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UnicodeEncodeError:'ascii'编解码器无法在位置20编码字符u'\\ xa0':序数不在范围内(128)

北慕城南 提交于 2020-04-07 15:04:16
问题: I'm having problems dealing with unicode characters from text fetched from different web pages (on different sites). 我在处理从不同网页(在不同站点上)获取的文本中的unicode字符时遇到问题。 I am using BeautifulSoup. 我正在使用BeautifulSoup。 The problem is that the error is not always reproducible; 问题是错误并非总是可重现的。 it sometimes works with some pages, and sometimes, it barfs by throwing a UnicodeEncodeError . 它有时可以在某些页面上使用,有时它会通过抛出 UnicodeEncodeError 来阻止。 I have tried just about everything I can think of, and yet I have not found anything that works consistently without throwing some kind of Unicode-related error.

获取实例的类名?

不想你离开。 提交于 2020-04-07 01:34:38
问题: How do I find out a name of class that created an instance of an object in Python if the function I am doing this from is the base class of which the class of the instance has been derived? 如果我从中执行此操作的函数是实例的类派生的基类,如何找出在Python中创建对象实例的类的名称? Was thinking maybe the inspect module might have helped me out here, but it doesn't seem to give me what I want. 想到也许 检查模块 可能在这里帮助了我,但它似乎没有给我我想要的东西。 And short of parsing the __class__ member, I'm not sure how to get at this information. 如果没有解析 __class__ 成员,我不知道如何获取这些信息。 解决方案: 参考一: https://stackoom.com/question/28vU/获取实例的类名 参考二: https://oldbug.net/q/28vU

夏令时和时区最佳实践

限于喜欢 提交于 2020-04-06 18:25:27
问题: I am hoping to make this question and the answers to it the definitive guide to dealing with daylight saving time, in particular for dealing with the actual change overs. 我希望使这个问题及其答案成为处理夏时制(尤其是处理实际变更)的权威指南。 If you have anything to add, please do 如果您要添加任何内容,请执行 Many systems are dependent on keeping accurate time, the problem is with changes to time due to daylight savings - moving the clock forward or backwards. 许多系统都依赖于保持准确的时间,问题在于夏时制导致的时间变化-向前或向后移动时钟。 For instance, one has business rules in an order taking system that depend on the time of the order - if the clock changes, the rules

055.Python前端Django模型ORM

只愿长相守 提交于 2020-04-06 09:14:56
由于前面在centos实验的过程中,pymql一直有属性错误,很难排查出问题,重新做了一个ubuntu的桌面系统同时使用pycharm开发工具作为学习开发工具,具体原因是因为在项目命名出现问题,和自己带的模块冲突,导致不能成功 一 ORM简介 对象关系映射(Object Relational Mapping,简称ORM)。 简单的说,ORM是通过使用描述对象和数据库之间映射的元数据,将程序中的对象自动持久化到关系数据库中。ORM在业务逻辑层和数据库层之间充当了桥梁的作用。 通过一张图来介绍一下数据库与python代码之间的一个关系: 1.1 ORM特点 ORM的优点 不用写繁琐的SQL语句,用咱们熟悉的python代码,就能实现对数据的操作,提高开发效率; 可以平滑的操作,切换数据库。 ORM的缺点 ORM代码转换为SQL语句时,需要花费一定的时间,执行效率会有所降低; 长期写ORM代码,导致写SQL语句能力,会有所减弱。  1.2 改进 如果想打印orm转换过程中的sql,需要在settings中进行如下配置: LOGGING = { 'version': 1 , 'disable_existing_loggers' : False, 'handlers' : { 'console' :{ 'level':'DEBUG' , 'class':'logging

树---把二叉树打印成多行

风流意气都作罢 提交于 2020-04-06 03:50:05
从上到下按层打印二叉树,同一层结点从左至右输出。每一层输出一行。 分析:首先先把根节点放入要打印的队列中,在打印之前把其子节点保存在队列中, 这里需要有一个list存放当前层的节点,有个计数器记还有多少节点要打印,下一层由多少节点。 /* function TreeNode(x) { this.val = x; this.left = null; this.right = null; } */ function Print(pRoot) { // write code here const queue=[],res= [] if (pRoot=== null ){ return res } queue.push(pRoot) let nextLevel =0 // 下一层节点的个数 let toBePrinted=1 // 这一层还有多少节点要打印 let list=[] // 存放每一层的节点 while (queue.length){ const pNode = queue.shift() list.push(pNode.val) if (pNode.left!== null ){ queue.push(pNode.left) nextLevel ++ } if (pNode.right!== null ){ queue.push(pNode.right) nextLevel

