globals

问题 I was reading something about SuplerGlobals like $_SERVER or (see more detail PHP Manual Superglobals) the other day, now, I'm asking me: Is it possible to implement own SuperGlobals? Beside of Constants... So for example user A writes something in the Variable which, if User B is calling it can see. Something like a server wide Session Variable or something. Please don't be to hard, if its a silly question :) I know there are couple of ways outside, like SQL, Xml and Stuff, but maybe... 回答1:

问题 In flask every function has access to a request global. How do the designers of flask stop that global from being overwritten in the middle of one request when another one starts? 回答1: It's a threadlocal, not a true global. Since each thread can only be dealing with one request at a time, there's no danger of interference. In fact there's a full description of exactly this in the Flask docs here. (Still doesn't necessarily make it a good design, of course.) 来源： https://stackoverflow.com

问题 So this is going to be really hard to explain, I have an A folder and I have a B folder. I am using a common database for both of them. Both folder have following files, inside each of them => config.php, index.php, upload.php, control_admin.php, admin.php and view.php. There are some basic database, CSS and JS files which B shares with A(not of any problem). Now A is for project A and B is for project B. for each of the projects, I have URLs => a.example.com & b.example.com At a.example.com

问题 I was programming, and came across this problem: In the code sample below, a public function sets a private varriable. Now one would expect the content of that private varriable is private, thought the $GLOBALS varriable (a superglobal) can access it, and at least read it. why? is there a way to prefent this? <?PHP error_reporting( E_ALL ); class test { private $test = ''; public function test() { $this->test = 'Can u see me?'; } } $b = new test(); $b->test(); pre( $GLOBALS['b'] ); // Result:

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . I'm learning python, and am having a problem with global variables/lists. I'm writing a basic manual tower of hanoi program, here's the program currently: pilar1 = [5,4,3,2,1,0] pilar2 = [0,0,0,0,0,0] pilar3 = [0,0,0,0,0,0] def tower_of_hanoi(): global pillar1 global pillar2 global pillar3 print_info() def print

问题 I've got a file, constants.py , that contains a bunch of global constants. Is there a way I can grab all of them as dict, for just this file? 回答1: It should be simple: import constants print(constants.__dict__) 回答2: import constants constants_dict = {} for constant in dir(constants): constants_dict[constant] = getattr(constants, constant) I'm not sure I see the point of this though. How is writing constants_dict['MY_CONSTANT'] any better/easier/more readable than constants.MY_CONSTANT ? EDIT:

问题 This question was migrated from Software Engineering Stack Exchange because it can be answered on Stack Overflow. Migrated 5 years ago . We all know the dogma that global variables are bad. As I began to learn python I read parameters passed to functions are treated as local variables inside the funktion. This seems to be at least half of the truth: def f(i): print("Calling f(i)...") print("id(i): {}\n".format(id(i))) print("Inside f(): i += 1") i += 1 print("id(i): {}".format(id(i))) return

问题 Based on Disable global variable lookup in Python (and my own answer there), I have had problems when using a function with optional parameters such as in this minimal example: import types def noglobal(f): return types.FunctionType(f.__code__, {}) @noglobal def myFunction(x=0): pass myFunction() Essentially, it fails like this: Traceback (most recent call last): File "SetTagValue.py", line 10, in <module> myFunction() TypeError: myFunction() missing 1 required positional argument: 'x' Why is

问题 I know this is very evil, but is it possible to add an object to another module's globals, something like: #module dog.py import cat cat.globals.addVar('name','mittens') and #module cat.py print name #mittens 回答1: setattr(cat, 'name', 'mittens') or cat.name = 'mittens' 来源： https://stackoverflow.com/questions/2406586/adding-an-object-to-another-modules-globals-in-python

问题 I want to merge a dictionary , recieved from another module as a function argument to the globals dictionary of the current module. Any idea how this can be done ? module - test.py def setdict(indict): somedict = dict(globals(), **indict) what i want is, the resultant dictionary somedict is to be set as the globals dictionary of the current module (test) . somedict was created by merging globals() of the current module and the recieved dictionary indict. 回答1: globals() returns the current