gawk

Is it possible to handle fields containing line breaks in awk?

岁酱吖の 提交于 2021-02-07 10:39:35
问题 Suppose I have a text file with records of the following form, where the FS is generally speaking a comma, and the RS is generally speaking a newline. However, the exception to this rule is that if a field is in quotes, it should treat the line breaks and commas as part of the field. "This field contains line breaks and is quoted but it should be treated as a single field",1,2,3,"another field" How can I use awk to parse such a file correctly, where I can still access $1,$2... , as I usually

Is it possible to handle fields containing line breaks in awk?

流过昼夜 提交于 2021-02-07 10:39:21
问题 Suppose I have a text file with records of the following form, where the FS is generally speaking a comma, and the RS is generally speaking a newline. However, the exception to this rule is that if a field is in quotes, it should treat the line breaks and commas as part of the field. "This field contains line breaks and is quoted but it should be treated as a single field",1,2,3,"another field" How can I use awk to parse such a file correctly, where I can still access $1,$2... , as I usually

awk sort multidimensional array [duplicate]

放肆的年华 提交于 2021-02-07 08:54:33
问题 This question already has an answer here : Appending an element to associative array awk (1 answer) Closed 4 years ago . GNU awk supports multidimensional arrays: q[1][1] = "dog" q[1][2] = 999 q[2][1] = "mouse" q[2][2] = 777 q[3][1] = "bird" q[3][2] = 888 I would like to sort the "second column" of q such that I am left with: q[1][1] = "mouse" q[1][2] = 777 q[2][1] = "bird" q[2][2] = 888 q[3][1] = "dog" q[3][2] = 999 as you can see the "first column" values moved to keep with the second. I

awk sort multidimensional array [duplicate]

痴心易碎 提交于 2021-02-07 08:54:15
问题 This question already has an answer here : Appending an element to associative array awk (1 answer) Closed 4 years ago . GNU awk supports multidimensional arrays: q[1][1] = "dog" q[1][2] = 999 q[2][1] = "mouse" q[2][2] = 777 q[3][1] = "bird" q[3][2] = 888 I would like to sort the "second column" of q such that I am left with: q[1][1] = "mouse" q[1][2] = 777 q[2][1] = "bird" q[2][2] = 888 q[3][1] = "dog" q[3][2] = 999 as you can see the "first column" values moved to keep with the second. I

normalize column data with maximum value of that column

隐身守侯 提交于 2021-02-07 07:58:22
问题 I have a data file with two columns. I want to find out the maximum data value from the second column and divide each entries of second column witht he maximum value. (So I will get all the entries in second column <= 1.00). I tried with this command below: awk 'BEGIN {max = 0} {if ($2>max) max=$2} {print ($2/max)}' angleOut.dat but I get error message as below. awk: (FILENAME=angleOut.dat FNR=1) fatal: division by zero attempted note: There are some data in the second column which is zero

normalize column data with maximum value of that column

非 Y 不嫁゛ 提交于 2021-02-07 07:57:50
问题 I have a data file with two columns. I want to find out the maximum data value from the second column and divide each entries of second column witht he maximum value. (So I will get all the entries in second column <= 1.00). I tried with this command below: awk 'BEGIN {max = 0} {if ($2>max) max=$2} {print ($2/max)}' angleOut.dat but I get error message as below. awk: (FILENAME=angleOut.dat FNR=1) fatal: division by zero attempted note: There are some data in the second column which is zero

normalize column data with maximum value of that column

*爱你&永不变心* 提交于 2021-02-07 07:57:19
问题 I have a data file with two columns. I want to find out the maximum data value from the second column and divide each entries of second column witht he maximum value. (So I will get all the entries in second column <= 1.00). I tried with this command below: awk 'BEGIN {max = 0} {if ($2>max) max=$2} {print ($2/max)}' angleOut.dat but I get error message as below. awk: (FILENAME=angleOut.dat FNR=1) fatal: division by zero attempted note: There are some data in the second column which is zero

normalize column data with maximum value of that column

寵の児 提交于 2021-02-07 07:57:07
问题 I have a data file with two columns. I want to find out the maximum data value from the second column and divide each entries of second column witht he maximum value. (So I will get all the entries in second column <= 1.00). I tried with this command below: awk 'BEGIN {max = 0} {if ($2>max) max=$2} {print ($2/max)}' angleOut.dat but I get error message as below. awk: (FILENAME=angleOut.dat FNR=1) fatal: division by zero attempted note: There are some data in the second column which is zero

How to check the type of an awk variable?

一世执手 提交于 2021-02-07 04:20:10
问题 The Beta release of gawk 4.2.0, available in http://www.skeeve.com/gawk/gawk-4.1.65.tar.gz is a major release, with many significant new features . I previously asked about What is the behaviour of FS = " " in GNU Awk 4.2?, and now I noticed the brand new typeof() function to deprecate isarray(): Changes from 4.1.4 to 4.2.0 The new typeof() function can be used to indicate if a variable or array element is an array, regexp, string or number. The isarray() function is deprecated in favor of

How to check the type of an awk variable?

陌路散爱 提交于 2021-02-07 04:18:48
问题 The Beta release of gawk 4.2.0, available in http://www.skeeve.com/gawk/gawk-4.1.65.tar.gz is a major release, with many significant new features . I previously asked about What is the behaviour of FS = " " in GNU Awk 4.2?, and now I noticed the brand new typeof() function to deprecate isarray(): Changes from 4.1.4 to 4.2.0 The new typeof() function can be used to indicate if a variable or array element is an array, regexp, string or number. The isarray() function is deprecated in favor of