geolocation

问题 I am trying to scrape user location with respect to user names from twitter. Input: The user list has more than 50K User names AkkiPritam,6.77E+17,12/15/2015,#chennaifloods AkkiPritam,6.77E+17,12/15/2015,#bhoomikatrust AkkiPritam,6.77E+17,12/15/2015,#akshaykumar gischethans,6.77E+17,12/15/2015,#chennaifloods mid_day,6.77E+17,12/15/2015,#bollywood mid_day,6.77E+17,12/15/2015,#chennaifloods Nanthivarman16,6.77E+17,12/15/2015,#admkfails Nanthivarman16,6.77E+17,12/15/2015,#jayafails

问题 I have a point expressed in lat/long Position louvreMuseum = new Position( 48.861622, 2.337474 ); and I have a radius value expressed in meters. I need to check if another point, also expressed in lat/long, is inside the circle. If I were on a flat surface I can simply use the formula (x - center_x)^2 + (y - center_y)^2 <= radius^2 as deeply explained in these SO answer. However as per the latitude/longitude usage I can not use that formula because of the spherical nature of the planet. How

问题 I have a point expressed in lat/long Position louvreMuseum = new Position( 48.861622, 2.337474 ); and I have a radius value expressed in meters. I need to check if another point, also expressed in lat/long, is inside the circle. If I were on a flat surface I can simply use the formula (x - center_x)^2 + (y - center_y)^2 <= radius^2 as deeply explained in these SO answer. However as per the latitude/longitude usage I can not use that formula because of the spherical nature of the planet. How

问题 I'm developing the iOS app and in one of the views I would like to include UIWebView with a page that contains a map (the address is: https://carsharing.mvg-mobil.de). The website requires location permission so as soon as the user is presented with this view, an alert appears: "https://carsharing.mvg-mobil.de/ would like to use your current location. OK/Don't allow". In my app I have the location of the user fetched from the CoreLocation framework. Is there a way to pass this location to

问题 I have an SQLite database, which does not support trig functions. I would like to sort a set of lat,lng pairs in my table by distance as compared to a second lat,lng pair. I'm familiar with the standard haversine distance formula for sorting lat,lng pairs by distance. In this case I don't care particularly for precision, my points are separated by large distances, so I don't mind rounding off the distances by treating curves as straight lines. My question, is there a generally accepted

问题 I have 2 coordinates. Coordinate 1 is a 'person'. Coordinate 2 is a destination. How do I move coordinate 1 100 meters closer to coordinate 2? This would be used in a cron job, so only php and mysql included. For example: Person is at: 51.26667, 3.45417 Destination is: 51.575001, 4.83889 How would i calculate the new coordinates for Person to be 100 meters closer? 回答1: Use Haversine to calculate the difference between the two points in metres; then adjust the value of the person coordinates

问题 I'm writing a booking web site in php and I would need a library or a remote service (similar to google maps api) that calculate the distance between 2 addresses. Ideally I prefer road distance but I don't care too much about what kind of distance is. Can you help me? Thank you very much, every help will be welcome. 回答1: Google Maps API - Directions is a good place to start. Sending off a request using the URL Pattern: http://maps.google.com/maps/api/directions/xml?origin=[FROM_ADDRESS]

问题 I m trying to make an android app which count the distance traveled from log,lan values with phonegap.But phonegap GPS work only when internet or wifi in ON condition.How can get log ,lan values without internet by using geolocation api.Thanks in advance . 回答1: See the PhoneGap API Docs for Geolocation under the geoLocationOptions: Android Quirks The Android 2.x simulators will not return a geolocation result unless the enableHighAccuracy option is set to true. { enableHighAccuracy: true }

问题 I am trying to write a PHP function that will calculate the center of gravity of a polygon. I've looked at the other similar questions but I can't seem to find a solution to this. My problem is that I need to be able to calculate the center of gravity for both regular and irregular polygons and even self intersecting polygons. Is that possible? I've also read that: http://paulbourke.net/geometry/polyarea/ But this is restricted to non self intersecting polygons. How can I do this? Can you

问题 I have looked at other questions that have been answered however, I am still unsure on how to; Get UK postcode data including Longitude, Latitude, Grid-N and Grid-E into my database If I use an API how do I go about it? Where do I start from? Would I need to use Pythagorus Theorem to calculate the distance between the two postcodes? I have got a table in my database for when a user adds a property. Maybe, there is a way when someone adds a property, it can add that postcode along with the