gets

while(1) { printf("\nEnter message : "); gets(message); //Send some data if( send(sock , message , strlen(message) , 0) < 0) { puts("Send failed"); return 1; } //Receive a reply from the server if( recv(sock , server_reply , 2000 , 0) < 0) { puts("recv failed"); break; } puts("Server reply :"); puts(server_reply); } close(sock); return 0; } This is part of my program. When I compile and run it, I get an error. The error's message is warning: the gets function is dangerous and should not be used! Shreevardhan A simple google search would have given a lot of useful information like this answer.

If we want to use gets in c we will do something like: int main(void) { char str[100]; while (gets(str)) { printf("%s\n",str); } } We have to know the length of str first(which is 100) and then use gets. Is it possible using gets without knowing the length of the array in c? If you mean using gets safely, no, it's not possible. Advice : don't use gets , because without knowing the length first, it may cause buffer overflow. Use fgets instead, or use gets_s in C11. In fact, gets has been removed from stdio.h since C11. (In C99, it's deprecated) Short answer: No. Long answer: If you know that

I'm doing an exercise in C but I have a problem when at the and I want to repeat the cicle (do while), infact if I type 1 the programme starts again by the top, but it doesn't stop at the gets(testo); . I tried plenty of ways to solve the bug without a solution, can anyone help me? #include <stdlib.h> #include <stdio.h> #include <string.h> main(){ int cch, cw, i, j, w, ord, f; //counter and index char testo[80]; char alfa[50][25]; char swap[25]; do{ cch=0; cw=0; j=0; w=0; f=0; for(i=0;i<80;i++){ testo[i]='\0'; } printf("Write the text:\n"); gets(testo); //initialization 2d array for(i=0;i<50;i

#include <stdio.h> #include <stdlib.h> #include <string.h> #include <ctype.h> typedef struct record { char name[20]; char surname[20]; char telephone[20]; }Record; typedef struct node { Record data; struct node *next; }Node; Node *head = NULL; void addRecord(Record s) { Node *newNode; Node *n; newNode = (Node*)malloc(sizeof(Node)); newNode->data = s; newNode->next = NULL; if (head == NULL) { // The linked list is empty head = newNode; } else { // Traverse the whole list until we arrive at the last node n = head; while (n->next != NULL) { n = n->next; } n->next = newNode; } } Record

I have written a simple program in C. A program to input a String and display it along with the length. #include<stdio.h> int main() { char a[4]; printf("Enter the name : "); gets(a); printf("\nThe name enterd is : %s",a); printf("\nLength of string is : %d",strlen(a)); getch(); return 0; } The program do not contain warning or error. At run-time I entered the value " melwinsunny " as input. There was no error and the result displayed was : Enter the name : melwinsunny The name entered is : melwinsunny length of string is : 11 Why is it so? I have declared the character array of length 4 (

#include<stdio.h> #include<conio.h> main() { int i; char c, text[30]; float f; printf("\nEnter Integer : "); scanf("%d",&i); printf("\nEnter Character : "); c = getch(); printf("\nEnter String:"); gets(text); printf("\nEnter Float:"); scanf("%f",&f); printf("\nInteger : %d",i); printf("\nCharacter : %c8",c); printf("\nString : %s",text); printf("\nFloat : %f",f); getch(); } Why is this simple program not able to read a string using the gets() function? What else should I use to correct it? Well it it worked in Turbo C in my old 32-bit PC but not here... Scanf or other input parsing functions