树---按之字形打印二叉树

拟墨画扇 提交于 2020-04-06 03:31:02
请实现一个函数按照之字形打印二叉树,即第一行按照从左到右的顺序打印,第二层按照从右至左的顺序打印,第三行按照从左到右的顺序打印,其他行以此类推。 分析: https://blog.csdn.net/qq_40608516/article/details/91128825 /* function TreeNode(x) { this.val = x; this.left = null; this.right = null; } */ function Print(pRoot) { // write code here const lists = [] if (pRoot=== null ){ return lists } const stack1 =[],stack2= [] let i =1 stack2.push(pRoot) while (stack1.length!==0||stack2.length!==0 ){ const list = [] // 为奇数层 if ((i % 2) === 1 ){ while (stack2.length!==0 ){ const temp =stack2[stack2.length-1 ] stack2.pop() list.push(temp.val) if (temp.left!== null )stack1.push(temp

a small thing that made me a little bit depressed

天涯浪子 提交于 2020-04-05 23:23:26
It was just two hours ago,specificly speaking It was 11:48 almost coming close to midneight. I was pratising singing songs in my renting room which is a sharing apartment . I realized that my voice was a little upper but I thought it didn't matter cause my neighbor had all gotten home for the vacation of Tomb Sweeping Day. at the monent when I was prepared to record my voice,there was a sharp knock at the door outside. I thought maybe It was my neighbor coming back. I opened the door however only saw a man blame me for making big noises. I apologized to him and promised him I would stop

购物券

落花浮王杯 提交于 2020-04-05 21:53:00
MobileShop class MobileShop { InnerPurchaseMoney purchaseMoney1; InnerPurchaseMoney purchaseMoney2; private int mobileAmount; MobileShop() { purchaseMoney1=new InnerPurchaseMoney(20000); purchaseMoney2=new InnerPurchaseMoney(10000); } void setMobileAmount(int m) { mobileAmount=m; } int getMobileAmount() { return mobileAmount; } class InnerPurchaseMoney { int moneyValue; InnerPurchaseMoney(int m) { moneyValue=m; } void buyMoblie() { if (moneyValue>=20000) { mobileAmount=mobileAmount-6; System.out.println("用价值"+moneyValue+"的内部购物券买了6部手机"); } else if(moneyValue<20000&&moneyValue>=10000) {

使用* args和** kwargs [重复]

你。 提交于 2020-04-05 20:53:18
问题: This question already has answers here : 这个问题已经在这里有了答案 : What does ** (double star/asterisk) and * (star/asterisk) do for parameters? **(双星号/星号)和*(星号/星号)对参数有什么作用? (19 answers) (19个回答) Closed 6 years ago . 6年前 关闭。 So I have difficulty with the concept of *args and **kwargs . 所以我很难理解 *args 和 **kwargs 的概念。 So far I have learned that: 到目前为止,我已经了解到: *args = list of arguments - as positional arguments *args =参数列表-作为位置参数 **kwargs = dictionary - whose keys become separate keyword arguments and the values become values of these arguments. **kwargs =字典-其键成为单独的关键字参数,而值则成为这些参数的值。 I don't understand

Tensorflow的gRPC编程(二)

不想你离开。 提交于 2020-04-05 20:41:05
gRPC编程()一)是一个简单预览,这一篇是官网的一个概念转载。 here gRPC 概念 本文档通过对于 gRPC 的架构和 RPC 生命周期的概览来介绍 gRPC 的主要概念。本文是在假设你已经读过文档部分的前提下展开的。针对具体语言细节请查看对应语言的快速开始、教程和参考文档(很快就会有完整的文档)。 概览 服务定义 正如其他 RPC 系统,gRPC 基于如下思想:定义一个服务, 指定其可以被远程调用的方法及其参数和返回类型。gRPC 默认使用 protocol buffers 作为接口定义语言,来描述服务接口和有效载荷消息结构。如果有需要的话,可以使用其他替代方案。 service HelloService { rpc SayHello (HelloRequest) returns (HelloResponse); } message HelloRequest { required string greeting = 1 ; } message HelloResponse { required string reply = 1 ; } gRPC 允许你定义四类服务方法: 单项 RPC,即客户端发送一个请求给服务端,从服务端获取一个应答,就像一次普通的函数调用。 rpc SayHello ( HelloRequest ) returns ( HelloResponse ) {