a specific byte in many bytes？

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问题 I readed a file using Java and use HexDump to output the data. It looks like this: The first and second line: one:31 30 30 31 30 30 30 31 31 30 30 31 30 31 31 31 two: 30 31 31 30 30 31 31 30 31 31 30 30 31 31 30 31 I want to print the data between first "31 30 30 31"and the second "31 30 30 31".My ideal ouput is 31 30 30 31 30 30 30 31 31 30 30 31 30 31 31 31 30 31. But the real output is wrong,I think my code can not find the 31 30 30 31 in the data1.How to figure it out? I Use jdk 1.7 and

Recursively search directory of binary files for hexadecimal sequence?

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问题 The current commands I'm using to search some hex values (say 0A 8b 02 ) involve: find . -type f -not -name "*.png" -exec xxd -p {} \; | grep "0a8b02" || xargs -0 -P 4 Is it possible to improve this given the following goals: search files recursively display the offset and filename exclude certain files with certain extensions (above example will not search .png files) speed: search needs to handle 200,000 files (around 50KB to 1MB) in a directly totaling ~2GB. I'm not too confident if the

I have data in hex dump but don't know the encoding. Eg. 0x91 0x05 = 657

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问题 I have some data in hexdump code. left hand are DEC and right hand are hexdump code. 16 = 10 51 = 33 164 = A4 01 388 = 84 03 570 = BA 04 657 = 91 05 1025 = 81 08 246172 = 9C 83 0F How to calculate any hexdump to DEC ? In perl, I tried to use ord() command but don't work. Update I don't known what it call. It look like 7bits data. I try to build formula in excel look like these: DEC = hex2dec(X) + (128^1 * hex2dec(Y-1)) + (128^2 * hex2dec(Z-1)) + ... 回答1: What you have is a variable-length

pythonic way to hex dump files

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问题 my question is simple: Is there any way to code in a pythonic way that bash command? hexdump -e '2/1 "%02x"' file.dat Obviously, without using os, popen, or any shortcut ;) EDIT: although I've not explicitly specified, it would be great if the code was functional in Python3.x Thanks! 回答1: If you only care about Python 2.x, line.encode('hex') will encode a chunk of binary data into hex. So: with open('file.dat', 'rb') as f: for chunk in iter(lambda: f.read(32), b''): print chunk.encode('hex')