function-pointers

Is there any way to print a pointer to a function in ANSI C? Of course this means you have to cast the function pointer to void pointer, but it appears that's not possible?? #include <stdio.h> int main() { int (*funcptr)() = main; printf("%p\n", (void* )funcptr); printf("%p\n", (void* )main); return 0; } $ gcc -ansi -pedantic -Wall test.c -o test test.c: In function 'main': test.c:6: warning: ISO C forbids conversion of function pointer to object pointer type test.c:7: warning: ISO C forbids conversion of function pointer to object pointer type $ ./test 0x400518 0x400518 It's "working", but

I'm trying to do some testing with member function pointer. What is wrong with this code? The bigCat.*pcat(); statement doesn't compile. class cat { public: void walk() { printf("cat is walking \n"); } }; int main(){ cat bigCat; void (cat::*pcat)(); pcat = &cat::walk; bigCat.*pcat(); } More parentheses are required: (bigCat.*pcat)(); ^ ^ The function call ( () ) has higher precedence than the pointer-to-member binding operator ( .* ). The unary operators have higher precedence than the binary operators. 来源： https://stackoverflow.com/questions/12189057/how-to-call-through-a-member-function

I am trying to run the following program but getting some strange errors: File 1.c: typedef unsigned long (*FN_GET_VAL)(void); FN_GET_VAL gfnPtr; void setCallback(const void *fnPointer) { gfnPtr = *((FN_GET_VAL*) (&fnPointer)); } File 2.c: extern FN_GET_VAL gfnPtr; unsigned long myfunc(void) { return 0; } main() { setCallback((void*)myfunc); gfnPtr(); /* Crashing as value was not properly assigned in setCallback function */ } Here the gfnPtr() is crashing on 64-Bit suse linux when compiled with gcc. But it successfully calling gfnPtr() VC6 and SunOS. But if I change the function as given below

How do I pass a function pointer from managed C++ (C++/CLI) to an unmanaged method? I read a few articles, like this one from MSDN , but it describes two different assemblies, while I want only one. Here is my code: 1) Header (MyInterop.ManagedCppLib.h): #pragma once using namespace System; namespace MyInterop { namespace ManagedCppLib { public ref class MyManagedClass { public: void DoSomething(); }; }} 2) CPP Code (MyInterop.ManagedCppLib.cpp) #include "stdafx.h" #include "MyInterop.ManagedCppLib.h" #pragma unmanaged void UnmanagedMethod(int a, int b, void (*sum)(const int)) { int result = a

Consider these two functions: void foo() {} void bar() {} is it guaranteed that &foo != &bar ? Similarly, template<class T> void foo() { } is it guaranteed that &foo<int> != &foo<double> ? There are two linkers I know of that fold function definitions together. MSVC aggressively COMDAT folds functions, so two functions with the same implementation can be turned into one function. As a side effect, the two functions share the same address. I was under the impression that this was illegal, but I cannot find where in the standard it is made illegal. The Gold linker also folds functions, with both