function-pointers

I have a function that takes a string, an array of strings, and an array of pointers, and looks for the string in the array of strings, and returns the corresponding pointer from the array of pointers. Since I use this for several different things, the pointer array is declared as an array of (void *), and the caller should know what kind of pointers are actually there (and hence what kind of a pointer it gets back as the return value). When I pass in an array of function pointers, however, I get a warning when I compile with -Wpedantic : clang: test.c:40:8: warning: assigning to 'voidfunc'

#include<stdio.h> #include<stdlib.h> int fun1() { printf("I am fun1."); return 0; } int fun2(int fun()) { fun(); return 0; } int main() { fun2(fun1); return 0; } The above program can run. As far as I am concerned, I can understand int fun2(int (*fun)()) , but I do not know how int fun2(int fun()) works. Thank you. Nawaz When you write int fun2(int fun()) , the parameter int fun() converts into int (*fun)() , it becomes exactly equivalent to this: int fun2(int (*fun)()); A more famiiar conversion happens in case of array when you declare it as function parameter. For example, if you've this:

class Child; class Parent { public: void (*funcPointer)(); void (*funcPointer2)(Parent* _this); void (Child::*funcPointer3)(); }; class Child: public Parent { public: void TestFunc(){ } void Do(){ Parent p; p.funcPointer=TestFunc; // error, '=': cannot convert from 'void (__thiscall Child::* )(void)' to 'void (__cdecl *)(void)' p.funcPointer2=TestFunc; // error too, '=': cannot convert from 'void (__thiscall Child::* )(void)' to 'void (__cdecl *)(Parent *)' p.funcPointer3=TestFunc; //this works p.funcPointer3=&Child::TestFunc; // this works too. p.funcPointer3(); // error, term does not

It looks like std::cout can't print member function's address, for example: #include <iostream> using std::cout; using std::endl; class TestClass { void MyFunc(void); public: void PrintMyFuncAddress(void); }; void TestClass::MyFunc(void) { return; } void TestClass::PrintMyFuncAddress(void) { printf("%p\n", &TestClass::MyFunc); cout << &TestClass::MyFunc << endl; } int main(void) { TestClass a; a.PrintMyFuncAddress(); return EXIT_SUCCESS; } the result is something like this: 003111DB 1 How can I print MyFunc 's address using std::cout ? I don't believe that there are any facilities provided by

I'm working on implementing a reflection mechanism in C++. All objects within my code are a subclass of Object(my own generic type) that contain a static member datum of type Class. class Class{ public: Class(const std::string &n, Object *(*c)()); protected: std::string name; // Name for subclass Object *(*create)(); // Pointer to creation function for subclass }; For any subclass of Object with a static Class member datum, I want to be able to initialize 'create' with a pointer to the constructor of that subclass. You cannot take the address of a constructor (C++98 Standard 12.1/12

In Go, is there any way to compare two non-nil function pointers to test for equality? My standard of equality is pointer equality. If not, is there any particular reason why pointer equality is not allowed? As of now, if I attempt to do this in the straight-forward way: package main import "fmt" func SomeFun() { } func main() { fmt.Println(SomeFun == SomeFun) } I get ./func-pointers.go:12: invalid operation: SomeFun == SomeFun (func can only be compared to nil) It is my understanding that this behavior was introduced recently. I've found an answer using the reflect package; however Atom