frequency

I am trying to prepare a frequency distribution table of a categorical variable in my data and I am using below code. But the output looks ok while I view it but not printing ok in report. # These lines are not needed because the data below is already # in that format # STI<-STI_IPD1%>% select(Q18_1,Q54) # STI$Q54<-as.factor(STI$Q54) STI = structure(list(Q18_1 = c(101L, 120L, 29L, 101L, 94L, 16L, 47L, 141L, 154L, 47L, 141L, 154L, 154L, 29L, 58L, 154L, 101L, 154L, 47L, 141L, 75L, 1L, 120L, 16L, 154L, 141L, 141L, 154L, 154L, 154L, 29L, 141L, 38L, 47L, 101L, 16L, 154L, 154L, 101L, 192L, 58L, 154L

In Excel 2010, I have a list of values in column A and a bin size is specified in B1 . This allows me to create histograms with N bins using this formula: {=FREQUENCY(A:A,(ROW(INDIRECT("1:"&CEILING((MAX(A:A)-MIN(A:A))/B1,1)))-1)*B1+MIN(A:A))} The only problem is that I need to select N cells and apply this formula to get N bins to be used as data source for my bar chart. Is it possible to skip this step? E.g. Is it possible to use this formula in a single cell - somewhat modified - so that when used as data source, it is interpreted as N cells, producing a nice histogram with N values? Thanks.

Maybe this is a stupid question, but I have a problem with extracting the ten most frequent words out of a corpus with Python. This is what I've got so far. (btw, I work with NLTK for reading a corpus with two subcategories with each 10 .txt files) import re import string from nltk.corpus import stopwords stoplist = stopwords.words('dutch') from collections import defaultdict from operator import itemgetter def toptenwords(mycorpus): words = mycorpus.words() no_capitals = set([word.lower() for word in words]) filtered = [word for word in no_capitals if word not in stoplist] no_punct = [s

I want to calculate the frequency of occurrence of each letter in all columns: for example I have this three sequences : seq1=AATC seq2=GCCT seq3=ATCA here, we have: in the first column frequency of 'A' is 2 , 'G' is 1 . for the second column : the frequency of 'A' is 1, 'C' is 1 and 'T' is 1. (the same thing in the rest of column) first, I try to do the code of calculating frequency I try this: for example: s='AATC' dic={} for x in s: dic[x]=s.count(x) this gives: {'A':2,'T':1,'C':1} now, I want to apply this on columns.for that I use this instruction: f=list(zip(seq1,seq2,seq3)) gives: [('A'

The goal is to produce a frequency table of all my selected variables (about reading habits for 4 Newspapers) which in essence have the same possible values: 1= Subscribed 2= Every week 3= Sometimes 4= Never 0= NA (No Answers) The problem arises if one of the variables does not contain one of the possible value. For example, if no one is subscribed to that particular Newspaper. a <- c(1,2,3,4,3,1,2,3,4,3) b <- c(2,2,3,4,3,0,0,3,4,1) d <- c(2,2,3,4,3,0,0,0,0,0) e <- c(3,3,3,3,3,3,3,3,3,3) ta <- table(a) tb <- table(b) td <- table(d) te <- table(e) abde <- cbind(ta,tb,td,te) ta tb td te 0 2 2 5

I've checked similar questions but it didnt help in my precise question. So, my table goes like this: id age 1 30 2 36 3 30 4 52 5 52 6 30 7 36 etc.. I need to count the frequency of ages: age freq 30 2 36 3 52 2 How can I grab this freq? After this I will need to work with that data, so it might be necessary using array? Thanks! function drawChart() { // Create the data table. var data = new google.visualization.DataTable(); data.addColumn('string', 'age'); data.addColumn('number', 'freq'); <?php while($row = mysql_fetch_row($result)) { $frequencies[$row[0]] = $frequencies[1]; echo "data

I have a data frame, which looks something like this: CASENO Var1 Var2 Resp1 Resp2 1 1 0 1 1 2 0 0 0 0 3 1 1 1 1 4 1 1 0 1 5 1 0 1 0 There are over 400 variables in the dataset. This is just an example. I need to create a simple frequency matrix in R (excluding the case numbers), but the table function doesn't work. Specifically, I'm looking to cross-tabulate a portion of the columns to create a two-mode matrix of frequencies. The table should look like this: Var1 Var2 Resp1 3 1 Resp2 3 2 In Stata, the command is: gen var = 1 if Var1==1 replace var= 2 if Var2==1 gen resp = 1 if Resp1==1