function-pointers

I'm trying to use a class function (interrupt service routine), void (ClassName::*fp)(void)=ClassName::FunctionName; and attaching it to an Arduino interrupt pin using the function with the following type inputs but that doesn't work. void attachInterrupt(int, void (*)(void),int); How can I make this happen? The interrupt service routine (ISR) needs to access privat object data, so I can't make a function outside of the class. My compiler error: ClassName.cpp : : In constructor 'ClassName::ClassName()': ClassName.cpp : *)()' ClassName.cpp : *)()' to 'void (*)()' for argument '2' to 'void

I want to implement some system in c++ so that I can call a function and ask for another function to be called in X milliseconds. Something like this: callfunctiontimed(25, funcName); 25 being the amount of milliseconds before the function should be called. I would like to know if multithreading is required for this and then use some delay function? Other than using function pointer how would a feature like this work? For a portable solution, you can use boost::asio. Below is a demo I wrote a while ago. You can change t.expires_from_now(boost::posix_time::seconds(1)); to suit you need say make

If you have a struct like this one struct A { void func(); }; and a reference like this one A& a; you can get a pointer to its func method like this: someMethod(&A::func); Now what if that method is virtual and you don't know what it is at run-time? Why can't you get a pointer like this? someMethod(&a.func); Is it possible to get a pointer to that method? Pointers to members take into account the virtuality of the functions they point at. For example: #include <iostream> struct Base { virtual void f() { std::cout << "Base::f()" << std::endl; } }; struct Derived:Base { virtual void f() { std:

I would like to make typedef for function pointer which has stl container as argument and this container has unknown type. Something like this: typedef void (* TouchCallBack)(GLRenderer*, const MotionEvent&, std::vector<T >); it's possible? (especially in c++ 03) I don't know of any C++03 solution exactly like that, and it's not built into the language, but in C++11, this is possible with using aliases: template<typename T> using TouchCallBack = void (*)(GLRenderer*, const MotionEvent&, std::vector<T >); One workaround for C++03 is using a struct: template<typename T> struct TouchCallBack {

As the function is set of instruction stored in one contiguous block of memory. And address of a function (entry point) is the address of the first instruction in the function. (from my knowledge) And thus we can say that the address of function and the address of the first instruction in the function will be the same (In this case the first instruction is the initialization of a variable.). But the program below contradicts the above line. code: #include<iostream> #include<stdio.h> #include<string.h> using namespace std; char ** fun() { static char * z = (char*)"Merry Christmas :)"; return &z

I've found C code that prints from 1 to 1000 without loops or conditionals : But I don't understand how it works. Can anyone go through the code and explain each line? #include <stdio.h> #include <stdlib.h> void main(int j) { printf("%d\n", j); (&main + (&exit - &main)*(j/1000))(j+1); } Don't ever write code like that. For j<1000 , j/1000 is zero (integer division). So: (&main + (&exit - &main)*(j/1000))(j+1); is equivalent to: (&main + (&exit - &main)*0)(j+1); Which is: (&main)(j+1); Which calls main with j+1 . If j == 1000 , then the same lines comes out as: (&main + (&exit - &main)*1)(j+1);

I have got a problem with calling a global function, which takes a pointer to a function as a parameter. Here is the declaration of the global function: int lmdif ( minpack_func_mn fcn, void *p, int m, int n, double *x, double *fvec, double ftol) The "minpack_func_mn" symbol is a typedef for a pointer to a function, defined as: typedef int (*minpack_func_mn)(void *p, int m, int n, const double *x, double *fvec, int iflag ); I want to call the "lmdif" function with a pointer to a function which is a member of a class I created, and here is the declaration of this class function: int LT